MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants

MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants

Reproduction in Plants Intex Questions

Question 1.
Boojho wants to know if there is any advantage of vegetative propagation?
Answer:
Plants produced by vegetative propagation take less time to grow and bear flowers and fruits earlier than those produced from seeds. The new plants are exact copies of the parent plant, as they are produced from a single parent.

Question 2.
Boojho wants to know how the male gamete in the pollen grain reaches the female gamete present in the ovule?
Answer:
The ovary contains one or more ovules.

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Question 3.
Boojho wants to know why flowers are generally so colorful and fragrant. Is it to attract insects?
Answer:
Yes.

Activities

Activity – 1
Take a fresh potato. Observe the scars on it with the help of a magnifying glass. You may find buds in them. These scars are also called “eyes”. Cut a few pieces of a potato, each with an eye and bury them in the soil. Water the pieces regularly for a few days and observe their progress?
Answer:
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 1
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 2

Reproduction in Plants Text Book Exercises

Question 1.
Fill in the blanks:

  1. Production of new individuals from the vegetative part of parent is called ……………………….
  2. A flower may have either male or female reproductive parts Such a flower is called …………………….
  3. The transfer of pollen grains from the another to the stigma of the same or of another flower of the same kind is known as ………………………….
  4. The fusion of male and female gametes is termed as ………………………
  5. Seed dispersal takes place by means of …………………………. , ……………………… and …………………………….

Answer:

  1. Vegetative propagation
  2. unisexual flowers
  3. pollination
  4. fertilisation
  5. wind, insects, water.

Question 2.
Describe the different methods of asexual reproduction. Give examples?
Answer:
The various methods of asexual reproduction are:

  1. Vegetative propagation, for example stem cutting of rose or champa.
  2. Budding, for example reproduction in yeast by budding.
  3. Fragmentation, for example fragmentation in spirogyra.
  4. Spore formation, for example reproduction in fern.

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Question 3.
Explain what you understand by sexual reproduction?
Answer:
In this type of reproduction male gamete (sperm) combines tie female gamete (ovum) in animals to form zygote.

Question 4.
State the main difference between asexual and sexual reproduction?
Sexual Reproduction:

  1. It occurs both in lower and the higher organisms but mostly in higher plants and animals.
  2. In it, there is fusion of the two (male and female) gametes and for this the sexes are required.
  3. The new individual formed is identical to the parent.

Asexual Reproduction:

  1. Usually occurs in lower organisms.
  2. Only one parent is sufficient in asexual reproduction.
  3. The new individual formed is similar but not identical to the parents.

Question 5.
Sketch the reproductive parts of a flower?
Answer:
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 3
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 4

Question 6.
Explain the difference between self – pollination and cross – pollination?
Answer:
self – pollination:
The transfer of pollen from the another to the stigma of a flower is called pollination.
If the pollen lands on the stigma of the same flower it is called self – pollination.

cross – pollination:
When the pollen of a flower lands on the stigma of another flower of the same plant, or that of a different plant of the same kind, it is called cross – pollination.

MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 5 and 6

Question 7.
How does the process of fertilisation take place in flowers?
Answer:
Fertilization is the process in which male and female gametes fuse together. In flowering plants the pollen fuses with ovules present in the overy to form a zygote, which later on develops into seed.
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 7 and 8

Question 8.
Describe the various ways by which seeds are dispersed?
Answer:
In nature same kind of plants grow at different places. This happens because seeds are dispersed to different places. Sometimes after a walk through a forest or a field or a park, we may have found seeds or fruits sticking to our clothes. Seeds and fruits of plants are carried away by wind, water and animals.

Winged seeds such as those of drumstick and maple [Fig.(a) and (b)], light seeds of grasses or hairy seeds of aak (Madar) and hairy fruit of sunflower [Fig. (a), (b)], get blown off with the wind to far away places. Some seeds are dispersed by water. These fruits or seeds usually develop floating ability in the form of spongy or fibrous outer coat as in coconut. Some seeds are dispersed by animals, especially spiny seeds with hooks which get attached to the bodies of animals and are carried to distant places. Examples are Xanthium and Urena.
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 8
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 9
Some seeds are dispersed when the fruits burst with sudden jerks. The seeds are scattered far from the parent plant. This happens in the case of castor and balsam.
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 10

Question 9.
Match items in Column I with those in Column II
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 11
Answer:

(a) – (iii)
(b) – (v)
(c) – (ii)
(d) – (i)
(e) – (iv).

Question 10.
Tick the correct answer:

Question (a)
The reproductive part of a plant is the?
(i) leaf
(ii) stem
(iii) root
(iv) flower.
Answer:
(iii) root

Question (b)
The process of fusion of the male and the female gametes is called?
(i) fertilisation
(ii) pollination
(iii) reproduction
(iv) seed formation.
Answer:
(i) fertilisation

Question (c)
Mature ovary forms the?
(i) seed
(ii) pistil
(iii) stamen
(iv) fruit.
Answer:
(iv) fruit.

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Question (d)
A spore producing plant is?
(i) rose
(ii) bread mould
(iii) potato
(iv) ginger.
Answer:
(iii) potato

Question (e)
Bryophyllum can reproduce by its?
(i) stem
(ii) leaves
(iii) roots
(iv) flower.
Answer:
(ii) leaves

Extended Learning – Activities and Projects

Question 1.
Make your own cactus garden by collecting pieces cut from different kinds of cacti. Grow the variety in one single flat container or in separate pots?
Answer:
Do yourself.

Question 2.
Visit a fruit market and collect as many local fruits as possible. If many fruits are not available, you can collect tomatoes and cucumbers (these are fruits, though we use them as vegetables). Make drawings of the different fruits. Split the fruits and examine the seeds within. Look for any special characteristics in the fruits and their seeds?
Answer:
Do yourself.

Question 3.
Think of ten different fruit – bearing plants. Remember that many vegetables are also fruits of the plants. Discuss with your teacher, parents, farmers, fruit growers and agricultural experts (if available nearby) and find out the manner of their dispersal. Present your data in the form of a table as shown below:
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 12
Answer:
Do yourself

Question 4.
Suppose there is one member of a particular kind of organism in a culture dish, which doubles itself in one hour through asexual reproduction. Work out the number of members of that kind of organism which will be present in the culture dish after ten hours. Such a colony of individuals arising from one parent is called a “clone”?
Answer:
Do yourself.

Reproduction in Plants Additional Important Questions

Objective Type Questions

Question 1.
Choose the correct alternative:

Question (a)
………………………… is formed in female reproductive part of plant.
(a) pollen grain
(b) pollination
(c) female gamete
(d) stigma.
Answer:
(d) stigma.

Question (b)
The process of reaching pollen grains to stigma is called as …………………….
(a) pollination
(b) budding
(c) fission
(d) fertilisation.
Answer:
(a) pollination

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Question (c)
In plants, male and female reproductive organs are found in ………………………….
(a) leaves
(b) flowers
(c) roots
(d) stem.
Answer:
(b) flowers

Question (d)
Those living beings who have male and female reproductive organs differently are called ………………………….
(a) asexual
(b) bisexual
(c) unisexual
(d) None of these.
Answer:
(c) unisexual

Question (e)
Zygote is formed:
(a) by fusion of two male gamete
(b) by fusion of two female gametes
(c) by fusion of male and female gametes
(d) by all the above methods.
Answer:
(c) by fusion of male and female gametes

Question (f)
Which one of the following organisms shows budding?
(a) Hydra
(b) Spirogyra
(c) Amoeba
(d) Paramecium.
Answer:
(a) Hydra

Question 2.
Fill in the blanks:

  1. ……………………. are parts of flower.
  2. Once the pollen grains reach stigma, they form …………………………..
  3. ……………………… are formed in pollen grains.
  4. The long thread like structure of carpel is called as ………………………
  5. The grain like structure in ovary is called as …………………………
  6. ………………………….. is formed in ovule.
  7. Formation of a new plant from the stem of sugarcane is known as ………………………..
  8. The fusion of sperm and egg is known as ………………………..
  9. We can count the age of a tree through its ……………………….
  10. The cells involved in sexual reproduction are called ………………………….
  11. Fusion of gametes gives rise to a single cells called ……………………….
  12. The process of fusion of gametes is called ………………………….. in animals and plants.
  13. Animals having both reproductive organs are called ………………………….

Answer:

  1. Stamen and carpel
  2. Male gametes
  3. Male gametes
  4. Ovules
  5. Female gametes
  6. Zygote
  7. Vegetative reproduction
  8. Fertilisation
  9. Annual rings
  10. Gametes
  11. Zygote
  12. Fertilisation
  13. Hermaphrodite.

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Question 3.
Which of the following statements are true (T) or false (F):

  1. The process of development in human and butterfly are the same because they both start from a zygote.
  2. The most common type of reproduction in amoeba and paramecium is budding.
  3. The common method of reproduction in yeast is budding.
  4. Asexual reproduction is more common than the sexual reproduction.
  5. Reproduction by spores is a method of asexual reproduction.
  6. Cutting and grafting are natural means of reproduction.
  7. A fertilized egg becomes a seed.
  8. Plants can have indefinite growth but animals do not.
  9. Insect pollinated flowers are brightly coloured.
  10. Flowers which possess stamens and carpel are called unisexual.
  11. Wind pollinated flowers produce pollen grains in large quantity.

Answer:

  1. False
  2. False
  3. True
  4. True
  5. True
  6. False
  7. True
  8. True
  9. True
  10. False
  11. True

Question 4.
Match the items in Column A with Column B:
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 13
Answer:

(i) – (d)
(ii) – (c)
(iii) – (a)
(iv) – (b).

Reproduction in Plants Very short Answer type Questions

Question 1.
Name two organisms which reproduce by two types of asexual methods. What are the methods?
Answer:
Amoeba reproduces by binary fission. Hydra reproduces by budding.

Question 2.
What is meant by reproduction?
Answer:
It is a process by which an organism gives birth to produce its own kind to maintain its species.

Question 3.
What are the two methods of reproduction in plants and animals?
Answer:
The two methods of reproduction in plants and animals are:

  1. Asexual reproduction.
  2. Sexual reproduction.

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Question 4.
What is pollination?
Answer:
It is the process of transference of pollen grains from the stamens to the stigma of the carpel of flower.

Question 5.
What do you call for the male reproductive organ of flower?
Answer:
The male reproductive organ of a flower is called ‘stamen’.

Question 6.
What do you call for the female reproductive organ of the flower?
Answer:
The female reproductive organ of the flower is called a “carpel”.

Question 7.
What is growth?
Answer:
The process in which the change in size and shape of the organism along with the increase in weight is called growth.

Question 8.
What kind of development takes place in dog and cat?
Answer:
The development in dog and cat takes place inside the body of female. The female gives birth to young ones after a definite period. This type of development is called internal development.

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Question 9.
What is the difference between sperm and ovum?
Answer:
Sperm is a male gamete while ovum is a female gamete. Sperm is mobile while ovum is non-mobile, the movement of sperm is attributed to mitochondria present in sperm.

Question 10.
In which part of the flower is the ovule found?
Answer:
In the ovary part of carpel of the flower the ovule is found.

Question 11.
Where does fertilisation occur in a flowering plant?
Answer:
In flowering plants, the fertilisation occurs in the ovary of the carpel of the flower.

Question 12.
How many types of gametes are there?
Answer:
Gametes are the fundamental units of reproduction. They are of two types :

  1. Male gametes or sperms
  2. Female gametes or ovum.

Question 13.
What is fertilisation process?
Answer:
The fusion of male and female gametes to form a zygote during sexual reproduction is called fertilisation.

Reproduction in Plants short Answer type Questions

Question 1.
How do insects help in cross – pollination?
Answer:
Insects get attracted towards flowers either due to their bright color or fragrance or nectar. In the process of collecting nectar from flowers some of the pollens get stuck to their legs and body. If such an insect visits another flower, he transfers pollens to this flower and thus completes the process of cross-pollination.

Question 2.
What are the organs in human which produce the gametes?
Answer:
In humans the parents are separate as mother and father. Mother (female) possesses the ovary and the father (male) possesses the testes. The ovary produces the ovum (female sex cell) and the testes produces the sperm.

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Question 3.
What is budding?
Answer:
Budding is a type of a sexual reproduction in which an individual is produced as an out growth called bud from the parent organism. It takes place in certain animals like Hydra and in non green plant cells of yeast.

Question 4.
How do plants developed from a seed?
Answer:
The embryo inside the seed has two distinct parts. One part produces root system, and the other shoot system under favourable conditions of water, air, light and temperature. The root system developed under the soil and shoot system above the soil. Due to cell division elongation of different parts takes place and a new plant is obtained.

Question 5.
Give some examples of growth in plants and animals?
Answer:
Examples of growth in plants:

  1. A small seedling gets developed into a fully developed tree.
  2. Growth of plant in length.
  3. Growth of stem in thickness.

Examples of growth in animals:

  1. An egg is developed into an organism by the division of cells.
  2. A small child grows into a fully developed adult.
  3. A wound is healed up by the division of cells in the surrounding region.

Question 6.
Explain with examples “fission”?
Answer:
When the body of an individual after a certain period of growth divides mitotically into two or more parts, it is known as fission reproduction. When a fission results in the formation of two daughters, it is known as binary fission. When fission results in the formation of two daughters, it is known as multiple fission.

Question 7.
How does reproduction take place in fungs by budding?
Answer:
A bulb like structure formed on body is known as bud. As the reproduction takes place through this bud, it is called as budding. Such types of buds are formed on the bodies of organisms like hydra, yeast etc. This bud increases gradually and detaches itself from parent body and develops in the form of new organism. In corel and sponge also reproduction takes place by budding.

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Question 8.
What is called as vegetative reproduction?
Answer:
The new plant develops when branches of these plants are burried in soil during rainy season. The new saplings are produced from various parts such as root, stem, leaf of plants. This type of propagation or reproduction in plants is called as vegetative propagation.

Question 9.
What is difference between fertilisation and pollination?
Answer:
Pollination is the transference of male gametes (pollen grain) from pollen sac to stigma and the fertilisation is fusion of male gamete (pollen grain) and female gamete (egg cell) in the ovary of a flower. Fertilisation is followed by the formation of embryo. Embryo is enclosed within the seed.

Question 10.
What are the advantages of vegetative reproduction?
Answer:
Advantages of vegetative reproduction:

  1. It helps in rapid propagation of plant species in some region. Examples: bamboo, sugarcane, potato crop etc.
  2. Those plants, whose seeds are not capable of germination, can be reproduced by vegetative reproduction e.g. garlic,
  3. There is 100 percent possibility of survival of plants by this method.
  4. The species having high qualities can be conserved.
  5. The plants reproduced by this method get the fruits earlier.

Reproduction in Plants Long Answer type Questions

Question 1.
What are the different ways in which reproduction in plants can take place?
Ans. Reproduction in plants can be classified in three main groups:

  1. Sexual reproduction,
  2. Asexual reproduction, and
  3. Vegetative reproduction.

In asexual reproduction, the new individuals are reproduced from a single parent. Here one cell undergoes division into two new individuals. In sexual reproduction, two parents are needed to produce one new individual. In vegetative propagation, a few cells of plant body propagate to form a new plant.

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Question 2.
Write the various steps involved in the formation of a plant seed, starting from pollination?
Answer:
There are following steps involved from pollination to the formation of the seed:

1. Fertilisation:
The process of fusion of male and female gamete in sexual reproduction is called fertilisation.

2. Pollination:
The male part of plant is stamen. It consists of the filament and the anther. The anther has pollen grains.The female part is made up of stigma, style and ovary. The ovary has ovule. The stigma receives of pollen grains. The process of transfer of pollen from anther to stigma is known as pollination.

3. Seed formation:
The whole ovary after fertilisation is converted into the fruit while the ovule is converted into the seed.

Question 3.
What is meant by the terms external fertilisation and internal fertilisation?
Answer:
Internal fertilisation:
The reproductive process remains incomplete till the male and female gamete do not fuse with each other. In some animals the process of fertilisation occurs inside the female body. This is called internal fertilization. After that female either lay eggs or given birth to young one. For example, dog, cat, bird, human etc.

External fertilisation:
In some animals the female release ovum or egg outside and the male drops sperms on these. This type of fertilization is called external fertilization. The zygote so formal undergoes regular and specific changes with rime to form a new individual.

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Question 4.
What are the reproductive organs in a flower? How does pollination take place? What is a seed?
Answer:
The reproductive organs of a plant develop on a special reproductive appendage called flower. The male reproductive, organs are stamen. The stamens bear anthers where pollen grains (the male gametes) are produced. The female reproductive organ is pistil. It consists of stigma, style and ovary. Inside the ovary (the female – gametes) are developed.

Pollination is the transfer of pollen grains from another to stigma of either the same flower (self pollination) or of another flower (cross pollination). The pollen grains are carried to the stigma by air, insects water in aquatic plants or by animals. Seed is the structure formed by the fusion of ovule and pollen grains in the ovary. The seeds germinate after their dispersion, into new plants.

Question 5.
Explain reproduction by spore formation in fungus with neat diagram?
Answer:
Spore formation:
You might have seen white powder like substance on leather objects during rainy season. These small particles are spores of fungus. Small spherical structures are in yeast, fungus, moss, fern and microbes during unfavourable circumstances. They have protective layer around them and remain floating in air. During favourable conditions, the protective layer breaks open and new organism is formed.
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 14.

Question 6.
What are spores? When do they form?
Answer:
Several plants produce spores which germinate to produce new individual plants e.g., rhizopus, mucus and moss etc. It is the mechanism to overcome the unfavourable conditions.
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 15

Question 7.
Draw a neat diagram to show reproduction through spore formation in fern?
Answer:
MP Board Class 7th Science Solutions Chapter 12 Reproduction in Plants img 16

MP Board Class 7th Science Solutions

MP Board Class 9th Science Solutions Chapter 7 Diversity in Living Organisms

MP Board Class 9th Science Solutions Chapter 7 Diversity in Living Organisms

Diversity in Living Organisms Intext Questions

Diversity in Living Organisms Intext Questions Page No. 80

Question 1.
Why do we classify organisms?
Answer:
Classification of organism make it easy to study the millions of organisms on this earth. Similarities among them is the basis to classify them into different classes. Classification makes study easier.

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Question 2.
Give three examples of the range of variations that you see in life – forms around you.
Answer:
Variations observed in life are:

  1. Size: Organisms vary greatly in size – from microscopic bacteria to elephants, whales and large trees.
  2. Appearance: The colour of various animals is quite different. Number of pigments are found in plants. Their body – built also varies.
  3. Life time: The life span of different organisms is varied.

Diversity in Living Organisms Intext Questions Page No. 82

Question 1.
Which do you think is a more basic characteristic for classifying organisms?
(a) the place where they live.
(b) the kind of cells they are made of. Why?
Answer:
(a) Different organisms may share same habitat but may have entirely different form and structure. So, the place where they live cannot be a basis of classification.

(b) The kind of cells they are. made of. Because placement of organism to other destination can create a easy confusion.

Question 2.
What is the primary characteristic on which the first division of organisms is made?
Answer:
The primary characteristic on which the first division of organisms is made is the nature of the cell – prokaryotic or eukaryotic cell.

Question 3.
On what basis are plants and animals put into different categories?
Answer:
Plants and animals are very different from each other but main basis to differentiate is “Mode of nutrition’’. Plants are autotrophs. They can make their food own while animals are heterotrophs which are dependent on others for food. Locomotion, absence of chloroplasts etc. also make them different.

Diversity in Living Organisms Intext Questions Page No. 83

Question 1.
Which organisms are called primitive and how are they different from the so-called advanced organisms?
Answer:
A primitive organism is the one which has a simple body structure and ancient body design or features that have not changed much over a period of time. As per the body design, the primitive organisms which have simple structures are different from those so – called advanced organisms which have complex body structure and organization.

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Question 2.
Will advanced organisms be the same as complex organisms? Why?
Answer:
Yes, they are developed from same ancestor once. They have relatively acquired their complexity recently. There is a possibility that these advanced or ‘younger’ organisms acquire more complex structures during evolutionary time to compete and survive in the changing environment.

Diversity in Living Organisms Intext Questions Page No. 85

Question 1.
What is the criterion for classification of organisms as belonging to kingdom Monera or Protista?
Answer:
The organisms belonging to kingdom Monera are unicellular and prokaryotic whereas the organisms belonging to Kingdom Protista are unicellular and eukaryotic. This is the main criterion of their classification.

Question 2.
In which kingdom will you place an organism which is single – celled, eukaryotic and photosynthetic?
Answer:
Kingdom Protista.

Question 3.
In the hierarchy of classification, which grouping will have the smallest number of organisms with a maximum of characteristics in common and which will have the largest number of organisms?
Answer:
In the hierarchy of classification, “species” will have the smallest number of organisms with a maximum of characteristics in common whereas “the kingdom” will have the largest number of organisms a Arthropoda.

Diversity in Living Organisms Intext Questions Page No. 88

Question 1.
Which division among plants has the simplest organisms?
Answer:
Division thallophyta.

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Question 2.
How are pteridophytes different from the phanerogams?
Answer:
1. Pteridophyta: They have inconspicuous or less differentiated reproductive organs. They produce naked embryos called spores.
Examples:

  • Ferns
  • marsilea
  • equisetum, etc.

2. Phanerogams: They have well developed reproductive organs. They produce seeds.
Example:

  • Pinus
  • cycas
  • fir etc.

Question 3.
How do gymnosperms and angiosperms differ from each other?
Answer:
Gymnosperm:

  1. They are non – flowering plants.
  2. Naked seeds not enclosed inside fruits are produced.
  3. Examples:
    • Pinus
    • Cedar
    • Fir
    • Cycas etc.

Angiosperm:

  1. They are flowering plants.
  2. Seeds are enclosed inside fruits.
  3. Examples:
    • Coconut
    • Palm
    • Mango etc.

Diversity in Living Organisms Intext Questions Page No. 94

Question 1.
How do poriferan animals differ from coelenterate animals?
Answer:

PoriferanCoelenterate
1. Mostly marine, non – motile.1. Motile marine animals that either live in colonies or have a solitary life – span.
2. Cellular level of organisation.2. Tissue level of organisation.
3. Spongilla, Euplectella etc.3. Hydra, sea anemone.

Question 2.
How do annelid animals differ from arthropods?
Answer:

AnnelidsArthropods
1. Closed circulatory system1. An open circulatory system
2. The body is divided into several identical segments2. The body is divided into few specialized segments

Question 3.
What are the differences between amphibians and reptiles?
Answer:

AmphibianReptiles
1. They live at land and water both.1. They are completely terrestrial.
2. Scales are absent.2. Skin is covered with scales.
3. They lay eggs in water.3. They lay eggs on land.
4. Example: frogs, toads and salamanders.4. Example: lizards, snakes, turtles, chameleons etc.

Question 4.
What are the differences between animals belonging to the Aves group and those in the mammalia group?
Answer:
Most birds have feathers and they possess a beak.Mammals do not have feathers and the beak is also absent. Birds lay eggs. Hence, they are oviparous. Some mammals lay eggs and some give birth to young ones. Hence, they are both oviparous and viviparous.

Diversity in Living Organisms NCERT Textbook Exercises

Question 1.
What are the advantages of classifying organisms?
Answer:
Advantages of classification:

  1. Better categorization of living beings based on common characters.
  2. Easier study for scientific research.
  3. Better understanding of human’s relation and dependency on other organisms.
  4. Helps in cross breeding and genetic engineering for commercial purposes.

Question 2.
How would you choose between two characteristics to be used for developing a hierarchy in classification?
Answer:
Gross character will form the basis of start of the hierarchy and fine character will form the basis of further steps of single hierarchy.
Examples:

  • Presence of vertebral column in human beings can be taken under vertebrata.
  • Presence of four limbs makes them members of Tetrapoda.
  • Presence of mammary glands keeps them under mammalia.

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Question 3.
Explain the basis for grouping organisms into five kingdoms.
Answer:
Basis of classification:

  1. Number of cells: unicellular or multicellular.
  2. Complexity of cell structure: Prokaryote and Eukaryote.
  3. Presence or absence of cell wall.
  4. Mode of nutrition.
  5. Level of organization.

Question 4.
What are the major divisions in the Plantae? What is the basis for these divisions?
Answer:
Major divisions of Kingdom Plantae:

DivisionBasis for classification
1. Thallophyta or Algae1. Thallus like body, plant body is not differentiated into roots, stems etc.
2. Bryophyta2. Body is divided into leaf and stem, lack vascular tissue.
3. Pteridophyta3. Body is divided into root, stem and leaf, lack seeds.
4. Gymnosperm4. Seed bearing, naked seeds, lack flowers.
5. Angiosperm5. Seed bearing covered seeds, produce flowers.

Question 5.
How are the criteria for deciding divisions in plants different from the criteria for deciding the subgroups among animals?
Answer:
In plants, basic structure of their body is a major criteria based on which thallophytes are different from bryophytes. Apart from this, absence or presence of seeds is another important criteria. Gymnosperms and angiosperms are further segregated based on if seeds are covered or not. It is clear that it is the morphological character which makes the basis for classification of plants.

In animal, classification is based on more minute structural variations. So in place of morphology, cytology forms the basis. Animals are classified based on layers of cells, presence or absence of coelom. Further, higher hierarchy animals are classified based on the presence or absence of smaller features, like presence or absence of four legs.

Question 6.
Explain how animals in Vertebrata are classified into further subgroups.
Answer:
Vertebrata is divided into two super classes, viz. Pisces and Tetrapoda. Animals of pisces have streamlined body with fins and tails to assist in swimming. Animals of tetrapoda have four limbs for locomotion.
Tetrapoda is further classified into following classes:

  1. Amphibia: Amphibians are adapted to live in water and on land. They can breathe oxygen through kin when under water.
  2. Reptilia: These are crawling animals. Skin is hard to withstand extreme temperatures.
  3. Aves: Forelimbs are modified into wings to assist in flying. Beaks are present. Body is covered with feathers.
  4. Mammalia: Mammary glands are present to nurture young ones. Skin is covered with hair. Most of the animals are viviparous.

Diversity in Living Organisms Additional Questions

Diversity in Living Organisms Tissues Multiple Choice Questions

Question 1.
Find out incorrect sentence.
(a) Protista includes unicellular eukaryotic organisms.
(b) Whittaker considered cell structure, mode and source of nutrition for classifying the organisms in five kingdoms.
(c) Both Monera and Protista may be autotrophic and heterotrophic.
(d) Monerans have well defined nucleus.
Answer:
(d) Monerans have well defined nucleus.

Question 2.
Which among the following has specialised tissue for conduction of water?
(i) Thallophyta
(ii) Bryophyta
(iii) Pteridophyta
(iv) Gymnosperms
(a) (i) and (ii)
(b) (ii) and (iii)
(c) (iii) and (iv)
(d) (i) and (iv).
Answer:
(c) (iii) and (iv)

Question 3.
Which among the following produce seeds?
(a) Thallophyta
(b) Bryophyta
(c) Pteridophyta
(d) Gymnosperms.
Answer:
(d) Gymnosperms.

MP Board Solutions

Question 4.
Which one is a true fish?
(a) Jellyfish
(b) Starfish
(c) Dogfish
(d) Silverfish.
Answer:
(c) Dogfish

Question 5.
Which among the following is exclusively marine?
(a) Porifera
(b) Echinodermata
(c) Mollusca
(d) Pisces.
Answer:
(b) Echinodermata

Question 6.
Which among the following animals have pores all over their body?
(a) Porifera
(b) Aves
(c) Mollusca
(d) Pisces.
Answer:
(a) Porifera

Question 7.
Which among the following have chi tin as cell wall?
(a) Sycon
(b) Yeast
(c) Jelly fish
(d) Euplectella.
Answer:
(c) Jelly fish

Question 8.
Which among the following is not a Monocotyledonous plant?
(a) Wheat
(b) Rice
(c) Maize
(d) Gram.
Answer:
(d) Gram.

Question 9.
Which among the following is not a dicotyledonous plant?
(a) Wheat
(b) Sunflower
(c) Mango
(d) Gram.
Answer:
(a) Wheat

Question 10.
An organism with a single cell is called _______ .
(a) Thallophyta
(b) Bryophyta
(c) Unicellular
(d) Multicellular.
Answer:
(c) Unicellular

MP Board Solutions

Question 11.
The amphibians of the plant is _______ .
(a) Thallophyta
(b) Bryophyta
(c) Unicellular
(d) Multicellular.
Answer:
(b) Bryophyta

Question 12.
Plant bearing naked seeds are _______ .
(a) Thallophyta
(b) Bryophyta
(c) Unicellular
(d) Gymnosperm.
Answer:
(d) Gymnosperm.

Diversity in Living Organisms Very Short Answer Type Questions

Question 1.
Name a saprophyte and also tell, why are they called so.
Answer:
Aspergillus: They are called so because they obtain their nutrition from dead and decaying matter.

Question 2.
Why are lichens called dual organisms?
Answer:
Lichens are permanent symbiotic association between algae and fungi. Therefore, they are called dual organisms.

Question 3.
State the phylum to which centipede and prawn belong.
Answer:
Arthropoda.

Question 4.
Name one reptile with four – chambered heart.
Answer:
Crocodile.

Question 5.
Identify kingdom in which organisms do not have well defined nucleus and do not show multicellular body designs.
Answer:
Monera.

Diversity in Living Organisms Short Answer Type Questions

Question 1.
Why do we differentiate organism, give two main basis?
Answer:
Due to variation in various characteristics, we differentiate organism. Two main basis are mode of nutrition and habitat.

Question 2.
Which kingdom generate food on earth and initiate food chain?
Answer:
Plantae.

MP Board Solutions

Question 3.
Which kingdom do not have cell wall to their cell?
Answer:
Animalia.

Question 4.
What do you understand by biodiversity?
Answer:
Biodiversity: The variety of living beings found in a particular geographical area is called biodiversity of that area. Amazon rainforests is the largest biodiversity hotspot in the world.

Question 5.
Why classification is required?
Answer:
Classification is necessary for the study of living beings in easy way. Without proper classification, it would be impossible to study millions of organisms which exist on this earth.

Question 6.
What was the basis of classification of Ancient Greek philosopher Aristotle?
Answer:
Aristotle classified living beings on the basis of their habitat. He classified them into two groups, i.e. those living in water and those living on land.

Question 7.
How can we divide organism on the basis of mode of nutrition ?
Answer:
On this basis, organisms can be divided into two broad groups, i.e. autotrophs and heterotrophs.

Question 8.
Define Monocotyledonous plants. Give examples.
Answer:
Monocotyledonous: There is single seed leaf in a seed. A seed leaf is a baby plant.
Examples:

  • wheat
  • rice
  • maize, etc.

Question 9.
Give example of Dicotyledonous plants.
Answer:
Dicotyledonous plants: Mustard, gram, mango etc.

Question 10.
Give one difference between prokaryotes and eukaryotes
Answer:

  1. Prokaryotes: When nucleus is not organized, i.e., nuclear materials are not membrane bound; the organism is called prokaryote.
  2. Eukaryotes: When nucleus is organized, i.e., nuclear materials are membrane bound; the organism is called eukaryote.

Question 11.
What is the difference between unicellular and multicellular organism?
Answer:

  1. Unicellular organism: An organism with a single cell is called unicellular organism.
  2. Multicellular organism: An organism with more than one cell is called multicellular organism.

MP Board Solutions

Question 12.
Write short notes on the following:
(a) Thallophyta
(b) Bryophyta
Answer:
(a) Thallophyta: The plant body is thallus type. The plant body is not differentiated into root, stem and leaves. They are known as algae also.
Examples:

  • Spirogyra
  • chara
  • volvox
  • ulothtrix etc.

(b) Bryophyta: Plant body is differentiated into stem and leaf like structure. Vascular system is absent, which means there is no specialized tissue for transportation of water, minerals and food. Bryophytes are known as the amphibians of the plant kingdom, because they need water to complete a part of their life cycle.
Examples:

  • Moss
  • marchantia.

Question 13.
What are cryptogams and phanerogams?
Answer:
Plant body is differentiated into root, stem and leaf. Vascular system is present. They do not bear seeds and hence are called cryptogams. Plants of rest of the divisions bear seeds and hence are called phanerogams.
Examples:

  • Marsilear
  • ferns
  • horse tails etc.

Question 14.
How gymnosperms are different from angiosperms?
Answer:

  1. Gymnosperms: They bear seeds. Seeds are naked i.e., are not covered. The word ‘gymnos’ means naked and ‘sperma’ means seed.
  2. Angiosperms: The seeds are covered. The word ‘angios’ means covered. There is great diversity in species of angiosperm.

Question 15.
What is porifera?
Answer:
Porifera: These animals have pores all over their body. The pores lead into the canal system. They are marine animals. Examples:

  • Sycon
  • Spongilla
  • Euplectella, etc.

Question 16.
What is coelenterata?
Answer:
Coelenterata: The body is made up of a coelom (cavity) with a single opening. The body wall is made up of two layers of cells (diploblastic).
Examples:

  • Hydra
  • jelly fish
  • sea anemone, etc.

Question 17.
What is Platyhelminthes?
Answer:
The body is flattened from top to bottom and hence the name platyhelminthes. These are commonly known as flatworms. The body wall is composed of three layers of cells (triploblastic).
Example:

  • Planaria
  • liver fluke
  • tapeworm etc.

Question 18.
What is Nematohelminthes and Annelida?
Answer:
Nematohelminthes: Animals are cylindrical in shape and the body is bilaterally symmetric and there are three layers in the body wall.
Example:

  • Roundworms
  • pinworms
  • filarial parasite (Wuchereria) etc.

Annelida: True body cavity is present in these animals. The body is divided into segments and hence the name annelida.
Example:

  • Earthworm
  • leech etc.

MP Board Solutions

Question 19.
Explain the followings:
(a) Arthropoda
(b) Mollusca
(c) Echinodermata
(d) Protochordata
(e) Chordata.
Answer:
(a) Arthropoda: Animals have jointed appendages which gives the name arthropoda. Exoskeleton is present which is made of chitin. This is the largest group of animals; in terms of number of species.
Examples:

  • cockroach
  • housefly
  • spider
  • prawn
  • scorpion etc.

(b) Mollusca: The animal has soft body; which is enclosed in a hard shell. The shell is made of calcium carbonate.
Examples:

  • Snail
  • mussels
  • octopus etc.

(c) Echinodermata: The body is covered with spines, which gives the name echinodermata. Body is radially symmetrical. The animals have well developed water canal system, which is used for locomotion.
Examples:

  • Starfish
  • sea urchins etc.

(d) Protochordata: Animals are bilaterally symmetrical, triploblastic and ceolomate. Notochord is present at least at some stages of life.
Examples:

  • Balanoglossus
  • herdmania
  • amphioxus etc.

(e) Chordata: Animals have notochord, pharyngeal gill slits and post anal tail; for at least some stages of life. Phylum chordata is divided into many sub – phyla; out of which we shall focus on vertebrata.

Diversity in Living Organisms Long Answer Type Questions

Question 1.
What is the different levels of organizations in case multicellular organism?
Answer:
Level of organization: Even in case of multicellular organisms, there can be different levels of organization:
(a) Cellular level of organization: When a cell is responsible for all the life processes, it is called cellular level of organization.

(b) Tissue level of organization: When some cells group together to perform specific function, it is called tissue level of organization.

(c) Organ level of organization: When tissues group together to form some organs, it is called organ level of organization. Similarly organ system level of organization is seen in complex organisms.

Question 2.
“Classification of living organism is based on evolution.” Explain.
Answer:
It is a well – established fact that all the life forms have evolved . from a common ancestor. Scientists have proved that the life begun on the earth in the form of simple life forms. During the course of time, complex organism evolved from them. So, classification is also based on evolution. A simple organism is considered to be primitive while a complex organism is considered to be advanced.

Question 3.
Explain five kingdom classification by Robert Whittaker (1959).
Answer:
Five Kingdom Classification by Robert Whittaker (1959):
This is the most accepted system of classification. The five kingdoms and their key characteristics are given below:

1. Monera: These are prokaryotes; which means nuclear materials are not membrane bound in them. They may or may not have cell wall. They can be autotrophic or heterotrophic. All organisms of this kingdom are unicellular. Examples: bacteria, blue green algae (cyanobacteria) and mycoplasma.
MP Board Class 9th Science Solutions Chapter 7 Diversity in Living Organisms 1

2. Protista: These are eukaryotes and unicellular. Some organisms use cilia or flagella for locomotion. They can be autotrophic or heterotrophic. Examples: unicellular algae, diatoms and protozoans.
MP Board Class 9th Science Solutions Chapter 7 Diversity in Living Organisms 2

3. Fungi: These are heterotrohic and have cell wall. The cell wall is made of chitin. Most of the fungi are unicellular. Many of them have the capacity to become multicellular at certain stage in saprophytic. Some fungi live in symbiotic relationship with other organisms, while some are parasites as well.
Examples:

  • Yeast
  • penicillum
  • aspergillus
  • mucor etc.

4. Plantae: These are multicellular and autotrophs. The presence of chlorophyll is a distinct characteristic of plants, because of which they are capable of doing photosynthesis. Cell wall is present.

5. Animalia: These are multicellular and heterotophs. Cell wall is absent. They feed on decaying organic materials.

Diversity in Living Organisms Higher Order Thinking Skills (HOTS)

Question 1.
What are the differences between Platyhelminthes and Nematohelminthes?
Answer:

PlatyhelminthesNematohelminthes
1. Form: They are flat in shape and are called flat worms.1. They are cylindrical in form and are called round worms.
2. Sexuality: Animals are hermaphrodite.2. Animals are uni – sexual.
3. Coelom: Platyhelminthes are acoelomate.3. Nematohelminthes are pseudocoelomate.
4. Digestive Tract: It is incomplete.4. It is complete

Question 2.
Differentiate between animals belonging to the Mammalia group and those in the Aves group.
Answer:
Differences between mammals and aves.

MammalsAves
1. Give birth to young ones except platypus and the echidna.1. Lay eggs.
2. Mammary glands are present.2. Mammary glands are absent.
3. Body covered with hair.3. Body covered with feathers.
4. Sweat and sebaceous glands are present in the skin.4. Sweat and sebaceous glands are not present in the skin.

Diversity in Living Organisms Value Based Questions

Question 1.
Ashish, a IX class student, was studying chapter, ‘Diversity in Living Organisms’. He thought that all the fungi are harmful as these spoil food and cause various diseases. However, his elder sister Dimple told him that not all fungi are harmful as these are also used in making bread, vitamins and medicines.

  1. Name any fungus which is the source of some medicine.
  2. Name any fungus which is used in bread making.
  3. What value are displayed by Ashish’s sister?

Answer:

  1. Pencillium.
  2. Yeast.
  3. Dimple acted as elder sister and enhanced his younger brother’s scientific knowledge about fungi and their functions.

Question 2.
Coral is getting diminished in all the oceans due to global warming. People in Goa island protects their coral by not allowing people / tourist to take it away.

  1. What is the phylum of coral?
  2. What is coral made up of?
  3. What value of people in Goa island is reflected here?

Answer:

  1. Coelenterates is the phylum of coral.
  2. It is made up of calcium carbonate.
  3. They reflect the value of being responsible citizen, respecting environment and nature.

MP Board Class 9th Science Solutions

MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1

MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1

Question 1.
In quadrilateral ABCD, AC = AD and AB bisects ∠A (see below). Show that ∆ABC = ∆ABD. What can you say about BC and BD?
MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1 img-1
Solution:
Given AC = AD
AB is the bisector of ∠A
i. e., ∠1 = ∠2
To prove: ∆ABC = ∆ABD
Proof:
In ∆ABC and ∆ABD
∠1 = ∠2 (given)
AC = AD (given)
AB = AB (common)
∆ABC ≅ ∆ABD (by SAS)

MP Board Solutions

Question 2.
ABCD is a quadrilateral in which AD = BC and ∠DAB = ∠CBA (see below). Prove that

  1. ∆ABD = ∆BAC
  2. BD = AC
  3. ∠ABD = ∠BAC

MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1 img-2
Solution:
Given AD = BC
∠DAB = ∠CBA
To prove:

  1. ∆ABD ≅ ∆BAC
  2. BD = AC
  3. ∠ABD = ∠BAC

Proof:
1. In ∆ABD and ∆BAC
AD = BC (Given)
∠DAB = ∠CBA (given)
AB = BA (common)
∆ABD = ∆BAC (by SAS)
and so 2. BD = AC (by CPCT)
and so 3. ∠ABD – ∠BAC (by CPCT)

Question 3.
AD and BC are equal perpendiculars to a line segment AB (see below). Show that CD bisects AB.
MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1 img-3
Solution:
Given: ∠B = ∠A (each 90°)
AD = BC
To prove: OA = OB
Proof:
In ∆OBC and ∆OAD
∠B = ∠A (each 90°)
BC = AD (given)
∠BOC = ∠AOD (V.O.A’s)
∆OBC = ∆OAD (by SAS)
and so OA = OB (by CPCT)

Question 4.
l and m are two parallel lines intersected by another pair of parallel lines p and q (see below). Show that ∆ABC = ∆CDM.
MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1 img-4
Solution:
Given: l ∥ m and p ∥ q
To prove:
∆ABC = ∆CDA
Proof:
In quadrilateral ABCD
AB ∥ DC and BC ∥ AD
∴ ABCD is a parallelogram
and so AB = DC [Opposite sides]
BC = AD
In ∆ABC and ∆CDA
AB = CD (proved)
BC = DA (proved)
AC = CA (proved)
∆ABC = ∆CDA (by SSS)

MP Board Solutions

Question 5.
Line l is the bisector of an angle ∠A and B is any point on l. BP and BQ are perpendiculars from B to the arms of ∠A (see below). Show that

  1. ∆APB = ∆AQB
  2. BP = BQ or B is equidistant from the arms of ∠A.

MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1 img-5
Solution:
Given
∠1 = ∠2
BQ ⊥ AC
and BP ⊥ AD
To prove:

  1. ∆APB ≅ ∆AQB
  2. BP = BQ

Proof:
In ∆APB and ∆AQB
∠2 = ∠1 (given)
∠P = ∠Q (each 90°)
AB = AB (common)
∆APB ≅ ∆AQB (byAAS)
BP = BQ (by CPCT)

Question 6.
In Fig. given below, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE.
MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1 img-6
Solution:
Given
AC = AE
AB = AD
∠BAD = ∠EAC i.e., ∠1 = ∠2
To prove: BC = DE
Proof:
In ∆ABC and ∆ADE
AB = AD (given)
AC = AE (given)
∠1 = ∠2 (given)
Adding ∠3 on both sides
∠1 + ∠3 = ∠2 + ∠3
∠BAC = ∠DAE
∆ABC = ∆ADE , (by SAS)
and so BC = DE (by CPCT)

MP Board Solutions

Question 7.
AB is a line segment and P is its mid-point. D and E are points on the same side of AB such that ∠BAD = ∠ABE and ∠EPA = ∠DPB (see below). Show that

  1. ∆DAP ≅ ∆EBP
  2. AD = BE

MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1 img-7
Solution:
Given:
AP = BP
∠BAD = ∠ABE
∠EPA = ∠DPB
∠1 = ∠2
To prove:

  1. ∆DAP ≅ ∆EBP
  2. AD = BE

Proof:
∠1 = ∠2 (given)
Adding ∠3 on both sides
∠1 + ∠3 = ∠2 + ∠3
∠APD = ∠BPE
In ∆DAP and ∆EBP
∠APD = ∠BPE (proved)
AP = BP (given)
∠PAD = ∠PBE (given)
∆DAP ≅ ∆EBP (by ASA)
and so AD = BE (by CPCT)

Question 8.
In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see below). Show that:

  1. ∆AMC = ∆BMD
  2. ∠DBC is a right angle.
  3. ∆DBC = ∆ACB
  4. CM = \(\frac{1}{2}\) AB

MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1 img-8
Solution:
∠C = 90°
AM = BM
DM = CM
To prove:

  1. ∆AMC ≅ ∆BMD
  2. ∆DBC = 90°
  3. ∆DBC ≅ ∆ACB
  4. CM = \(\frac{1}{2}\) AB

Proof:
1. ∆AMC and ∆BMD
AM = BM (given)
MC = MD (given)
∠1 = ∠2 (V.O.A’s)
∆AMC = ∆BMD (by SAS)
and so AC = DB and ∠4 and ∠3 (by CPCT)

2. ∠4 = ∠3 (proved) [AIA’s]
∴ DB ∥ AC
AC ∥ BD and BC is the transversal
∠C + ∠B = 180° (C.I.A’s)
∠B = 180° – 90° = 90°

3. In DBC and ∆ACB
DB = AC (proved)
∠B = ∠C (each 90°)
BC = CB (common)
∆DBC = ∆ACB (by SAS)
and so DC = AB (by CPCT)

4. DC =AB (proved)
\(\frac{1}{2}\)DC = \(\frac{1}{2}\)AB
CM = \(\frac{1}{2}\)AB.

MP Board Solutions

Theorem 7.3
AAS (Angle-Angle-Side) Congruence Theorem:
If any two angles and a non-included side of one triangle are equal to the corresponding angles and side of another triangle, then the two triangles are congruent.
Given:
In ∆s ABC and DEF, we have
MP Board Class 9th Maths Solutions Chapter 7 Triangles Ex 7.1 img-9
∠A = ∠D
∠B = ∠E
and BC = EF
To prove:
∆ABC = ∆DEF
Proof:
Since the sum of the angles of a triangle is 180°. We have
∠A + ∠B + ∠C = ∠D + ∠E + ∠F
Since ∠A = ∠D and ∠B – ∠E (Given)
∠C = ∠F …..(i)
Now, in ∆ABC and ∆DEF, we have
∠B = ∠E (Given)
∠C = ∠F [From, (i)]
and BC = EF (Given)
∴ ∆ABC ≅ ∆DEF [ASA Cong. Theorem]

MP Board Class 9th Maths Solutions

MP Board Class 9th Science Solutions Chapter 6 Tissues

MP Board Class 9th Science Solutions Chapter 6 Tissues

Tissues Intext Questions

Tissues Intext Questions Page No. 69

Question 1.
What is a tissue?
Answer:
A group of cells that are similar in structure and / or work together to achieve a particular function form a tissue.

Question 2.
What is the utility of tissues in multi – cellular organisms?
Answer:
In multi – cellular organisms, different types of tissues perform different functions. Since a particular group of cells carry out only a particular function, they do it very efficiently. So, multi – cellular organisms possess a specific division of labour.

Tissues Intext Questions Page No. 74

Question 1.
Name types of simple tissues.
Answer:

  1. Parenchyma
  2. Collenchyma and
  3. Sclerenchyma

Question 2.
Where is apical meristem found?
Answer:
At root tip and shoot tip.

Question 3.
Which tissue makes up the husk of coconut?
Answer:
Sclerenchymatous tissue.

Question 4.
What are the constituents of phloem?
Answer:
Phloem is made up of four types of elements: Sieve tubes, companion cells, phloem fibres and the phloem parenchyma.

Tissues Intext Questions Page No. 78

Question 1.
Name the tissue responsible for movement in our body.
Answer:
Muscular, tissue.

Question 2.
What does a neuron look like?
Answer:
A neuron is the unit of nervous tissue. It is elongated in shape and consists of three parts viz., dendrites, cell body and axon.

MP Board Solutions

Question 3.
Give three features of cardiac muscles.
Answer:

  1. Cardiac muscle cells are cylindrical, branched and uninucleate.
  2. They show rhythmic contraction and relaxation throughout life.
  3. They are involuntary muscles.

Question 4.
What are the functions of areolar tissue?
Answer:
Areolar tissue fills space inside the organs, supports internal organs and helps in repair of the tissues.

Tissues NCERT Textbook Exercises

Question 1.
Define the term ‘tissue’.
Answer:
The group of cells similar in structure that work together to achieve a particular function forms a tissue. This group of cells has a common origin.

Question 2.
How many types of elements together make up the xylem tissue? Name them.
Answer:
Xylem is formed of four types of elements.
They are:

  1. tracheids
  2. vessels
  3. xylem parenchyma
  4. xylem fibre.

Question 3.
How are simple tissues different from complex tissues in plants?
Answer:
Simple tissues are made of one type of cells which coordinate to perform a common function.
Complex tissues are made of more than one type of cells. All these coordinate to perform a common function.

Question 4.
Differentiate between parenchyma, collenchyma and sclerenchyma on the basis of their cell wall.
Answer:

Question 5.
What are the functions of the stomata?
Answer:
Functions of stomata:

  1. Exchange of gases, particularly CO2 and O2 with atmosphere.
  2. Loss of water in the form of vapours during transpiration.

Question 6.
Diagrammatically show the difference between the three types of muscle fibres.
Answer:
MP Board Class 9th Science Solutions Chapter 6 Tissues 2

Question 7.
What is the specific function of the cardiac muscle?
Answer:
The specific function of cardiac muscle is to contract and relax rhythmically throughout life.

Question 8.
Differentiate between striated, unstriated and cardiac muscles on the basis of their structure and site / location in the body.
Answer:
MP Board Class 9th Science Solutions Chapter 6 Tissues 3

Question 9.
Draw a labelled diagram of a neuron.
Answer:
MP Board Class 9th Science Solutions Chapter 6 Tissues 4

Question 10.
Name the following:

  1. Tissue that forms the inner lining of our mouth.
  2. Tissue that connects muscle to bone in humans.
  3. Tissue that transports food in plants.
  4. Tissue that stores fat in our body.
  5. Connective tissue with a fluid matrix.
  6. Tissue present in the brain.

Answer:

  1. Squamous epithelium.
  2. Tendons.
  3. Phloem.
  4. Adipose tissue.
  5. Blood.
  6. Nervous tissue.

Question 11.
Identify the type of tissue in the following: skin, bark of tree, bone, lining of kidney tubule, vascular bundle.
Answer:

  1. Skin: Striated squamous epithelium
  2. Bark of tree: Cork (protective tissue)
  3. Bone: Connective tissue
  4. Lining of kidney tubule: Cuboidal epithelium tissue
  5. Vascular bundle: Conducting tissue (xylem and phloem).

Question 12.
Name the regions in which parenchyma tissue is present.
Answer:
Parenchyma is found in cortex and pith of both root and stem. When it contains chlorophyll, it is called chlorenchyma, found in green leaves.

MP Board Solutions

Question 13.
What is the role of epidermis in plants?
Answer:
Cells of epidermis form a continuous layer without intercellular spaces. It protects all the parts of the plant.

Question 14.
How does the cork act as a protective tissue?
Answer:
In older plants, the secondary meristem forms on its outerside several layered thick cork or the bark. Cork acts as a protective tissue because:

  1. Its cells are dead and compactly arranged without intercellular spaces
  2. Its cells also have deposition of suberin in their walls that makes them impervious to gases and water.

Thus, cork protects the underlying tissues from excessive loss of water, adverse external environment and mechanical injuries.

Question 15.
Complete the table:
MP Board Class 9th Science Solutions Chapter 6 Tissues 5
Answer:
MP Board Class 9th Science Solutions Chapter 6 Tissues 6

Tissues Additional Questions

Tissues Multiple Choice Questions

Question 1.
The spindle shaped cells, uninucleated and unbranched are present in muscular tissue of _________.
(a) Striated muscles
(b) Smooth muscles
(c) Cardiac muscles
(d) Both (a) and (b).
Answer:
(b) Smooth muscles

Question 2.
The size of the stem increases in the width due to _________.
(a) Apical meristem
(b) Intercalary meristem
(c) Primary meristem
(d) Lateral meristem.
Answer:
(d) Lateral meristem.

Question 3.
The cells of cork are dead and have a chemical in their walls that makes them impervious to gas and water. The chemical is _________.
(a) Lignin
(b) Suberin
(c) Cutin
(d) Wax.
Answer:
(b) Suberin

Question 4.
The tissue that helps in the movement of our body are _________.
(a) Muscular tissue
(b) Skeletal tissue
(c) Nervous tissue
(d) All of the above.
Answer:
(d) All of the above.

Question 5.
The connective tissue that connects muscle to bone is called _________.
(a) Ligament
(b) Tendon
(c) Cartilage
(d) Areolar.
Answer:
(b) Tendon

Question 6.
Cartilage and bone are types of _________.
(a) Muscular tissue
(b) Connective tissue
(c) Meristematic tissue
(d) Epithelial tissue.
Answer:
(b) Connective tissue

Question 7.
A tissue whose cells are capable of dividing and re – dividingis called _________.
(a) Complex tissue
(b) Connective tissue
(c) Permanent tissue
(d) Meristematic tissue.
Answer:
(d) Meristematic tissue.

Question 8.
The tissue that helps in the secretion and absorption and is found in the inner lining of the alimentary canal is?
(a) Ciliated epithelium
(b) Cuboidal epithelium
(c) Squamous epithelium
(d) Columnar epithelium.
Answer:
(d) Columnar epithelium.

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Question 9.
The flexibility in plants is due to a tissue called?
(a) Chlorenchyma
(b) Parenchyma
(c) Sclerenchyma
(d) Collenchyma.
Answer:
(d) Collenchyma.

Question 10.
The tissue present in the lining of kidney tubules and ducts of salivary glands is?
(a) Squamous epithelium tissue
(b) Glandular epithelium tissue
(c) Cuboidal epithelium tissue
(d) Columnar epithelium tissue.
Answer:
(d) Columnar epithelium tissue.

Tissues Very Short Answer Type Questions

Question 1.
Name two main groups of plant tissue.
Answer:
Two groups are:

  1. meristematic tissues and
  2. permanent tissues.

Question 2.
Where will you look for meristematic cells in a plant body?
Answer:
The meristematic cells are present only at the growing regions such as shoot tips, root tips and at the base of the leaves or internodes.

Question 3.
What are simple permanent tissues?
Answer:
Simple permanent tissues consist of one type of cells which look like each other.

Question 4.
Name two types of simple permanent plant tissues.
Answer:
Simple permanent plant tissues are:

  1. Parenchyma
  2. Collenchyma and
  3. Sclerenchyma.

Question 5.
Write four elements of xylem.
Answer:

  1. Tracheids
  2. Vessels
  3. Xylem parenchyma
  4. Xylem fibres.

Question 6.
What are the three types of muscle fibres (muscle cells)?
Answer:
Three types of muscle fibres are:

  1. Striated muscle (skeletal muscle or voluntary muscle).
  2. Unstriated muscle (smooth muscle or involuntary muscle).
  3. Cardiac muscle.

Question 7.
What are the various functions of all types of epithelial tissues?
Answer:
Epithelial tissues help in

  1. protection
  2. absorption
  3. excretion
  4. exchange of respiratory gases
  5. secretion.

Question 8.
What is basement membrane?
Answer:
It is a very thin non – cellular membrane on which cells of epithelial tissue rest. It also separates the epithelial tissue from the underlying tissues.

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Question 9.
Of which type of muscles the stomach wall is made of? Whether they are voluntary or involuntary?
Answer:
Smooth or non-striated. They are involuntary muscles.

Question 10.
What is the function of connective tissue?
Answer:
Connective tissue connects different tissues and organs. It provides support to different parts of the body by forming packing around different organs of the body

Question 11.
What are the two main features of connective tissue?
Answer:

  1. Cells are loosely spaced and are embedded in matrix.
  2. Matrix may be jelly – like, fluid, dense or rigid.

Question 12.
Name one animal whose whole skeleton is made of cartilage.
Answer:
Shark fish.

Question 13.
List seven examples of connective tissue.
Answer:

  1. Bone
  2. Cartilage
  3. Tendons
  4. Ligaments
  5. Areolar tissue
  6. Adipose tissue and
  7. Blood.

Question 14.
What are blood platelets?
Answer:
Blood platelets are minute (about 2 to 4μ in diameter), anucleated, disc like bodies. The main function of platelets is to help in clotting of blood.

Question 15.
Name the connective tissue that is found between skin and muscles.
Answer:
Areolar connective tissue fills the space between skin and muscles.

Question 16.
How would you recognize that the slide given to you is of striated muscle? Give only two important points.
Answer:

  1. Striated muscles have light and dark bands (which gives it a striped look).
  2. Striated muscle fibres are not branched like cardiac muscles.

Question 17.
From which part of a nerve cell, dendrites arise?
Answer:
The cell body.

MP Board Solutions

Question 18.
Name the tissue present in the brain.
Answer:
Nervous tissue (formed of neuron cells).

Question 19.
Which cell is the longest in the body of an animal?
Answer:
Neuron (Nerve cell) which may be upto 1m long (in special cases).

Question 20.
Name a fluid, except blood, which circulates in the body.
Answer:
Lymph.

Question 21.
Why are striated muscles generally called skeletal muscles?
Answer:
In general, striated muscles are attached with the bones. They help in the movement of the bones. So, they are also called skeletal muscles.

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Question 22.
Name one muscle which does not fatigue and works throughout life in normal conditions.
Answer:
Cardiac muscles.

Question 23.
How are ligaments different from tendons?
Answer:
Ligaments are elastic connective tissues which attach bones with each other to keep them in then placer Tendons arc less elastic connective tissues which attach, muscles to a bone.

Question 24.
What is the main function of meristematic tissue?
Answer:
The mam function of meristematic tissue is to form continuously new cells for increasing cell number, length and the girth of the plant.

Tissues Short Answer Type Questions

Question 1.
How do tissues formed in multicellular organisms?
Answer:
During development from zygote (formed by the union of egg and sperm), a large number of cells are formed. These cells undergo differentiation to produce various specialised tissues to perform different functions in the living body.

Question 2.
What are the characteristics of plant tissues?
Answer:
Plants are stationary or fixed, they do not need much energy. So, most of the tissues they have are supportive, which provide them with structural strength. Most of these tissues are dead; they do not contain living protoplasm.

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Question 3.
What are structural and functional differences between plants and animals?
Answer:
As plants do not move, they do not need much energy. So, most of the tissues they have are dead and supportive. But animals need energy as they move around in search of food, mate and shelter. So, most of the animal tissues are living.

Question 4.
Why do meristematic cells lack vacuoles?
Answer:
Meristematic cells divide frequently to give rise to new cells. So, they need dense cytoplasm and soft cell wall. Vacuoles cause hindrance in cell division as they are full of cell sap and provide turgidity and rigidity to the cell.

Question 5.
What are characteristic structural features of meristematic cells ?
Answer:
Meristematic cells have:

  1. Thin cell walls.
  2. Abundant or dense cytoplasm and single large nucleus.
  3. Spherical, oval, polygonal or rectangular shape.
  4. No intercellular spaces between them.
  5. Either no vacuoles at all or a few vacuoles.

Question 6.
List any four salient features of meristematic tissue.
Answer:

  1. This tissue consists of actively dividing cells.
  2. This tissue is present in growing regions of plants.
  3. In this tissue, cells are packed closely without intercellular spaces.
  4. Cells of this tissue have thin cell walls, dense cytoplasm and prominent nuclei.

Question 7.
What are permanent tissues?
Answer:
The cells of meristematic tissue lose the ability to divide and get differentiated into specialised cells. These differentiated cells form different types of tissues which are known as permanent tissues.
Some examples: permanent tissues are

  • parenchyma
  • sclerenchyma etc.

Question 8.
With the help of only schematic line diagram, show classification of main permanent tissues.
Answer:
MP Board Class 9th Science Solutions Chapter 6 Tissues 7

Question 9.
Write the characteristics of collenchyma.
Answer:
The cells in this type of tissue are living, elongated and thickened with cellulose at the corners. There is very little intercellular space. This tissue provides flexibility and mechanical support to plants. It is found in hypodermis of stems and leaf stalks.

Question 10.
What are protective tissues?
Answer:
All parts of plants e.g., leaves, flowers, stems and roots are covered by a single outermost protective layer called epidermis. It consists of rectangular, closely fitted relatively flat cells which lack intercellular spaces. Usually, it is one cell thick and is covered with cutin. Epidermis protects internal tissues of the plant.
MP Board Class 9th Science Solutions Chapter 6 Tissues 8

Question 11.
Does the outer most protective layer is throughout, continuous? If not, what interruptions are usually foundation leaves and herbaceous parts of the plant?
Answer:
Epidermis is the outermost layer of cells in leaves and green herbaceous stems. It is not a continuous layer as it contain numerous minute pores called stomata.

Question 12.
Write major functions of stomata present in the epidermis.
Answer:
Major functions of stomata:

  1. Stomata are essential for exchange of gases – oxygen and carbon dioxide between the plant and the atmosphere.
  2. Normally, plants remove excessive water in the form of vapour through stomata. This process is called transpiration.

Question 13.
What is the main function of vascular tissues in plants?
Answer:
Vascular tissues transport:

  1. Water and dissolved minerals from toots to various parts of the plant (xylem).
  2. Prepared food material from leaves to different plant parts (phloem).

Question 14.
What ire vascular bundles?
Answer:
In plants, complex tissues xylem and phloem altogether constitute a structure called vascular bundle. Their main function is transportation of water, salts and food materials within the plant body.

Question 15.
List four elements of phloem. Which one of them is most important and why?
Answer:
Phloem consists of following four elements:

  1. Sieve tubes
  2. Companion cells
  3. Phloem parenchyma
  4. Phloem fibres.

The most important element of phloem is sieve tubes because they translocate food materials from leaves to other parts of plant.

MP Board Solutions

Question 16.
What is muscular tissue? What is their function?
Answer:
1. Muscular tissue: This is a specialised tissue which is composed of contractile, fibre – like cells. This tissue is responsible for movement in our body.

2. Function: The movement of the body or limbs is brought about by contraction and relaxation of contractile proteins present in the muscle cells.

Question 17.
In desert plants, epidermis is covered by waxy substances. Can you think why?
Answer:
Waxy substances which cover epidermis are waterproof and hence, they check loss of water during transpiration. Besides this, they also aid in protection against mechanical injury and invasion by parasitic fungi.

Question 18.
What are the four important types of tissues found in animals?
Answer:
The four animal tissues found in animals are:

  1. Epithelial tissues.
  2. Connective tissues.
  3. Muscular tissues and.
  4. Nervous tissue.

Question 19.
State one important function of each of the following:

  1. Areolar tissue
  2. Cuboidal epithelium.

Answer:

  1. Areolar tissue: It fills the space inside the organs, supports internal organs and helps in repair of tissues.
  2. Cuboidai epithelium: it forms the lining of kidney tubules and ducts of salivary glands where it provides mechanical support.

Question 20.
What are the two main components of blood? Why is blood considered a type of connective tissue?
Answer:
Blood has two main components:

  1. Fluid (liquid) matrix called plasma.
  2. Suspended red blood cells (RBCs), white blood cells (WBCs) and platelets.

Blood is considered as a connective tissue because:

  1. It has the same Origin as the other connective tissues.
  2. It flows to different parts of the body and thus, connects different parts of the body with one another to exchange materials and gases.

Question 21.
Why do blood and lymph called as connective tissues?
Answer:
The fluid tissue (blood and lymph) connects various parts (cells) of the body. It supplies nutritive materials, oxygen and hormones collected from different organs to the body tissues. It also collects waste materials from different body tissues and delivers to excretory organs.

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Question 22.
Why is blood called as fluid connective tissue?
Answer:
Blood is considered as a connective tissue because it connects different parts of the body. It contains plasma as matrix in which blood cells remain suspended. Being matrix (plasma) in liquid state, blood is called fluid connective tissue.

Question 23.
Explain how the bark of a tree is formed. How does it act as a protective tissue?
Answer:
As trees grow old, a strip of secondary meristem replaces the epidermis of the stem. Cells on the outside are cut off from this layer. This forms the several layer thick cork or the bark of the tree. Bark is a mass of dead tissue lying in the peripheral region of the plant body as a hard dry covering. Its function is protection. It protects the inner tissues against the attack of fungi and insects, against loss of water by evaporation etc.

Question 24.
What is the difference between voluntary and involuntary muscles? Give example of each.
Answer:
Voluntary muscles are those which are directly under control of our will
e.g.

  • skeletal muscle.

They work or contract on our command. Involuntary muscles are not under the command of our will. We cannot control contraction and relaxation of these muscles. They are of two types – smooth muscles and cardiac muscles. Smooth muscles are found in stomach, intestine, iris of eye, in ureters and in the bronchi of lungs. Another type of involuntary muscles that is, cardiac muscles are found in heart.

Tissues Long Answer type Questions

Question 1.
The following diagrams are of L.S. of shoot apex and L.S. of root apex. Observe the diagrams and answer the questions given below:

  1. What type of cells shoot apex and root apex consists of?
  2. What are the main characteristics of these cells?
    MP Board Class 9th Science Solutions Chapter 6 Tissues 9

Answer:

  1. Meristematic cells.
    • (a) Cells have big nucleus and dense cytoplasm.
    • (b) These cells lack intercellular spaces and vacuoles.

Question 2.
How many types of meristems are present in plants, on the basis of position?
Answer:
On the basis of location of meristem, it is classified into three types:

1. Apical meristem: It is present at the tip of stem, root and their branches.

2. Intercalary meristem: It is found at the leaf base, above the nodes (i.e. at the base of internodes as in grasses) or below the nodes (i.e. at the upper most region of internode as in mint.)

3. Lateral meristem: Vascular cambium and cork cambium are the examples of lateral meristem. Vascular cambium is found in vascular bundles while cork cambium is found underneath the bark of trees. Both of these cause increase in the girth of plants.

Question 3.
Draw a labelled diagratn of shoot to show location of meristematic tissues in the plant body and write the functions of each of them.
Answer:
Functions:

  1. Apical meristem: It increases the length of the stem and the root.
  2. Lateral meristem (cambium): It increases the girth of the stems and roots.
  3. Intercalary meristem: It is present at the base of the leaves or internode (on either side of the node).

It produces buds which develop in auxiliary branches or auxiliary floral branches.
MP Board Class 9th Science Solutions Chapter 6 Tissues 10

Question 4.
Explain the structure of parenchyma. What are its major modifications?
Answer:
Parenchyma: It is the basic or fundamental tissue found in plants. Cells of this tissue are thin walled, circular or polygonal. They are living with a nucleus and a vacuole. Intercellular spaces are present between the cells of this tissue. Two modifications of parenchyma are chlorenchyma and aerenchyma.

Chlorenchyma: Sometimes cells of the parenchyma contain chlorophyll and perform photosynthesis. This kind of parenchyma is known as chlorenchyma.

Aerenchyma: In aquatic plants, parenchyma contains big air spaces in between them. Such a parenchyma tissue is known
MP Board Class 9th Science Solutions Chapter 6 Tissues 11
(a) Parenchyma with intercellular spaces.
(b) Aerenchyma with big spaces

Question 5.
Write the main functions of parenchyma.
Answer:
Functions of the parenchyma:

  1. They store food.
  2. They provide temporary support by retaining the turgid condition of cells.
  3. Chlorenchyma containing chloroplasts prepare food through photosynthesis.
  4. In aquatic plants, aerenchyma gives buoyancy to plants and hence they can float easily.

Question 6.
Describe the structure of selerenchyma. Write its major functions.
Answer:
Selerenchyma: Selerenchyma is the chief mechanical tissue of plants. The cells of this tissue are usually long, narrow and pointed at both ends. Due to deposition of lignin, their walls are often very highly thickened. Hence, the lumen of cell cavity is nearly obliterated. They are usually provided with simple pits which may be oblique or straight.
The selerenchyma cells are dead cells and their main function is to provide strength and rigidity to the plant.
MP Board Class 9th Science Solutions Chapter 6 Tissues 12

Question 7.
What is xylem? Explain its structure. Which one of its component is very important and why?
Answer:
Xylem is a complex plant tissue which transports water and dissolved minerals from roots to all other plant parts.
MP Board Class 9th Science Solutions Chapter 6 Tissues 13
Structure: Xylem consists of four kinds of cells (also known as elements):
(i) Tracheids: A tracheid is an elongated, hollow cell with its both ends tapering. The walls of these cells are thickened by the deposition of lignin. At certain spots lignin is not present. These spots are termed as pits. The tracheids are dead cells.

(ii) Vessels: These are tube like structures formed by a number of cells placed end to end with their transverse walls dissolved. The side walls of these tubes also have deposition of lignin. The thickening of the walls show various kinds of patterns. They are also dead cells.

(iii) Xylem parenchyma: These are parenchymatous, thin walled, living cells. They help in lateral conduction of water and sap. They also store food.

(iv) Xylem fibres: They are lignified dead fibres which provide mechanical support to plant. The most important element of xylem is vessel because most of the water and minerals are carried upward through this component of xylem.
MP Board Class 9th Science Solutions Chapter 6 Tissues 15

Question 8.
Describe the structure of phloem.
Answer:
Structure of phloem: The main conducting part of the phloem is sieve tube which is formed of elongated cylindrical cells arranged in vertical rows. The walls between the cells have many minute pores through which food material can pass from one cell to the next. The porous walls between the cells is termed as sieve plate. Each sieve tube is supported by a long parenchymatous cell called the companion cell which helps the sieve tubes in the conduction of food material.
MP Board Class 9th Science Solutions Chapter 6 Tissues 16
The above figure shows that phloem also contains phloem fibres, which provide mechanical support. Another component of phloem is parenchyma cells which stores food.

Question 9.
What is epithelial tissue?
Answer:
Epithelial Tissue: Epithelial tissue forms covering of entire surface of the body and lines the internal organs. Because of this, epithelial tissue is also called protective tissue. It also forms a barrier to keep different body systems separate. In this tissue cells are closely associated and arranged on a very thin extracellular fibrous basement membrane. Epithelial tissue may be composed of one (simple epithelium) or more layers of cells (compound epithelium). The skin, lining of mouth and alimentary canal, lung alveoli etc. are made of epithelial tissues.

Question 10.
What are the four main functions of epithelial tissue?
Answer:
The four main functions of epithelial tissue are:

  1. It forms the outer layer of skin and hence it protects the underlying cells from drying, injury, bacterial and chemical effects..
  2. It forms lining of mouth, alimentary canal and other internal organs and thus protects these organs.
  3. It helps in absorption of water and other nutrients in alimentary canal.
  4. Some of them are greatly specialised and perform secretory function.

Question 11.
What are the categories of epithelial tissue depending upon the shape and function of epithelial cells?
Answer:
Depending upon the shape and function of the cells, epithelial tissue is classified as:
MP Board Class 9th Science Solutions Chapter 6 Tissues 17

Question 12.
What are the various forms of epithelial tissues? Describe briefly.
Answer:
(i) Squamous epithelium: The cells of this tissue are thin and flat forming a delicate lining. It is found in the alveoli and blood vessels. Tongue, oesophagus and lining of mouth also made up of squamous epithelium.

(ii) Cuboidal epithelium: The cells of this tissue are cube like in appearance. It is found in the lining of kidney tubules and ducts of salivary glands etc.

(iii) Columnar epithelium: The cells of this tissue are more tall and wide, placed side by side. Their nuclei are situated near the bases. They may have finger like . projections – the microvilli on their free surfaces. This tissue usually lives in the internal surface of stomach and intestine.

(iv) Ciliated epithelium: The cells of this tissue are modifications of columnar epithelial cells. They have many small hair like projections called cilia on their free ends. This type of epithelium is found in trachea and oviduct.

(v) Striated squamous epithelium: Cells of this tissue are similar to squamous epithelial cells but in this tissue they are arranged in many layers to prevent wear and tear of parts. In skin, striated squamous epithelium is found.
MP Board Class 9th Science Solutions Chapter 6 Tissues 18

(vi) Glandular epithelium: In this type of epithelium, cells secrete substances at the epithelial surface. Such type of epithelium is found in glands.
MP Board Class 9th Science Solutions Chapter 6 Tissues 19

Question 13.
Explain the structure of three types of muscle fibres. Also write the locations where they are found in the body.
Answer:
The following are the three types of muscle cells:
(i) Unstriated muscles: (Also known as smooth, involuntary muscles). This type of muscular tissue consists of spindle – shaped, long uninucleate cells. These muscles are present in alimentary canal, blood vessels, iris of eye, in ureters and bronchi of lungs etc.

(ii) Striated muscles: Also known as voluntary muscles because of their function being in our control or will. This type of muscular cells are long multi – nucleated and, enclosed in a membrane known as sarcolemma. Each fibre has several longitudinal filaments embedded in cytoplasm. These filaments give these muscles striated appearance. These muscles are attached to the skeleton; so they are also called skeletal muscles.
MP Board Class 9th Science Solutions Chapter 6 Tissues 20

(iii) Cardiac muscles: These muscles are found in heart. They are not under the control of the will. They contract rhythmically and involuntarily throughout life without the sign of fatigue. Structurally they show the characters of both unstriated and striated muscles. They are made up of branched fibres. These fibres are uninucleated and show alternate light and dark bands (striations).

Question 14.
What are three main categories of connective tissue?
Answer:
Categories of Connective Tissue:
(i) Connective tissue: There is a matrix in which generally two types of (white and yellow) fibres are present. In between these fibres some connective tissue cells are present.
Examples of this kind of connective tissues are

  • areolar tissue and
  • adipose tissue.

(ii) Skeletal tissue: This type of tissue forms the skeleton of an organism. It is of two types – cartilage and bone Cartilage has solid matrix, called chondrin, in which fibres and cells known as chondrocytes are present. Usually, cells are present in clusters of 2 – 3 cells in small spaces called lacunae. Cartilage is found in the regions of pinna, nose, trachea and larynx. In bones, matrix is formed of a protein called ossein impregnated with phosphate and carbonates of calcium and magnesium.

(iii) Fluid tissue: Blood and lymph are examples of fluid connective tissue. These are specialized connective tissues. It consists of liquid matrix with no fibres. In liquid matrix called plasma corpuscles remain suspended. Blood transports food material, gases and other substances to the various parts of the body.

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Question 15.
What are fibrous connective tissue?
Answer:
Fibrous connective tissue. It is of two types:
(i) The white fibrous connective tissue: It consists of white, non-elastic, unbranched fibres which unite to form bundles called tendons. Tendons are strong, tough and smooth, rope like structures which serve to attach muscles with the bones.

(ii) The yellow fibrous connective tissue: It also consists of fibres which are fine thread like structures. These fibres are quite elastic. Like white elastic fibres, these fibres also form cords called ligaments. These ligaments connect two bones.

Question 16.
Describe the structure of cartilage and bone.
Answer:
1. Cartilage: It is a solid but semi – rigid and flexible connective tissue. It has large, bluntly angular cartilage cells called chondrocytes. They occur in clusters of 2 or 3 in small spaces (lacunae) scattered in the matrix. Cartilage smoothens bone surfaces at joints and is also present in the nose, ear, trachea and larynx.

2. Bone: Bone is a solid, rigid and strong connective tissue. Its matrix become hard due to the deposition of salts of calcium and phosphorus. Osteocytes or bone cells are present in irregular spaces – lacunae in the matrix, interconnected by fine canals called canaliculi. In this tissue, matrix deposits in concentric rings around narrow longitudinal cavities called Haversian canals. These canal carries blood vessels and nerves.
MP Board Class 9th Science Solutions Chapter 6 Tissues 21

Question 17.
Explain the structure of a fluid connective tissue.
Answer:
Blood is a fluid connective tissue consists of:

  1. Blood plasma: It is the fluid matrix which contains 85% to 90% water, 7% different types of proteins, 0.9% of salts, about 0.1% glucose and a very small amount of hormones, wastes etc. In the plasma, blood corpuscles (cells) are suspended.
  2. Blood cells. Three kinds of blood cells are found suspended in the blood plasma.

These are:
(a) Red blood corpuscles (erythrocytes) or RBC
(b) White blood corpuscles (leucocytes) or WBC and
(c) Blood platelets.

(a) Red blood corpuscles (erythrocytes) or RBC:
The red blood corpuscles are biconcave, disc – like cells which are devoid of nucleus. They contain a substance called haemoglobin because of this they appear red in colour. The most important function of the RBC is the transport of oxygen and carbon dioxide.

(b) White blood corpuscles (leucocytes) or WBC: These cells are comparatively larger in size, colourless and irregular in appearance. They are devoid of haemoglobin. They protect our body from diseases by destroying germs.

(c) Blood platelets: These are small, 2 – 4μ in diameter. They are without nucleus. Their main function is to liberate some substances which helps in blood clotting.
MP Board Class 9th Science Solutions Chapter 6 Tissues 22

Question 18.
What are areolar tissue and adipose tissue? Where are they located?
Answer:

  1. Areolar tissue: It is a connective tissue which consists of matrix, several types of cells, collagen and elastin fibres.
  2. Location: They are found between the skin and muscles, around blood vessels and nerves and in the bone marrow.
  3. Functions: It fills space inside the organs, support internal organs and helps in repair of the tissues.
    MP Board Class 9th Science Solutions Chapter 6 Tissues 23
  4. Adipose tissue: It consists of cells (adipocytes) which are filled with fat globules. These cells remain scattered in a matrix.
  5. Location: It is found below the skin and between internal organs.
  6. Function: It stores fats and act as insulator.
    MP Board Class 9th Science Solutions Chapter 6 Tissues 24

Question 19.
(i) What is a nervous tissue?
(ii) Draw a well labelled diagram of neuron. (label any 4 parts).
Answer:
(i) Nervous Tissue: Nervous tissue is made up of specialised cells called nerve cells or neurons. Each nerve cell is elongated in shape and consists of three parts: cell body, dendrites and axon.The cell body contains a distinct nucleus and has a special kind of granules, called Nissel’s granules in the cytoplasm. From the cell body a single long part called the axon and many branched parts called dendrites arise. In some nerve cells, the axon has a thick white covering called medullary sheath. The terminal end of axon is without sheath and branched. Each nerve cell receives message through the dendrites and sends them to the axon (see Fig. below).
(ii)
MP Board Class 9th Science Solutions Chapter 6 Tissues 14

Tissues Higher Order Thinking Skills (HOTS)

Question 1.
Cutting of rose plant is done timely in gardens, but still it regain its length. Give reason.
Answer:
In rose plant, intercalary meristeim is present at the base of leaves or internodes. The cells of these tissues, therefore divide and increase the length of plant.

MP Board Solutions

Question 2.
Why does water hyacinth floats on water?
Answer:
A type of parenchyma called aerenchyma is present in water hyacinth. This encloses a lot of air and makes the plant lighter than water. Therefore, it floats on water.

Tissues Value Based Question

Question 1.
A patient suffering from paralysis was unable to walk. His family members took the utmost care of him:

  1. Name two tissues responsible for the movement of body?
  2. What are the tissues present in brain and spine?
  3. What value of the family members is seen in the above case?

Answer:

  1. Two tissues responsible for movement of the body are nervous tissue and muscular tissue.
  2. The tissues present in brain and spine are nervous tissues.
  3. His family members showed the value of being kind, caring, dutiful and responsible.

MP Board Class 9th Science Solutions

MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.3

MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.3

Question 1.
In Fig. given below, sides QP and RQ of ∆PQR are produced to points S and T respectively. If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.3 img-1
Solution:
Given
∠SPR = 135°
∠PQT = 110°
To find. ∠PRQ
Calculation:
∠Q = 110°
110° + ∠PQR = 180° (LPA’s)
∠1 = 70°
∠P = ∠1 + ∠PRQ
135° = 70° + ∠PRQ
135° – 70° = ∠PRQ
65° = ∠PRQ

Question 2.
In Fig. given below, ∠X = 62°, ∠XYZ = 54°. If YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively of ∠XYZ, find ∠OZY and ∠YOZ.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.3 img-2
Solution:
Given
∠X = 62°, ∠XYZ = 54°
∠OYZ = \(\frac{1}{2}\)∠XYZ
∠OZY = \(\frac{1}{2}\)∠XZY
To find ∠OZY and ∠YOZ
Calculation:
In ∠XYZ
∠X + ∠Y + ∠Z = 180° (ASP)
62° + 54° + ∠Z = 180°
116° + ∠Z = 180°
∴ ∠Z = 64°
In ∠OYZ
∠OYZ + ∠OZY + ∠O = 180° (ASP)
⇒ \(\frac{1}{2}\)∠XYZ + \(\frac{1}{2}\)∠XZY + ∠O = 180°
32° + 27° + ∠O = 180°
59° + ∠O = 180°
∠O = 121°

Question 3.
In Fig. given below, if AS ∥ DE, ∠BAC = 35° and ∠CDE = 53°, find ∠DCE.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.3 img-3
Solution:
Given
AS ∥ DE,
∠BAC = 35°
∠CDE = 53°
To find. ∠DCE
Calculation:
AB ∥ DE and AE is the transversal.
∠BAE = ∠AED = 35°
In ∆DEC
∠D + ∠E + ∠C = 180°
53° + 35° + ∠C = 180°
88° + ∠C = 180°
∠C = 180° – 88° = 92°

MP Board Solutions

Question 4.
In Fig. given below, if lines PQ and RS intersect at point T, such that ∠PRT = 40°, ∠RPT = 95° and ∠TSQ = 75°, find ∠SQT.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.3 img-4
Solution:
Given
∠PRT = 40°
∠RPT = 95°
∠TSQ = 75°
To find. ∠SQT
Calculation:
In ∆PRT
∠P + ∠R + ∠T= 180° (ASP)
95° + 40 ° + ∠T= 180°
∠T = 180° – 135° = 45°
∠T = ∠STQ = 45°
In ∆TSQ
∠STQ + ∠S + ∠Q = 180° (V.O.A’S)
45° + 75° + ∠Q = 180° (ASP)
∠Q = 180° – 120° = 60°

Question 5.
In Fig. given below, if PQ ⊥ PS, PQ ∥ SR, ∠SQR = 28° and ∠QRT = 65°, then find the values of x and y.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.3 img-5
Solution:
Given
PQ ⊥ PS
PQ ∥ SR
∠SQR = 28°
∠QRT = 65°
To find, x and y
Calculation:
PQ ∥ SR and QR is the transversal
x + 28° = 65° (A.I.A’s)
x = 65° – 28° = 37°
In ∆PQS
x + y + 90° = 180° (ASP)
37° + y + 90° = 180°
∴ y = 180° – 127° = 53°

Question 6.
In Fig. given below, the side QR to ∆PQR is produced to a point S. If the bisectors of ∠PQR and ∠PRS meet at point T, then prove that ∠QTR = \(\frac{1}{2}\) ∠QPR.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.3 img-6
Solution:
Given
∠TQR = \(\frac{1}{2}\)∠PQR
∠TRS = \(\frac{1}{2}\)∠PRS
To prove. ∠QTR = \(\frac{1}{2}\)∠QPR
Proof:
In ∆PQR
∠PRS = ∠P + ∠Q (EAP)
In ∆TQR, ∠TRS = ∠T + ∠TQR (EAP)
\(\frac{1}{2}\)∠PRS = ∠T + \(\frac{1}{2}\)∠PQR
Multiplying both sides by 2
∠PRS = 2∠T+ ∠PQR
From (1) and (2) we get,
∠P + ∠Q = 2∠T + ∠PQR
∠P=2∠T
∠T= \(\frac{1}{2}\)∠P
∠QTR = \(\frac{1}{2}\)∠QPR
Proved.

MP Board Class 9th Maths Solutions

MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2

MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2

Question 1.
In Fig. given below, find the values of x and y and then showthat AB ∥ CD.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-1
Solution:
∠y = 130° (VOA’s)
x + 50° = 180° (LPA’)
∴ x = 180° – 50° = 130°
∠x and ∠y are alternate interior angles and are equal AB ∥ CD

Question 2.
In Fig. given below, if AB ∥ CD, CD ∥ EF and y : z = 3 : 7, find x.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-2
Solution:
Given
AB ∥ CD
CD ∥ EF
y : z = 3 : 7
∴ y = 3k
and z = 7k
To find, x
Solution:
AB ∥ EF and PQ is the transversal
x = z (A. I.A’s)
AB ∥ CD and PQ is the transversal
∴ x + y = 180° (C.I.A.’s)
z + y = 180° (∴ x = z)
7k + 3k = 180°
∴ k = 18°
y = 3 x 18° = 54°
2 = 7 x 18° = 126°
x = z = 126°

Question 3.
In Fig. given below, if AS ∥ CD, EF ⊥ CD and ∠GED = 126°, find ∠AGE, ∠GEF and ∠FGE.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-3
Solution:
Given
AB ∥ CD
EF ⊥ CD
To find
∠AGE, ∠GEF, ∠FGE
AB ∥ CD and GE is the transversal
∴ ∠AGE = ∠GED = 126°
∠AGE + ∠FGE = 180°
126° + ∠FGE = 180°
∠FGE = 54°
∠GED = ∠GEF + ∠FED
126° = ∠GEF + 90°
126° – 90° = ∠GEF
∠GEF = 36°

MP Board Solutions

Question 4.
In Fig. given below, if PQ ∥ ST, ∠PQR = 110° and ∠RST = 130°, find ∠QRS.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-4
Solution:
Given
PQ ∥ ST
∠PQR = 110°; ∠TSR = 130°
To find
∠QRS Construction.
Draw a line EF ∥ PQ passing through point R.
Calculation. PQ ∥ EF (by construction)
PQ ∥ ST (Given)
EF ∥ ST (lines ∥ to the same line are parallel to each other)
PQ ∥ EF and QR is the transversal
110° + ∠1 = 180° (CIA’s)
∴ ∠1 = 70°
ST ∥ EF and SR is the transversal
130° + ∠3 = 180° (CIA’s)
∠3 = 50°
∠1 + ∠2 + ∠3 = 180° (angles on the same line)
70° + ∠2 + 50° = 180°
∠2 = 180° – 120°
∴ ∠QRS = 60°

Question 5.
In Fig. given below, if AB ∥ CD, ∠APQ = 50° and ∠PRD = 127°, find x and y.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-5
Given
AB ∥ CD
∠APQ = 50°; ∠PRD = 127°
To find, x and y
Calculation:
AB ∥ CD and PQ is the transversal
∠APQ = x = 50° (AIA’s)
y + 50° = 127°
∴ y = 77°

Question 6.
In Fig. given below, PQ and RS are two mirrors placed parallel to each other. An incident ray AB strikes the mirror PQ at B, the reflected ray moves along the path BC and strikes the mirror RS at C and again reflects back along CD. Prove that AB ∥ CD.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-6
Solution:
Given
PQ ∥ RS
To prove:
AB ∥ CD
Construction:
Draw MB and NC normals at point B and C respectively.
Proof:
∠1 = ∠2
(Angle of incident = Angle of reflection)
and ∠3 = ∠4
∠ABC = 2∠2 and ∠BCD = 2∠3
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-7
MB ⊥ PQ and NC ⊥ RS
MB ∥ CN (Lines perpendicular to two parallel lines are parallel to each other)
MB ∥ CN and BC is the transversal
∠2 = ∠3 (AIA’s)
⇒ 2∠2 = 2∠3
(on multiplying both sides by 2)
⇒ ∠ABC = ∠BCD
∠ABC and ∠BCD are alternate interior angles and are equal AB ∥ CD

MP Board Solutions

Angle Sum Property of a Triangle:

1. Triangle:
A plane figure bounded by three line segments in a plane is called a triangle. A triangle has six parts –

  • Three sides – AB, BC and AC
  • Three angles – ∠A, ∠B and ∠C

MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-8
2. Median:
The median of a ∆ corresponding to a particular side is the line segment joining the midpoint of that side to its opposite vertex. In Fig., D, E and F are the midpoints of sides BC, AC and AB respectively. AD, BE and CF are the medians.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-9
3. Incentre of a triangle:
The incentre of a ∆ is the point of intersection of angle bisectors of the triangle. In Fig., OA, OB and OC are the angle bisectors of ∠A, ∠B and ∠C respectively. These angle bisectors intersect at point O. Therefore, point O is the incentre of ∆ABC.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-10
4. Circumcenter of a triangle:
The circumcenter of a triangle is the point of intersection of the perpendicular bisectors of the sides of the triangle. In Fig., O is the circumcenter of ∆ABC where the perpendicular bisectors of AB, BC and AC intersect.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-11

Theorem 1.
The sum of the angles of a triangle is 180°.
Given
ABC is a ∆ in which ∠1, ∠2 and ∠3 are angles.
To prove:
∠1 + ∠2 + ∠3 = 180°
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-12
Construction:
Draw a line PQ passing through point A parallel to BC.
Proof:
PQ is a line.
∠4 + ∠1 + ∠5 = 180° (angles on the same line) …..(i)
PQ ∥ BC and AB is the transversal
∴ ∠4 = ∠2 (AIA’s) …..(ii)
PQ ∥ BC and AC is the transversal
∴ ∠5 = ∠3 (AIA’s) …..(iii)
Putting ∠4 = ∠2 and ∠5 = ∠3 in (i), we get
∠2 + ∠1 + ∠3 = 180°
∴ ∠1 + ∠2 + ∠3 = 180°. Proved

MP Board Solutions

Exterior Angle Property:

Theorem 2.
If a side of a triangle is produced, then the exterior angle so formed is equal to the sum of the two opposite interior angles. This is also known as exterior angle property (EAP).
Given
ABC is a ∆ in which side BC is produced to point D.
To prove. ∠4 = ∠1 + ∠2
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-13
Proof:
In ∆ABC,
∠1 + ∠2 + ∠3 = 180° (ASP)
∠3 + ∠4 = 180° (LPA)
From (i) and (ii), we get
∠1 + ∠2 + ∠3 = ∠3,+ ∠4
∠1 + ∠2 = ∠4. Proved

Corollary

Theorem 3.
An exterior angle of a triangle is greater than either of the opposite interior angles.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-14
Given
In ∆ABC
∠4 = ∠1 + ∠2 (EAP)
∠4 > ∠1 and ∠4 > ∠2
Hence an exterior angle of A is greater than either of the opposite interior angle.

Lines And Angles:

Example 1.
In the Fig., AB divides ∠DAC in the ratio 1 : 3 and AB = DB. Find the value of y.
Solution:
Let ∠DAB = x and ∠BAC = 3x
In ∆ABD
AB = BD
∠ADB = ∠DAB = x
(∴ In a ∆ angles opposite to equal sides are equal)
∠ABC = x + x = 2x
(In a ∆ Exterior angle is equal to sum of two opp. interior angles) In ∆ABC
2x + 3x + y = 180° (ASP)
5x + y = 180° …..(i)
In ∆ADC
x + y = 180° (ASP)
y = 180° – X …..(ii)
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-15
Putting y = 180° – x in (i), we get
5x + 108° – x = 180°
4x + 108° = 180°
4x = 180° – 108°
= 72°
∴ x = \(\frac{72}{4}\) = 18°
Putting x = 18° in (ii), we get
y = 108° – 18° = 90°.

Example 2.
In the Fig., given below, find the value of x.
Solution:
Given
∠ABD = 100°
∠ACE = 115°
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-16
To find. x°
∠ABC + ∠ABD = 180° (LPA’s)
∠ABC + 100° = 180°
∠ABC = 180° – 100° = 80°
∠ACB + ∠ACE = 180°
∠ACB + 115° = 180°
∠ACB = 180° – 115° = 65°
Now, ∠A + ∠ABC + ∠ACE = 180° (ASP)
⇒ x° + 80° + 65° = 180°
⇒ x° + 145° = 180°
x° = 180° – 145° = 35°

MP Board Solutions

Example 3.
In Fig., PQ ⊥ PS, PQ ∥ SR, ∠SQR = 25° and ∠QRT = 65°.
Solution:
Given
∠SQR = 25°
∠QRT = 65°
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-17
To find x and y
In ∆SQR
∠QRT = ∠SQR + ∠QSR (FAP)
⇒ 65° = 25° + ∠QSR
⇒ 65° – 25° = ∠QSR
∠QSR = 40°
PQ ∥ SR and SQ is the transversal.
∴ ∠PQS = ∠QSR (AIA’s)
∴ x = 40°

Example 4.
In Fig., AM ⊥ L BC and AN is the bisector of ∠A. Find the measure of ∠MAN.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-18
Solution:
In ∆AMB
∠ABM + ∠AMB + ∠MAB = 180°
65° + 90° + ∠MAB = 180°
155° + ∠MAB = 180°
∠MAB = 180° – 155° = 25°
In ∆BAC
∠A + ∠B + ∠C = 180° (ASP)
∠A + 65° + 30° = 180°
∠A + 95° = 180°
∠A = 180° – 95° = 85°
∠MAN = ∠BAN – ∠MAB
= \(\frac{1}{2}\) ∠A – 25°
= \(\frac{85^{\circ}}{2}\) – 25 = \(\frac{85^{\circ}-50^{\circ}}{2}\)
∠MAN = \(\frac{35^{\circ}}{2}\) = 17.5°

Example 5.
If the sides of a triangle are produced in order, prove that sum of the exterior angles so formed is equal to four right angles.
Solution:
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-19
∠EAB = ∠2 + ∠3 (EAP) …..(i)
∠FBC = ∠1 + ∠3 (EAP) …..(ii)
∠ACD = ∠1 + ∠2 (EAP) …(iii)
Adding (i), (ii) and (iii), we get
∠EAB + ∠FBC + ∠ACD = ∠2 + ∠3 + ∠1 + ∠3 + ∠1 + ∠2
= 2(∠1 + ∠2 + ∠3) = 2 x 180° = 360°. Proved

Example 6.
Bisectors of angles B and C of a triangle ABC intersect each other at the point O. Prove that ∠BOC = 90° + \(\frac{1}{2}\) ∠A.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-20
Solution:
Given
∠1 = \(\frac{1}{2}\) ∠ABC
⇒ ∠ABC = 2∠1
∠2 = \(\frac{1}{2}\) ∠ACB
⇒ ∠ACB = 2∠2
To prove:
∠BOC = 90° + \(\frac{1}{2}\) ∠A
Proof:
In ∆BOC ∠O + ∠1 + ∠2 = 180°
∠1 + ∠2 = 180° – ∠O …..(i)
In ∆ABC
∠A + ∠ABC + ∠ACB = 180°
∠A + 2∠1 + 2∠2 = 180°
2∠1 + 2∠2 = 180° – ∠A
2(∠1 + ∠2) = 180° – ∠A
∠1 + ∠2 = \(\frac{180^{\circ}-\angle A}{2}\) = 90° – \(\frac{\angle A}{2}\) …..(ii)
From (i) and (ii) we get
180° – ∠O = 90° – \(\frac{\angle A}{2}\)
180° – 90° + \(\frac{\angle A}{2}\) = ∠O
90° + \(\frac{\angle A}{2}\) = ∠O
∴ ∠BOC = 90° + \(\frac{\angle A}{2}\)

MP Board Solutions

Example 7.
In Fig. show that ∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360°
Solution:
In ∆ACE
∠A + ∠C + ∠E = 180° (ASP) …..(i)
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-21
In ABDF
∠B + ∠D + ∠F = 180° (ASP) …..(ii)
Adding (i) and (ii), we get
∠A + ∠C + ∠E + ∠B + ∠D + ∠F = 180° + 180°
∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360°

Example 8.
In Fig., ∠Q > ∠R, PA is the bisector of ∠QPR and PM ⊥ QR. Prove that ∠APM = \(\frac{1}{2}\) (∠Q – ∠R)
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-22
Solution:
Given
∠Q > ∠R
∠QPA = ∠RPA
PM ⊥ QR
To prove:
∠APM = \(\frac{1}{2}\) (∠Q – ∠R)
Proof:
In ∆PMQ
∠Q + ∠QPM + ∠M= 180° (ASP)
∠Q + ∠QPA – ∠APM + 90° = 180°
(∴ ∠QPM = ∠QPA – ∠APM)
∠Q + ∠QPA – ∠APM = 180° – 90°
∠Q + ∠QPA – ∠APM = 90°
∠Q + ∠QPA – ∠APM = 90° …..(i)
In ∆PMR
∠R + ∠RPM + ∠PMR = 180°
∠R + ∠RPA + ∠APM + 90° = 180°
(∴ ∠RPM = ∠RPA + ∠APM)
∠R + ∠QPA + ∠APM = 180° – 90°
(∴ ∠RPA = ∠QPA)
∠R + ∠QPA + ∠APM = 90° …..(ii)
From (i) and (ii), we get
∠Q + ∠QPA – ∠APM = ∠R + ∠QPA + ∠APM
∠Q – ∠R = ∠APM – ∠QPA + ∠QPA + ∠APM
∠Q – ∠R = 2∠APM
∠APM = \(\frac{1}{2}\) (∠Q – ∠R) Proved

Example 9.
In fig., AB ∥ DC, ∠BDC = 30° and ∠BAD = 80°, find x, y and z.
Solution:
AB ∥ DC and BD is the transversal.
x = 30° (AIA’s)
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.2 img-23
In ∆ABD
x + y + 80° = 180° (ASP)
30° + y + 80° = 180°
110° + y = 180°
∴ y = 180° – 110° = 70°
y – 30° = 70 – 30° = 40°
In ∆BCD
30° + 40° + z = 180° (ASP)
[∴ y – 30° = 40°]
70° + z = 180°
∴ z = 180° – 70° = 110°

MP Board Class 9th Maths Solutions

MP Board Class 9th Science Solutions Chapter 5 The Fundamental Unit of Life

MP Board Class 9th Science Solutions Chapter 5 The Fundamental Unit of Life

The Fundamental Unit of Life Intext Questions

The Fundamental Unit of Life Intext Questions Page No. 59

Question 1.
Who discovered cells and how?
Answer:
Robert Hooke (1665), by chance observed a slice of cork through a self designed microscope. He observed that it contained many little compartments, like a honey comb, which he named as cells. However, Leeuwenhoek (1674) discovered the free living cells in pond water for the first time, by his improved microscope.

MP Board Solutions

Question 2.
Why is the cell called the structural and functional unit of life?
Answer:
The body of all organisms consists of one or many cells. Therefore, cell is called the structural unit of life. All processes associated with life such as respiration, digestion, excretion etc. are performed by cell. So, cell is also called as functional unit of life.

The Fundamental Unit of Life Intext Questions Page No. 61

Question 1.
How do substances like CO2 and water move in and out of the cell? Discuss.
Answer:
When concentration of CO2 is more inside the cell than outside, CO2 diffuses from the cell to outside of cell. If CO2 concentration inside the cell is less, CO2 moves inside the cell from outside. The water move in and out of the cell by the process of osmosis. Osmosis is the passage of water from a region of high water concentration through semi – permeable membrane (cell membrane) to a region of low concentration of water.

Question 2.
Why is the plasma membrane called a selectively permeable membrane?
Answer:
Plasma membrane permits the entry and exit of some materials in and out of the cell. It also prevents movement of some other materials. So, it is called selectively permeable membrane.

The Fundamental Unit of Life Intext Questions Page No. 63

Question 1.
Fill in the gaps in the following table illustrating differences between prokaryotic and eukaryotic cells.

Prokaryotic CellEukaryotic Ceil
1. Size: Generally, small (1 – 10 μm). (1 μm = 10-6m).1. Size: Generally, large (5 – 100 μm).
2. Nuclear region: ………………
……………………………………………..
…………………… and known as …………. .
2. Nuclear region: Well – defined and surrounded by a nuclear membrane.
3. Chromosome: Single.3. More than one chromosome.
4. Membrane – bound cell organelles absent.4. ………………………………………….. .

Answer:
Prokaryotic cell:
2. Nuclear region is poorly defined due to absence of a nuclear membrane and is known as nucleoid.

Eukaryotic cell:
4. Membrane bound cell organelles are present.

The Fundamental Unit of Life Intext Questions Page No. 65

Question 1.
Can you name the two organelles we have studied that contain their own genetic material?
Answer:

  1. Mitochondria and
  2. Plastid (chloroplast).

Question 2.
If the organisation of a cell is destroyed due to some physical or chemical influence, what will happen?
Answer:
Each cell has got certain specific cell organelles. Each cell organelle performs a special function.
e.g.,

  • making of new material, removal of waste from the cell, release of energy etc. If the organization of a cell is destroyed, the functioning of the cell organelles will be disturbed, control of the nucleus will be lost. Ultimately, cell will die.

Question 3.
Why are lysosomes known as suicide bags?
Answer:
Lysosome is a membrane bound bag – like cell organelle which contains powerful enzymes. If lysosome bursts, its enzymes eat up (digest) other organelles of its own cell. Therefore, they are known as ‘suicide bags’.

MP Board Solutions

Question 4.
Where are proteins synthesised inside the cell?
Answer:
Ribosomes.

The Fundamental Unit of Life NCERT Textbook Exercises

Question 1.
Make a comparison and write down ways in which plant cells are different from animal cells?
Answer:
Difference between plant cell and animal cell is given below:
MP Board Class 9th Science Solutions Chapter 5 The Fundamental Unit of Life 1

Plant CellAnimal Cell
1. The outermost covering of the plant cell is the cell wall which is formed of cellulose.1. The outermost covering is the plasma membrane.
2. Plastids (e.g., chloroplast) present.2. Plastids absent.
3. Large vacuole present.3. No or small vacuoles are present.
4.  Centrioles are absent but plastids caps are present.4. Centrioles are present within centrosome.

Question 2.
How is a prokaryotic cell different from a eukaryotic cell?
Answer:

Prokaryotic CellEukaryotic Cell
1. Cell size is generally small. (1 – 10 mm).1. Cell is generally large. (5 – 100 mm).
2. Nuclear region is called nucleoid is not surrounded by a nuclear membrane.2. Nuclear material is surrounded by a nuclear membrane.
3. Only a single chromosome is present.3. More than one chromosome are present.
4. Nucleolus is absent.4. Nucleolus is present.
5. Membrane bound cell organelles are absent.5. Cell organelles bounded by membrane are present.
6. Cell division by fission or budding (no mitosis).6. Cell division mitotic or meiotic.

Question 3.
What would happen if the plasma membrane ruptures or breaks down?
Answer:
Plasma membrane regulates the movement of substances in and out of the cell. Due to rupture of plasma membrane, there will be no regulation of the movement of molecules. Secondly, contents of the cell may leak out. Because of these two reasons cell will die.

MP Board Solutions

Question 4.
What would happen to the life of a cell if there was no Golgi apparatus?
Answer:
Golgi apparatus is connected to ER. It collects simpler molecules from ER and convert them into more complex molecules. These are then packaged in small vesicles and are stored or transported inside or outside the cell. If Golgi apparatus is not present in the cell, all the above processes of modification, storage and tRansportation will not be possible.

Golgi apparatus is also involved in the formation of lysosomes. If there was no Golgi apparatus in the cell, lysosomes would not be formed and hence, foreign materials like bacteria could easily invade and destroy the cell.

Question 5.
Which organelle is known as the powerhouse of the cell? Why?
Answer:
Mitochondria are known as ‘Power House’ of the cell. They are said so because, the energy required for various life activities is released by mitochondria in the form of ATP molecules. The body uses energy stored in ATP for synthesis of new compounds and for mechanical work. As ATP instantly provide energy, they are called energy currency of the cell.

Question 6.
Where do the lipids and proteins constituting the cell membrane get synthesised?
Answer:

  1. Rough Endoplasmic Reticulum (RER) synthesizes proteins constituting cell membrane.
  2. Smooth Endoplasmic Reticulum (SER) synthesizes and secretes lipids constituting cell membrane.

Question 7.
How does an Amoeba obtain its food?
Answer:
Amoeba has flexible cell membrane. It enables Amoeba to engulf in food by the process called endocytosis.

Question 8.
What is osmosis?
Answer:
The passage of water from a region of its high concentration through a semipermeable membrane to a region of low water concentration is known as osmosis.

Question 9.
Carry out the following osmosis experiment:
Take four peeled potato halves and scoop each one out to make potato cups. One of these potato cups should be made from a boiled potato. Put each potato cup in a trough containing water. Now,
(a) Keep cup A empty.
(b) Put one teaspoon sugar in cup B.
(c) Put one teaspoon salt in cup C.
(d) Put one teaspoon sugar in the boiled potato cup D.

Keep these for two hours. Then observe the four potato cups and answer the following:

  1. Explain why water gathers in the hollowed portion of B and C?
  2. Why is potato A necessary for this experiment ?
  3. Explain why water does not gather in the hollowed out portions of A and D.

Answer:

  1. Water gathers in the hollowed portion of B and C because:
    • Living plasma membrane of potato cells act as semipermeable membrane.
    • There is higher concentration of water in trough than the hollowed portion of B and C.
    • So, water by the process of osmosis moves into hollowed portion of potato cups B and C.
  2. Potato cup A is kept empty to act as control set – up.
    • As the potato cup A, is empty, water does not gather in hollowed out portions of A.
    • In the potato cup D, the potato cell membrane lost quality of semi – permeability due to boiling. So, no water movement occurs from the trough into the potato cup D.

The Fundamental Unit of Life Additional Questions

The Fundamental Unit of Life Multiple Choice Questions

Question 1.
Who coined the term protoplasm for the fluid substance of the cell?
(a) J.E. Purkinje
(b) Robert Brown
(c) W. Flemming
(d) Robert Hooke.
Answer:
(a) J.E. Purkinje

Question 2.
Ribosomes are the centre for __________.
(a) Fat synthesis
(b) Protein synthesis
(c) Starch synthesis
(d) Sugar synthesis.
Answer:
(b) Protein synthesis

Question 3.
The complete break down of glucose in presence of oxygen in a cell takes place in __________.
(a) Mitochondria
(b) Ribosome
(c) Chloroplast
(d) None of these.
Answer:
(a) Mitochondria

Question 4.
Lysosomes contains __________.
(a) Fats
(b) Secretory glycoproteins
(c) Hydrolytic enzymes
(d) RNA.
Answer:
(c) Hydrolytic enzymes

MP Board Solutions

Question 5.
Plant cells have large vacuoles each surrounded by a membrane known as __________.
(a) Plasma membrane
(b) Cell wall
(c) Leucoplast
(d) Tonoplast.
Answer:
(d) Tonoplast

Question 6.
The process of selective movement of substances through semi – permeable membrane is called?
(a) Osmosis
(b) Diffusion
(c) Plasmolysis
(d) Imbibition.
Answer:
(a) Osmosis

Question 7.
What makes to withstand greater changes in the surrounding medium in animal cell?
(a) Plasma membrane
(b) Cell wall
(c) Vacuoles
(d) Plastids.
Answer:
(b) Cell wall

Question 8.
When an animal cell is placed in hypotonic solution, it __________.
(a) Swells up
(b) Shows plasmolysis
(c) Bursts due to over swelling
(d) Shows crenation.
Answer:
(c) Bursts due to over swelling

Question 9.
Which of the following maintains the basic structure (shape) of the plant cell after shrinkage of the cell content during plasmolysis?
(a) Plasma membrane
(b) Vacuole
(c) Plastids
(d) Mitochondria.
Answer:
(d) Mitochondria.

Question 10.
Plasmolysis occurs due to __________.
(a) Endosmosis
(b) Exosmosis
(c) Absorption
(d) None of these.
Answer:
(b) Exosmosis

Question 11.
Who among the following scientists coined the term ‘cell’?
(a) Leeuwenhoek
(b) J.E. Purkinje
(c) Robert Hooke
(d) Robert Brown.
Answer:
(c) Robert Hooke

Question 12.
Which is the largest cell in human body?
(a) Muscle cell
(b) Nerve cell
(c) Kidney cell
(d) Liver cell.
Answer:
(b) Nerve cell

Question 13.
Iodine solution is used to __________.
(a) Stain onion peel cells
(b) Stain human cheek cells
(c) Mount onion peel cells
(d) Mount human cheek cells.
Answer:
(a) Stain onion peel cells

Question 14.
The barrier between the cytoplasm and the outer environment in an animal cell is __________.
(a) Tonoplast
(b) Nuclear membrane
(c) Cell wall
(d) Plasma membrane.
Answer:
(d) Plasma membrane.

Question 15.
The power house of a cell is known as __________.
(a) Golgi apparatus
(b) Chloroplast
(c) Mitochondrion
(d) Vacuole.
Answer:
(c) Mitochondrion

Question 16.
Which of the following organelles possesses its own DNA and Ribosomes?
(a) Mitochondria
(b) Lysosomes
(c) Golgi apparatus
(d) Endoplasmic reticulum.
Answer:
(a) Mitochondria

MP Board Solutions

Question 17.
The functions of which of die organelle include the storage, modification and packaging of products in vesicles:
(a) Lysosome
(b) Vacuoles
(c) Golgi apparatus
(d) SER.
Answer:
(c) Golgi apparatus

Question 18.
Which organelles, like mitochondria, have their own DNA and ribosomes?
(a) Golgi apparatus
(b) Vacuoles
(c) Endoplasmic reticulum
(d) Plastids.
Answer:
(d) Plastids.

Question 19.
Mitochondria and plastids are able to synthesis some of their own proteins because they have?
(a) DNA and nucleolus
(b) RNA and lysosomes
(c) DNA and ribosomes
(d) RNA and ribosomes.
Answer:
(c) DNA and ribosomes

Question 20.
Stroma is present in __________.
(a) Mitochondria
(b) Leucoplast
(c) Endoplasmic reticulum
(d) Lysosomes.
Answer:
(b) Leucoplast

Question 21.
Which of the following cell organelle is called suicide bag of a cell?
(a) Mitochondria
(b) Lysosome
(c) Plastids
(d) Golgi apparatus.
Answer:
(b) Lysosome

Question 22.
Which of the following molecules is known as the energy currency of the cell?
(a) RNA
(b) DNA
(c) ATP
(d) Aminoacid.
Answer:
(c) ATP

Question 23.
ATP stands for __________.
(a) Adenosine triphosphate
(b) Amino triphosphate
(c) Amino triglycerophosphate
(d) Adeninetri – phosphoglyceride.
Answer:
(a) Adenosine triphosphate

Question 24.
Which cell organelle is involved in the formation of lysosomes?
(a) Mitochondria
(b) Golgi apparatus
(c) Plastids
(d) Endoplasmic reticulum.
Answer:
(d) Endoplasmic reticulum.

MP Board Solutions

Question 25.
Which cell organelle plays a crucial role in detoxifying many poisons and drugs?
(a) RER
(b) SER
(c) RNA
(d) DNA.
Answer:
(b) SER

The Fundamental Unit of Life Very Short Answer Type Questions

Question 1.
Which is the longest flowering plant cell?
Answer:
The fibre.

Question 2.
Which is the longest animal cell?
Answer:
The nerve cell.

Question 3.
Name any two single celled animals.
Answer:
Amoeba, paramoecium and euglena etc.

Question 4.
Which is the largest animal cell?
Answer:
An ostrich egg.

Question 5.
Which is the smallest animal cell?
Answer:
Pleuro Pneumonia like organisms (PPLO).

Question 6.
What are cell organelles?
Answer:
The functional units of cell.

Question 7.
Name the process involved in the movement of O2 in and out of the cell.
Answer:
Diffusion.

Question 8.
Which is the outer most covering of the plant cell?
Answer:
Cell wall.

MP Board Solutions

Question 9.
Name is the outer most covering of an animal cell.
Answer:
Plasma membrane.

Question 10.
Which is the largest plant cell?
Answer:
Acetabalaria.

Question 11.
Is plasma membrane living or dead?
Answer:
Living.

Question 12.
Name the process involved in the movement of water from outside into the cell.
Answer:
Osmosis.

Question 13.
By which process CO2 and water (H2O) move in and out of the cell?
Answer:
CO2 by diffusion and water (H2O) by osmosis.

Question 14.
Is cell wall living or dead?
Answer:
Dead.

Question 15.
Name the control centre of the cell.
Answer:
Nucleus is the control centre of the cell.

Question 16.
What is the function of ribosomes?
Answer:
Ribosomes are involved in protein synthesis.

Question 17.
Name the site of photosynthesis.
Answer:
Chloroplast.

Question 18.
Which organelles are called

  1. powerhouse of cell
  2. suicide bags
  3. Kitchen of the cell?

Answer:

  1. Mitochondria
  2. Lysosome and
  3. Chloroplasts.

Question 19.
Which organelle makes endoplasmic reticulum rough?
Answer:
Ribosomes.

Question 20.
Name the scientists who formed primitive microscope in the 17th century.
Answer:
Robert Hooke (1665) formed primitive microscope.

Question 21.
Name the plastid which stores starch, oils and protein granules.
Answer:
Leucoplast.

Question 22.
Name the main substance which nucleolus consists of.
Answer:
Nucleolus, found in nucleus, mainly consists of RNA (Ribonucleic acids).

Question 23.
What are genes?
Answer:
Genes are segments of DNA present linearly on chromosomes. They are the functional units of chromosomes.

MP Board Solutions

Question 24.
What is cytoplasm?
Answer:
The cytoplasm is the fluid content inside the plasma membrane. It contains many specialised cell organelles.

Question 25.
Where are centrioles found?
Answer:
Centrioles are found in centrosome of an animal cell only.

The Fundamental Unit of Life Short Answer Type Questions

Question 1.
Define diffusion.
Answer:
The spontaneous movement of a substance from a region of its high concentration to Che region where its concentration is low, is called diffusion.

Question 2.
Observe the following diagram and answer the questions given below:
MP Board Class 9th Science Solutions Chapter 5 The Fundamental Unit of Life 2

  1. What is the name of this instrument?
  2. What are the names of the parts marked as 1, 2 and 3 ?
  3. There are two objectives, one is marked as 45X and second one as 10X. Under which objective you would first view the onion peel cells ?

Answer:

  1. Compound microscope.
    • Eye piece
    • Fine adjustment screw
    • Coarse adjustment screw.
  2. Under 10X objective (low power objective).

Question 3.
What is the function of cell wall and plasma membrane?
Answer:

  1. Cell wall: Gives rigidity, shape and protection to plant cell.
  2. Cell membrane: Allows only selected materials to move in and out of the cell.

Question 4.
Define osmosis.
Answer:
The passage of water from a region of higher concentration to a region of lower concentration through a semipermeable membrane is called osmosis.

Question 5.
What is chromatin material?
Answer:
Inside the nucleus a tangled mass of thread – like structure is present which is called chromatin material. It mainly consists of DNA (deoxyribonucleic acid) and protein.

Question 6.
What is the function of centrosome? Name the structure found in plant cell to do the same function.
Answer:
Centrosome helps in cell division in animal cells. The polar caps perform the same function in a plant cell.

MP Board Solutions

Question 7.
What is the function of Mitochondria?
Answer:
In mitochondria, digested food is broken down to release energy. This released energy is stored in the form of ATP.

Question 8.
What is plasmolysis?
Answer:
When a living plant cell loses water through osmosis, there is shrinkage or contraction of the protoplasm away from the cell wall. This phenomenon is called plasmolysis.

Question 9.
What is endocytosis? Give one example.
Answer:
The process in which a cell due to flexible cell membrane engulfs in food and other material from its external environment is known as endocytosis. Amoeba acquires its food through this process.

Question 10.
Who discovered cells in living organisms? Give an example of unicellular organism.
Answer:
Leeuwenhoek (1674) observed free living cells in pond water for the first time. Example of unicellular organisms: Amoeba, chlamydomonas, paramoecium, bacteria etc.

Question 11.
What is the location and main component of cell wall?
Answer:
Cell wall is a rigid structure found outside the plasma membrane of the plant cells. Cellulose (a fibrous polysaccharide) is the main constituent of the cell wall.

Question 12.
What are chromosomes?
Answer:
Chromosomes are rod – shaped structures found in the nucleus of the cell. Chromosome contain information for inheritance of features from parents to next generation in the form of DNA molecule.

Question 13.
What is a eukaryotic cell?
Answer:
A cell that has a definite nucleus with nuclear membrane and also contains membrane bound organelles in its cytoplasm is called eukaryotic cell.

Question 14.
What is nucleoid?
Answer:
In prokaryotes, due to absence of nuclear membrane, nuclear region of the cell is poorly defined. This kind of undefined nuclear region containing only nucleic acid is called a nucleoid.

Question 15.
Give two examples of prokaryotic organisms.
Answer:
Bacteria and cyanobacteria (blue green algae)
e.g.,

  • Nostoc are prokaryotic unicellular organisms.

Question 16.
What is a prokaryotic cell?
Answer:
A cell which lacks nuclear membrane, contains a single chromosome and also lacks membrane bound organelles is called prokaryotic cell.

Question 17.
What is cytoplasm?
Answer:
The part of protoplasm which remains after excluding nucleus, is known as cytoplasm. Cytoplasm contains an aggregate molecules of various chemicals and cell organelles. Most of the biochemical reactions such as protein synthesis, release of energy etc. take place in cytoplasm or organelles present in the cytoplasm.

Question 18.
Write three main points of cell theory as expressed by Schleiden, Schwann and Virchow.
Answer:
Cell Theory: Schleiden and Schwann proposed that:

  1. all the plants and animals are composed of cells and that
  2. the cell is the basic unit of life. Later on, Virchow added that
  3. all cells arise from pre – existing cells.

Question 19.
List four major functions of a cell.
Answer:
Functions of Cell:

  1. Synthesis of substances.
  2. Digestion (lysis) of substances.
  3. Generation of energy for vital functions.
  4. Secretion.

Question 20.
What is the function of an endoplasmic reticulum?
Answer:
Endoplasmic reticulum helps in the transport of substances between various regions of the cytoplasm or between the cytoplasm and the nucleus. Endoplasmic reticulum also functions as a cytoplasmic framework providing a surface for some of the biochemical activities of the cell. In vertebrates, SER present in the liver cells also plays an important role in detoxifying poisons and drugs.

MP Board Solutions

Question 21.
What is lacking in a virus which makes it dependent on a living cell to multiply?
Answer:
Viruses lack selectively .permeable plasma membrane and cell organelles. Thus, they lack a basic structural organisation to perform various life processes effectively and in their own way. After entering a living cell, a virus utilises its own genetic material and machinery of host cell to multiply.

Question 22.
Write one function of each:

  1. rough endoplasmic reticulum and
  2. smooth endoplasmic reticulum.

Answer:

  1. Rough endoplasmic reticulum (RER) has ribosomes on its surface for synthesizing proteins.
  2. Smooth endoplasmic reticulum (SER (without ribosomes) secrete lipids or fats. Some of the proteins and lipids help in building cell membranes.

Question 23.
What is membrane biogenesis?
Answer:
The SER (Smooth Endoplasmic Reticulum) synthesises certain proteins and lipids which help in building the plasma membrane. This building of plasma membrane by SER products is called membrane biogenesis.

Question 24.
What are the leucoplasts and their functions?
Answer:

  1. Leucoplasts: These are colourless plastids which do not contain any pigment.
  2. Function: Leucoplasts are involved in formation and storage of starch, oil drops and proteins granules.
    • For example: Amyloplasts found in potato tuber store starch.

Question 25.
Why mitochondria are referred to as strange organelles?
Answer:
Mitochondria have their own DNA and ribosomes. Therefore, they can make some of their own proteins. So, sometimes they are referred as ‘strange organelles’. On the other hand, they help in cellular respiration and formation of ATP.

Question 26.
Expand the term ATP. What is use of ATP?
Answer:
ATP stands for Adenosine triphosphate.
Use:
ATP molecules are rich in chemical energy. The body cells use the energy stored in ATP for synthesis of new chemical compounds, their transport and for mechanical work done by cells / tissues.

Question 27.
What are plastids?
Answer:
Plastids are double membrane bounded structures which are found in plant cells only. Inside the plastid, a fluid material called stroma is present. In stroma, numerous membrane layers remain scattered. Plastids like mitochondria do not have cristae. They also have extra – nuclear DNA. There are two types of plastids: Leucoplasts and Chromoplasts.

Question 28.
What type of enzymes are present in the lysosomes? What is their functions? Which organelles membrane manufacture these enzymes?
Answer:

  1. Lysosomes contain powerful digestive enzymes capable of breaking down all organic material.
  2. Lysosomes help to keep the cell clean by digesting worn out cell organelles and foreign material such as bacteria or food.
  3. RER (Rough Endoplasmic Reticulum) makes the digestive enzymes present in the lysosomes.

MP Board Solutions

Question 29.
What are the three functional regions of cell?
Answer:
The functional regions of all cells are:

  1. The plasma membrane
  2. The nucleus and
  3. The cytoplasm.

Question 30.
What are vacuoles?
Answer:
Vacuoles are fluid – filled structures surrounded by a membrane known as tonoplast. The fluid in the vacuoles is called cell sap. In animal cells either they are absent or are very small in size but can be many. In most plant cells, vacuole is big and centrally placed which provides turgidity and rigidity to cells.

The Fundamental Unit of Life Long Answer Type Questions

Question 1.
What will happen if an animal or plant cell is put into a solution of sugar and water?
Answer:
The following three things could happen:

  1. If the solution surrounding the cell is very dilute than cytoplasm, the water will move into the cell, i.e., the cell will gain water.
  2. If the solution has exactly similar water concentration as that of cytoplasm of cell, there will be no net movement of water across the cell membrane, i.e., no gain or loss of water from the cell.
  3. If the medium (solution) has a lower concentration of water than the cell i.e., the solution is concentrated, the cell will lose water by osmosis.

Question 2.
What will happen when

  1. an egg without shell is placed in concentrated salt solution for 5 minutes?
  2. an egg without shell is placed in pure I distilled water for 5 minutes? Give reason in brief.

Answer:

  1. The egg loses water and shrinks.
    • Reason: The egg membrane acts as semipermeable membrane. The concentrated salt solution present outside the egg is hypertonic so the egg loses water by osmosis.
  2. The egg gains water and swells.
    • Reason: The pure water is hypotonic (dilute) than egg cells, so water from the outside moves into the egg cells by osmosis. The gain of water results in swelling of egg.

Question 3.
What is the significance of cell wall in plant cell?
Answer:
It performs the following functions in the plant cell:

  1. It gives a definite shape to the cell.
  2. It provides rigidity and strength to the cell.
  3. It protects the plasma membrane and inner cell organelles by bounding the cell from outside.
  4. It allows cells of plants, fungi and bacteria to withstand very dilute external media without bursting.
  5. It helps in transport of the material in and out of the cell.
  6. Cell wall maintains the shape of the cell when cytoplasm shrinks away from cell wall during plasmolysis.
  7. It prevents desiccation of cells.

Question 4.
Explain the structure of nucleus.
Answer:
Nucleus is the control centre of the cell. It is covered by a double layered envelope called nuclear membrane. The nuclear membrane has pores which allow the transfer of material from inside the nucleus to cytoplasm. Inside the nuclear membrane an entangled mass of thread – like structures is present. This is called chromatin material (see Fig. given).
MP Board Class 9th Science Solutions Chapter 5 The Fundamental Unit of Life 3
The chromatin material mainly formed of DNA (deoxyribonucleic acid) and proteins. When a cell starts to divide, chromatin material condenses into rod – shaped structures called chromosomes. The chromosomes contain stretches of DNA which are called genes.

Question 5.
Name the cell organelle which are known as:

  1. Control centre of the cell.
  2. Demolition squads / suicidal bags of the cell.
  3. Export firms.
  4. Power house of the cell.
  5. Kitchen of the cell.
  6. Internal transport system.

Answer:

  1. Nucleus.
  2. Lysosomes.
  3. Golgi bodies.
  4. Mitochondria.
  5. Chloroplast.
  6. Endoplasmic reticulum.

Question 6.
What is endoplasmic reticulum? Write its main functions.
Answer:
Endoplasmic reticulum. It is a membranous network. enclosing a fluid – filled lumen. Its main functions are:

  1. Synthesis of proteins (Rough ER).
  2. Synthesis of lipids and other metabolic products and their secretion (SER).
  3. Helps in formation of cell plate and nuclear membrane during cell division.
  4. ER also produces substance for new cellular parts (especially cell membrane).
  5. ER provides internal support (Mechanical support) to the colloidal cytoplasmic matrix of the cell.
    MP Board Class 9th Science Solutions Chapter 5 The Fundamental Unit of Life 4

Question 7.
(a) What would happen to the life of a cell if there was no Golgi apparatus?
(b) Which cell organelle detoxifies poisons and drugs in the liver of vertebrates?
Answer:
(a) Golgi apparatus is connected to ER. It collects simpler molecules from ER and convert them into more complex molecules. These re then packaged in small vesicles and are stored or transported inside or outside the cell. If Golgi apparatus is not present in the cell, all the above processes of modification, storage and transportation will not be possible. Golgi apparatus is also involved in the formation of lysosomes. If there was no Golgi apparatus in the cell, lysosomes would not hr formed and hence foreign materials like bacteria could easily invade and destroy the cell.

(b) Try yourself.

Question 8.
Briefly explain the structure of Golgi apparatus.
Answer:
Golgi apparatus is also known as Golgi body or Golgi complex. It consists of a set of smooth, flattened membranous sac like structures called cisternae. These are placed one above the other (staked) in parallel rows.
MP Board Class 9th Science Solutions Chapter 5 The Fundamental Unit of Life 5
On the outer edge of cisternae (stacks of membrane), tubules and vesicles (small sacs) are present. In plant cells, the Golgi apparatus consists of many unconnected units called dictyosomes.

Question 9.
What are the functions of Golgi apparatus?
Answer:
Functions of Golgi apparatus:

  1. Golgi apparatus is the secretory organelle of the cell. It packages and dispatches the material synthesized in the cell to intracellular (plasma membrane and lysosomes) and extracellular targets.
  2. Golgi complex is also involved in the formation of lysosomes.
  3. Golgi apparatus is also involved in the synthesis of many substances such as polysaccharides, glycoproteins etc.

Question 10.
What are lysosomes?
Answer:
Lysosomes: These are membrane bound vesicles which bud off from Golgi apparatus. They contain powerful enzymes capable of digesting or breaking down all organic material. The enzymes present in lysosome are synthesised on RER.

The membrane that bound lysosomes does not allow the enclosed enzymes to pass freely into the cell cytoplasm. Thus, protects the cell from autolysis (self – dissolution or breakdown). They are absent in RBCs and a few plant cells
for example:

  • yeast
  • fungi and
  • green algae.

MP Board Solutions

Question 11.
Describe the role played by the Lysosomes. Why are these termed as suicidal bags? How do they perform their function?
Answer:
Functions of Lysosomes:

  1. Extracellular digestion: Sometimes lysosome enzymes are released outside the cell to break down extracellular material.
  2. Digestion of foreign material: Lysosomes also destroy any foreign material which enters inside the cell such as bacteria.
  3. Cellular digestion: In damaged cells, ageing cells or dead cells lysosomes get ruptured and enzymes are released. These enzymes digest their own cell.

Lysosomes contain about 40 hydrolytic enzymes. When the cell gets damaged, lysosomes burst and their enzymes digest their own cell. So, lysosomes are called ‘suicide bags’. Foreign materials entering the cell, such as bacteria or food, as well as old organelles end up in the lysosomes, which break them up into small pieces.

Question 12.
Describe the structure of mitochondria.
Answer:
Mitochondria are rod – shaped cell organelle found in the cytoplasm. Each mitochondrion (singular of mitochondria) is a double membrane bound structure. The outer membrane of mitochondrion is smooth. But the inner membrane of the mitochondrion is folded inwardly, into the matrix of mitochondrion forming finger – like projections.

MP Board Class 9th Science Solutions Chapter 5 The Fundamental Unit of Life 6
The inward finger – like projections of inner membrane are called cristae. Cristae greatly increase the surface area of the inner membrane. Mitochondria contain extra – nuclear DNA.

Question 13.
What are chromoplasts and leucoplasts? Give an example of chromoplasts which has green pigment.
Answer:
Chromoplasts are coloured plastids i.e., they may contain pigment of different colours. For example, Blue green chromoplasts found in blue green algae.
MP Board Class 9th Science Solutions Chapter 5 The Fundamental Unit of Life 7
The most important chromoplasts are chloroplasts which contain green pigment, known as chlorophyll. Chloroplasts are very important for photosynthesis. Other non – green chromoplasts are responsible for characteristic colour of flowers and fruits.

  1. Leucoplast: These are colourless plastids which do not contain any pigment.
  2. Function: Leucoplasts are involved in formation and storage of starch, oil drops and proteins granules.
    • For example: Amyloplasts found in potato tuber store starch.

Question 14.
(a) Name the organelle which provides turgidity and rigidity to the plant cell. Name any two substances which are present in it.
(b) How are they useful in unicellular organisms?
Answer:
(a) Plant cells have big vacuoles full of cell sap that provide them turgidity and rigidity. Plant vacuoles store amino acids, sugars, various organic acids and some proteins.
(b) In unicellular organisms they may serve the following purposes:

  1. Forming food vacuoles: In single celled organisms like Amoeba, the food vacuole contains the food items that the Amoeba has ingested. The food items are digested by the enzymes later on.
  2. Removal of excess water and wastes: In some unicellular organisms, specialised vacuoles play important roles in expelling excess water and some wastes from the cell.

The Fundamental Unit of Life Higher Order Thinking Skills (HOTS)

Question 1.
When we take bath for long time, the skin of our fingers shrink. Give reason.
Answer:
The soaps used are hypertonic as compared to the osmotic concentration of our skin. Exosmosis in skin cells occurs resulting in shrinking of skin of fingers.

MP Board Solutions

Question 2.
‘The Golgi apparatus is also called the secretary organelle of the cell’. Why?
Answer:
Golgi apparatus is called so as its main function is secretion. The secretary proteins and lipids are packed and released on the surface by Golgi via exocytosis.

The Fundamental Unit of Life Value Based Questions

Question 1.
Manjeet is a five year old boy who joined the swimming classes. After the first class, he was worried when he saw his wrinkled fingers. He asked his elder brother about the wrinkling and shrinking of his fingers. His brother explained Manjeet, why it was so.

  1. Why did the fingers wrinkle after swimming?
  2. What caused the shrinking / wrinkling of fingers?
  3. What value of Manjeet is seen in the above case?

Answer:

  1. Fingers wrinkled because the cells of the skin lost some water.
  2. This happened because of the difference in the concentration of water in the skin cells and swimming pool’s water.
  3. Manjeet showed the value of aware person and a good learner who clarifies the doubts.

Question 2.
Kalyan’s mother wanted to use some eggs for incubation. Kalyan helped his mother in separating rotten and spoilt eggs from the good ones. He took a bucket of water to separate them.

  1. How can one separate the rotten eggs from the good ones using water?
  2. What is the shell of an egg made up of?
  3. What value of Kalyan is seen in this act?

Answer:

  1. We can separate the rotten eggs by dipping them in water. The eggs that will float in water are rotten eggs and those that sinks are good one.
  2. The shell of an egg is made up of calcium carbonate.
  3. Kalyan showed the value of being helpful and responsible.

MP Board Class 9th Science Solutions

MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants

MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants

Transportation in Animals and Plants Intex Questions

Question 1.
Why is the color of blood red?
Answer:
Because blood contains a red pigment called hemoglobin.

Question 2.
Paheli wonders which side of the heart will have oxygen – rich blood and which side will have carbon dioxide  rich blood?
Answer:
Right side of heart has blood rich in oxygen and left side of heart has blood rich in carbon dioxide.

Question 3.
Paheli wants to know whether other animals also urinate?
Answer:
Yes.

MP Board Solutions

Question 4.
Boojho wants to know why plants absorb a large quantity of water from the soil, then give it off by transpiration?
Answer:
Because transpiration helps in suction of water.

Activities

Activity – 1
Record your own pulse beats per minute and those of your classmates? Compare the values you obtained and insert them in Table?
Table:
Pulse rate
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 1

Activity – 2
Record your own pulse rate and heartbeat and that of your friends while resting and after running and record in Table? Do you find any relationship between your heartbeat and pulse rate?
Table:
Heartbeat and pulse rate
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 2

Transportation in Animals and Plants Text Book Exercises

Question 1.
Match structures given in Column I with functions given in Column II.
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 3
Answer:

(i) – (b)
(ii) – (d)
(iii) – (a)
(iv) – (c)

Question 2.
Fill in the blanks:

  1. The blood from the heart is transported to all parts of the body by the …………………..
  2. Haemoglobin is present in ……………………….. cells.
  3. Arteries and veins are joined by a network of ………………………..
  4. The rhythmic expansion and contraction of the heart is called …………………………
  5. The main excretory product in human beings is ………………………….
  6. Sweat contains water and ……………………..
  7. Kidneys eliminate the waste materials in the liquid form called ……………………….
  8. Water reaches great heights in the trees because of suction pull caused by ……………………..

Answer:

  1. Arteries
  2. Red blood
  3. Capillaries
  4. Heart beat
  5. Urine
  6. Urea
  7. Urine
  8. Transpiration.

MP Board Solutions

Question 3.
Choose the correct alternative:

Question (a)
In plants, water is transported through?
(a) Xylem
(b) Phloem
(c) Stomata
(d) Root hair.
Answer:
(a) Xylem

Question (b)
Water absorption through roots can be increased by keeping the plants?
(a) In the shade
(b) In dim light
(c) under the fan
(d) covered with a polythene bag.
Answer:
(b) In dim light

Question 4.
Why is transport of materials necessary in a plant or in an animal? Explain.
Answer:
Transport of material is necessary in plant or animal because due to it the nutrients are made available to all the parts of the body. If the transport of necessary nutrients does not take place in the body, the body will not be able to survive. For example, in plants
roots absorb water and leaves prepare food utilising the water.

The food is also required by root. So, there is no utility of water absorbed by the roots if it does not reach leaf or food prepared by leaf if it does not reach root. Thus, the process of transportation is necessary.

MP Board Solutions

Question 5.
What will happen if there are no platelets in the blood?
Answer:
The blood platelets are responsible for the clotting of the blood. Without the platelets, blood cannot be clot. So, if there is any cut, blood will continue to flow out and ultimately the person die.

Question 6.
What are stomata? Give two functions of stomata?
Answer:
The small pores in leaves and stems of plants are called stomata.
Functions of Stomata:

  1. It absorb oxygen from air.
  2. It helps in the transportation of water.

Question 7.
Does transpiration serve any useful function in the plants? Explain.
Answer:
Yes, transpiration is an important function in plants. Plants absorb mineral nutrients and water from the soil. Not all the water absorbed is utilised by the plant. The water evaporates through the stomata present on the surface of the leaves by the process of transpiration. The evaporation of water from leaves generates a suction pull (the same that you produce when you suck water through a straw) which can pull water to great heights in the tall trees. Transpiration also cools the plant.

Question 8.
What are components of blood?
Answer:
Red blood cells (RBC), while blood cells (WBC), plasma and platelets are the components of blood.

Question 9.
Why is blood needed by all the parts of a body?
Answer:
Blood is needed by all the parts of a body because it carries digested food and oxygen to all parts of body. It also carries away the waste products.

MP Board Solutions

Question 10.
What makes the blood look red?
Answer:
A red coloured pigment called hemoglobin gives the blood red color.

Question 11.
Describe the function of the heart?
Answer:
The main function of heart is to collects and distributes blood from and to all parts of the body. The right auricle and ventricle receives blood with carbon dioxide from all the parts of the body. The collected blood is then pumped to the lungs for the purification. In lungs, the exchange of gases take place and purified blood is sent back to the left auricle. After that purified blood is sent to all the parts of the body through arteries.

Question 12.
Why is it necessary to excrete waste products?
Answer:
Waste products are harmful for the body, so it is necessary to excrete waste products.

Question 13.
Draw a diagram of the human excretory system and label the various parts?
Answer:
Human Excretory System Diagram:
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 4.2

Extended Learning – Activities and Projects

Question 1.
Find out about the blood groups and their importance?
Answer:
Carl Landesteiner (1900) discovered that there are two types of antigens present on the plasma membrane of the RBC. These are antigen A and antigen B. These are also called corpuscle factors. There are also two types of antibodies present in the plasma. These are antibody A (Anti – A) and antibody B (Anti – B).

These are also called plasma factors. The blood is classified into four groups on the basis of the presence or absence of these antigens. These groups are A, B, AB and O. This system of classification of blood is called: ‘ABO’ system. The following table shows the types of blood groups and their antigens and antibodies:
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 5

Along with the A and B antigens or antibodies, many people have another factor called the Rh factor. This is an antigen first found in Rhesus monkey (hence, called the Rh factor). People whose red blood cells contain the Rh antigen are said to be Rh positive (Rh+). People who lack it are called Rh negative (Rh).

A person with Rhblood does not have Rh antibody (which destroys Rh antigen) naturally. But, as and when an Rh antigen enters the blood, it develops Rh antibody and destroys the antigen. If a person with blood group A has Rh antigen, his/her blood is said to be A+(A positive).

Similarly if a person’s blood group is B and he/she does not have Rh antigen, then his/her blood group is B(B negative). So, we have eight blood groups: A+, B+, AB+, O+, A+, B+, AB+ and O+.
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 6

Question 2.
When a person suffers from chest pain, the doctor immediately takes an ECG? Visit a doctor and get information about ECG? You may even look up an encyclopedia or the internet?
Answer:
An electrocardiogram (ECG or EKG, abbreviated from the German Electrocardiogram) is a graphic produced by an electrocardiograph, which records the electrical activity of the heart over time. Analysis of the various waves and normal vectors of depolarization and repolarization yields important diagnostic information.

  1. It guides therapy and risk stratification for heart patients.
  2. It helps detect electrolyte disturbances. It allows for the detection of conduction abnormalities.
  3. It is used as a screening tool for ischemic heart disease during a cardiac stress test.
  4. It is occasionally helpful with non – cardiac

In 1856, Kollicker and Mueller discovered the electrical activity of the heart when a frog sciatic nerve/gastrocenemius preparation fell onto an isolated frog heart and both muscles contracted synchronously. Alexander muirhead attached wires to a feverish patient’s wrist to obtain a record of the patient’s heartbeat while studying for his DSc (in electricity) in 1872 at St Bartholomew’s Hospital.

This activity was directly recorded and visualized using a Lippmann capillary electrometer by the British physiologist John Burdon Sanderson. The first to systematically approach the heart from an electrical point – of – view was Augustus Waller, working in St Mary’s Hospital in Paddington, London. His electrocardiograph machine consisted of a Lippmann capillary electrometer fixed to a projector.

The trace from the heartbeat was projected onto a photographic plate which was itself fixed to a toy train. This allowed a heartbeat to be recorded in real time. In 1911 he still saw little clinical application for his work. The break through came when Willem Einthoven, working in Leiden, The Netherlands, used the string galvanometer invented by him in 1901, which was much more sensitive than the capillary electrometer that Waller used. Einthoven assigned the letters P, Q, R, S and T to the various deflections, and described the electrocardiographic features of a number of cardiovascular disorders. In 1924, he was awarded the Nobel Prize in Medicine for his discovery.

MP Board Solutions

Transportation in Animals and Plants Additional Important Questions

Objective Type Questions

Question 1.
Choose the correct alternative:

Question (a)
The cells in blood that fight against the disease causing germs are called?
(a) Platelets
(b) White blood cells
(c) Red blood cells
(d) None of these.
Answer:
(b) White blood cells

Question (b)
Which of these is responsible for clotting of blood?
(a) Platelets
(b) White blood cells
(c) Red blood cells
(d) none of these.
Answer:
(a) Platelets

Question (c)
Smallest filtering units in kidneys are called?
(a) ventricles
(b) auricles
(c) vessels
(d) nephrons.
Answer:
(d) nephrons.

MP Board Solutions

Question (d)
Urine is stored in till excreted?
(a) Ureter
(b) Kidney
(c) Urinary bladder
(d) Urethra.
Answer:
(c) Urinary bladder

Question (e)
Instrument used to measure heart beat is called?
(a) thermometer
(b) nanometer
(c) stethoscope
(d) none of these.
Answer:
(c) stethoscope

Question (f)
How many times heart of an healthy person beats in one minute?
(a) 70
(b) 71
(c) 72
(d) 73
Answer:
(c) 72

Question (g)
Which one of the following is not an excretory organ?
(a) Lever
(b) Skin
(c) Kidney
(d) Oesophagus.
Answer:
(d) Oesophagus.

MP Board Solutions

Question (h)
The tube by which all the wastes are thrown out is known as?
(a) ureters
(b) urethra
(c) urinary bladder
(d) none of these.
Answer:
(b) urethra

Question 2.
Fill in the blanks:

  1. The fluid part of the blood is called …………………………
  2. One type of cells are the red blood cells which contain a red pigment called …………………….
  3. There are the ……………………… types of blood vessels in the body.
  4. …………………….. carry oxygen rich blood from the heart to all parts of the body.
  5. The number of pulse beats per minute is called the ………………………
  6.  …………………… are the vessels which carry carbon dioxide rich blood from all parts of the body back to the heart.
  7. The heart has …………………….. chambers.
  8. The walls of the chambers of the heart are made up of ……………………
  9. Your heart is roughly the size of your ……………………………
  10. The English Physician, William Harvey discovered the circulation of ………………………….
  11. The parts involved in excretion forms the …………………… system.
  12. The kidneys, ureters, bladder and urethra form the ……………………………… system
  13. Birds, Insects and lizard excrete ………………………………. in semi – solid form.
  14. A …………………………………. is a group of cells not perform  specialized function in an organism.
  15. The vascular tissue for the transport of water and nutrients in the plant is called the ………………………..
  16. Water and mineral nutrients are absorbed by roots from the ………………………….

Answer:

  1. Plasma
  2. Hemoglobin
  3. Two
  4. Arteries
  5. Pulse rate
  6. Veins
  7. Four
  8. Muscles
  9. Fist
  10. Blood
  11. Excretory
  12. Excretory
  13. Uric acid
  14. Tissue
  15. Xylem
  16. Soil.

MP Board Solutions

Question 3.
Which of the following statements are true (T) or false (F):

  1. Circulatory system consists of the heart and blood vessels.
  2. Oxygenated blood flows in arteries.
  3. Valves are there in inner walls of veins.
  4. White blood cells to not protect our body from diseases.
  5. Blood is red due to platelets.
  6. In humans, blood flows through arteries and veins and the heart acts as a pumping organ.
  7. The heart is protected by a membrane called paracardium.
  8. Veins carry blood from all parts of the body back to the heart.
  9. Artery carry blood from the heart to all parts of the body.
  10. Our body requires at least 2 to 3 litres of water everyday.
  11. In humans, excretion involves the removal of sweat, urea and faces.
  12. All organisms nave same method of waste removal from their body.
  13. The xylem and phloem together make up the vascular system in plants.
  14. In older plants vacuoles contain the excretory products.

Answer:

  1. True
  2. True
  3. True
  4. False
  5. False
  6. True
  7. True
  8. True
  9. True
  10. True
  11. True
  12. False
  13. True
  14. True.

Transportation in Animals and Plants Very Short Answer Type Questions

Question 1.
Name the transport medium in human beings?
Answer:
Blood.

Question 2.
White blood corpuscles is called as soldiers. Why?
Answer:
They have no definite shape. They work in our body like soldiers whenever any harmful micro – organism, virus or foreign body enters inside our body then these corpuseles prevent their entry and destroy them.

Question 3.
If blood does not coagulate after injury, then what will happen?
Answer:
The people can be died.

MP Board Solutions

Question 4.
How does the red blood corpuscles deliver oxygen to each part of body?
Answer:
Hemoglobin reacts with oxygen and forms a temporary compound called as oxyhemoglobin which breaks again in every part of body and donates oxygen.

Question 5.
Write the names of different blood vessels?
Answer:
The names of different blood vessels are arteries, veins and capillaries.

Question 6.
Write functions of hemoglobin?
Answer:
Hemoglobin containing iron and this hemoglobin reacts with oxygen and forms a temporary compound called as oxyhemoglobin which breaks again in every part of body and donates oxygen.

Question 7.
Why is the blood red in color?
Answer:
The blood is red in color due to the presence of an iron containing pigment hemoglobin.

Question 8.
What will happen if the blood rich in oxygen and the blood rich in carbon dioxide mix with each other?
Answer:
The net oxygen content of blood Will be reduced and hence body will suffer from lack of oxygen.

Question 9.
What is pulse rate?
Answer:
The number of beats per minute is called the pulse rate.

Question 10.
What is the resting pulse rate of a normal person?
Answer:
A resting person, usually has a pulse rate between 72 and 80 beats per minute.

MP Board Solutions

Question 11.
Where is heart located?
Answer:
The heart is located in the chest cavity with its lower tip slightly tilted towards the left.

Question 12.
What are the two upper chamber of hearts?
Answer:
Atria.

Question 13.
What are ventricles?
Answer:
The two lower chambers of heart are called ventricles.

Question 14.
Define excretion?
Answer:
Excretion is a process through which the metabolic wastes are excreted out from the body.

Question 15.
Name the various organs of excretion in human?
Answer:
Various excretory organs of humans are skin, lungs and kidneys.

Question 16.
How does excretion occur in unicellular animals?
Answer:
In unicellular animals excretion takes place by diffusion process.

MP Board Solutions

Question 17.
What is transpiration?
Answer:
Transpiration is a process of evaporation of water from the surface of the leaf in the form of water vapours. It helps:

  1. To generate pulling force for the upward movement of water.
  2. To get rid of excess of water.
  3. To maintain the temperature because of cooling effect.

Question 18.
What is excretion?
Answer:
Excretion is the process of the removal of the waste product from the body of a plant or an animal. The different organisms eliminate their waste in different ways.

Question 19.
Write the names exretory materials in plants?
Answer:
The excretory materials in plants are a gum, rain and latex.

Transportation in Animals and Plants Short Answer Type Questions

Question 1.
Name the various blood vessels and write their functions?
Answer:
There are three blood vessels:
1. Arteries:
These are the blood vessels which carry or transport oxygenated pure blood from heart to all other parts of the body.

2. Veins:
These are blood vessels which collects the deoxygenated impure blood from the whole body and send it to the heart.

3. Capillaries:
These are the network of thin tube like structures which connect the arteries and veins together.

Question 2.
What is blood? What are the components of blood?
Answer:
Blood is a fluid tissue that circulates and transport the material within the cells. It is red in color due to the presence of a pigment called hemoglobin. Various components of bloods are blood cells and plasma.
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 7

Question 3.
What is the main difference between artery and a vein?
Answer:
Differences between arteries and veins:
Artery:

  1. It carries pure blood from heart to the different organs of the body.
  2. Blood flows with jerks with high pressures.
  3. They always carry oxygenated rich blood.
  4. It has no valve.
  5. Its wall is thick.

Vein:

  1. It collects impure blood from different parts of the body.
  2. Blood flows smoothly with low pressure.
  3. They always carry carbon dioxide rich blood.
  4. Semilunar valves are present.
  5. Its wall is thin.

MP Board Solutions

Question 4.
What is meant by excretion? Explain its need for the sustenance of the individual?
Answer:
Excretion is a process of removal of metabolic waste materials from the body. If excretory matter is present in the body It will disturb the metabolic activities going or in different parts of the body. It will disturb metabolic activity in body. So it is necessary to excrete out all the metabolic wastes from the body.

Question 5.
Describe the process of water and mineral absorption in plants?
Answer:
In higher plants root system is well developed. The tertiary roots possess root hairs. They absorb mineral salt and water in the form of dilute solution through endosmosis. The cells of root hair transfer this solution to the epidermal cells. Through diffusion process absorbed solution reaches in the xylem vessels and from it lifts up and then reaches up to the top of the plant.

Question 6.
How do the exchange of gases occur in plants?
Answer:
In case of plants the lower surface of leaves have small pores called stomata. These are provided by two guard cells which control the opening or closing of the stomata. When the concentration of O2 gas increases during photosynthesis the guard cells open and O2 gas is given out and if concentration CO2 gas increases during respiration, the guard cells cause CO2 gas to go out of the cells. This is how the exchange of gases occur in plants.

Question 7.
How does liver help in the process of excretion?
Answer:
Liver plays a major role in excreting waste products of the body. Urea, the chief introgenous waste materials is formed in the liver. The break down of amino acids which takes place in it results in the accumulation of nitrogenous wastes. These nitrogenous wastes break down further into ammonia. Ammonia is a very toxic, therefore, liver converts ammonia along with CO2, into urea with the help of specific enzymes. This urea is eventually thrown out by kidneys.

Question 8.
Why is the process of excretion important for living?
Answer:
As a result of metabolism various toxic substances are continuously formed. These wastes (carbon dioxide, ammonial compounds, other salts) if allowed to accumulate in the body (cells), would disturb the chemical composition of the protoplasm and produce toxic effects, crippling the life activities. Hence their elimination is most important. This is done by the process of excretion.

MP Board Solutions

Question 9.
Why do doctors examine the urine to diagnose a disease? What do they examine in urine?
Answer:
The concentration of various wastes in the urine depends upon the functioning of various organs or organ system in the body. So the examination of urine of a person gives a good idea about his/her general health. The doctors, therefore use the urine test to diagnose disease in the body. For example, presence of excess sugar in urine indicates malfunctioning of pancreas. Presence of excess urea or uric acid indicates the malfunctioning of kidneys.

Transportation in Animals and Plants Long Answer Type Questions

Question 1.
How many types of blood corpuscles are there? Write their functions?
Answer:
There are three types of blood corpuscles:
1. Red blood corpuscles:
They are elliptical or spherical in shape. Hemoglobin containing iron is present in them. This hemoglobin reacts with oxygen and forms a temporary compound called as oxyhemoglobin which breaks again in every part of body and donates oxygen.

2. White blood corpuscles They have no definite shape, They work in our body like soldiers. Whenever any harmful microorganism, virus or foreign body enters inside our body then these corpuscles prevent their entry and destroy them.

3. Blood platelets:
Whenever there is bleeding due to injury, these platelets move there and coagulates the blood, as a result excess blood does not flow.

4. Plasma:
It is the fluid medium which transports digested food as well as metabolic waste products.

MP Board Solutions

Question 2.
Write functions of blood?
Answer:
Various functions of blood are:

  1. The red blood cells carry oxygen to different parts of the body.
  2. The white blood cells fight against the disease causing germs and bacteria and kill them.
  3. The platelets of blood help in clotting of blood.
  4. The plasma carries CO2 from the body.
  5. It regulates our body temperature.
  6. It carries digested and absorbed food and hormones to different organs.
  7. The waste products are taken into excretory organs through blood.

Question 3.
Describe the “pulmonary circulation of blood?”
Answer:
The deoxygenated blood is collected from various organs of the body by two veins called superior and inferior vena cava. They join to form a main vein which empties the blood into the right auricle. From here it enters the right ventricle and is pumped into the right pulmonary artery which caries it to the lungs. Here the carbon – dioxide oxygen exchange takes place. The oxygenated blood is carried by the pulmonary vein to the left auricle. This part of the circulation is called the pulmonary circulation.

Question 4.
Explain structure of heart and draw it’s diagram?
Answer:
Our heart is situated in the left side of our chest. It is divided into four chambers. The upper two chambers collect the blood from veins and are known as auricles. The lower two chambers are meant for distribution of the blood in various parts of the body and are known as the ventricles.
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 8
Right auricle gets the impure blood which is sent to right ventricle. From right ventricle the blood is thrown to pulmonary arteries which carry this. blood to lungs for put if cation, which is collected by pulmonary veins and now it is in a purified state.

It is brought to left auricle and then to left ventricle from where it is thrown into aorta which is responsible for distribution of this pure blood to various parts of the body. Aorta is divided into various arteries which are divided into five capillaries. After exchange of materials these capillaries form the veins which bring blood to the right auricle.

MP Board Solutions

Question 4.
Define the systematic circulation of blood. Draw the diagram of schematic diagram of circulation?
Answer:
The oxygenated blood from the left auricle enters the left ventricle and is then pumped into the aorta and carried to all parts of the body by arteries and capillaries. This part of the circulation is known as systemic circulation.
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 9

Question 5.
Describe “blood transfusion?”
Answer:
Blood is a very vital component of our body and we cannot afford to lose it. In case of serious injury, accident or during an operation, we may lose a considerable quantity of blood from our body. In such cases blood from another healthy person is transferred to the patient. This is called blood transfusion. The blood of all human beings falls in any one of the following groups A, B, AB or O. Transfusion should be done carefully and only after checking the blood group of the patient.

Question 6.
“Excretion is process to eliminate the waste by products from the body”. Justify the statement?
Answer:
The nitrogenous waste ammonia is converted into urea by the liver. The renal artery carry the urea of kidneys. Each kidney consists of number of coiled tubes called Nephron. There are about ten million nephron in each kidney of an adult man. The Nephron is the functional unit of the kidney.

One end of the nephron is cup shaped called Bowman’s capsule. The renal artery branches into millions of capillaries in the form of coil in the each Bowman’s capsule. This coil or capillaries of renal artery in the Bowman’s capsule is called Glomerules. The blood is filtered through the walls of capillaries of glomerulus.

This is a selective filteration. The bigger molecules of sugars, salts and nitrogenous wasters are filtered. This selective filteration is termed as dialysis. Thus, the glomerulus acts as dialysis bag of the kidney. The filterate from glomerulur in the Bowman’s capsule passes through the tiny tubule.

Where major part of glucose and other useful substances is reabsorbed. It is sent back into the blood of the renal vein. The waste liquid called urine, containing nitrogenous waste is sent to the urinary bladder through collecting tubule and uretere. From urinary bladder it is eliminated from the body through urethera.
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 10 and 11

Question 7.
What are the various waste materials excreted from the human body?
Answer:
Excretion is done by following organs:
1. Kidneys:
These excrete urea, salts, water etc. through urine.

2. Skin:
Skin possesses sweat glands. These glands absorb urea, salts and a large quantity of water from the blood capillaries near by and excrete them through their pores on the skin in the form of sweat.

3. Liver:
Liver is not a direct excretory organ. Liver cells convert more toxic ammonia into less toxic urea and uric acid and then pass them to the kidneys through the blood for excretion. Liver also censer toxic substances. It removable salts in bile juice. These bile salts are formed due to break down of hemoglobin. If bile salts are not remove. They cause jaundice. Bile salts are removed through intestine.

MP Board Solutions

Question 8.
Write a short note on “excretion in plants”?
Answer:
Plants, have no special organs for excretion. product of respiration i.e. carbon dioxide is partly us phtosynthesis. The excess amount of carbon dioxide escape the stomata and lenticles. Some of the waste products of photosynthesis an in vacuoles in the leaves and bark of trees. The plant them by sheddingthe leaves and bark.

Some waste products are transformed into harm and stored inside the plant body. Rubber and raphides a of such products. Plants also secrete a number of uses like gum, latex, resin, sandalwood oil and eucalyptus
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 12

Question 9.
Describe the process of absorption and transportation of water and minerals in plants?
Answer:
The plant root have root hairs which absorb water and minerals in the form of solution from soil. This process is called absorption. This water and minerals are then transported to other parts of plant i.e., stem, leaves and flowers through a special tissue called xylem. Then food is synthesised within leaves of plant and is transported in all parts of plant including roots, through phloem. This produces is called transportation.

Question 10.
Draw a neat diagram to show circulatory system?
Answer:
MP Board Class 7th Science Solutions Chapter 11 Transportation in Animals and Plants img 13

MP Board Class 7th Science Solutions

MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1

MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1

Question 1.
In the given fig., lines AB and CD intersect at O. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.
Solution:
Given
∠AOC + ∠BOE = 70°
∠BOD = 40°
To find:
∠BOE and Reflex ∠COE
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-1
Calculation:
∠BOD
= ∠AOC = 40° (VOA’s)
∠AOC + ∠BOE = 70°
40° + ∠BOE = 70°
∴ ∠BOE = 30°
∠AOC + ∠COE + ∠BOE = 180°
(∴ Angles on the same line)
70° + ∠COE = 180°
∴ ∠COE – 110°
Reflex ∠COE = 360° – ∠COE
= 360° – 110° = 250°

Question 2.
In Fig. below, lines XY and MN intersect at O. If ∠POY = 90° and a : b = 2 : 3, find c.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-2
Solution:
Given
∠POY= 90°
a : b = 2 : 3
To find. ∠C
Calculation:
a = 2x
b = 3x
b + a + 90° = 180° (∴ Angles on the same line)
3x + 2x + 90° = 180°
5x = 90°
x = 18°
a = 2 x 18° = 36°
b = 3 x 18° = 54°
b + c = 180 (LPA’s)
c = 180° – 54° = 126°

MP Board Solutions

Question 3.
In Fig. below, if ∠PQR = ∠PRQ, then prove that ∠PQS = ∠PRT.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-3
Solution:
Given
∠PQR = ∠PRQ
To prove:
∠PQS = ∠PRT
Proof:
∠PQS + ∠PQR = 180° (LPA’s) …..(1)
∠PRT + ∠PRQ = 180° (LPA’s)
=> ∠PRT + ∠PQR = 180° (∴ ∠PRQ = ∠PQR) …(2)
From (1) and (2), we get
∠PQS + ∠PQR = ∠PRT + ∠PQR
∠PQS = ∠PRT Proved.

Question 4.
In Fig. below, if x + y = w + z, then prove that AOB is a line.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-4
Solution:
Given
x + y = w + z
To prove
AOB is a line
Proof:
x + y + z + w = 360° (Complete angle)
x + y + x + y = 360° (∴ w + z = x + y)
2(x + y) = 360°
x + y = 180° (LPA’s)
AOB is a line. Proved

Question 5.
In Fig. below. POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that
∠ROS = \(\frac{1}{2}\) (∠QOS – ∠POS).
Solution:
Given
POQ is a line, OR ⊥ PQ
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-5
To prove:
∠ROS = \(\frac{1}{2}\) (∠QOS – ∠POS).
Proof:
∠QOS = ∠QOR + ∠ROS
∠QOS = 90° + ∠ROS ….(1)
∠POS = ∠POR – ∠ROS
∠POS = 90° – ∠ROS …..(2)
Subtracting (1) and (2), we get
∠QOS – ∠POS = 90° + ∠ROS – (90° – ∠ROS)
= 90° + ∠ROS – 90° + ∠ROS
∠QOS – ∠POS = 2 ∠ROS
∠ROS = \(\frac{1}{2}\) (∠QOS – ∠POS)

Question 6.
It is given that ∠XYZ = 64° and XY is produced to point P. Draw a figure from the given information. If ray YQ bisects ∠ZYP, find ∠XYQ and reflex ∠QYP.
Solution:
Given
∠XYZ = 64°
To find:
∠XYQ and Reflex ∠QYP
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-6
Calculation:
∠XYZ + ∠ZYQ + ∠QYP
= 180° (∴ Angles on the same line)
64° + x + x = 180°
2x = 180° – 64° = 116°
x = 58°
∠XYQ = ∠XYZ + ∠ZYQ
= 64° + 58° = 122°
Reflex ∠QYP = 360° – 58° = 302°

Transversal:
A line which intersects two or more lines at distinct points is called a transversal.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-7

Angles and their Name formed by Transversal:
Line intersects line m and n at point P and Q respectively. So line l is a transversal ftk lines m and n. Observe that four angles are formed at each of the points P and Q. Name these angles ∠1, ∠2, ∠3, ∠4, ∠5, ∠6, ∠7 and ∠8. There are two type of angles: exterior angles and interior angles as shown in Fig. above.

(a) ∠1, ∠2, ∠7 and ∠8 are Exterior angles and
(b) ∠3, ∠4, ∠5 and ∠6 are Interior angles

Same pairs of angles are formed when a transversal intersects two lines. These are given below:

(a) Corresponding angles:

  1. ∠1 and ∠5
  2. ∠2 and ∠6
  3. ∠4 and ∠8
  4. ∠3 and ∠7

(b) Alternate interior angles:

  1. ∠4 and ∠6
  2. ∠3 and ∠5

(c) Alternate exterior angles:

  1. ∠1 and ∠7
  2. ∠2 and ∠8

(d) Interior angles on the same side of the transversal:

  1. ∠4 and ∠5
  2. ∠3 and ∠6

MP Board Solutions

Axiom 3:
If a transversal intersects two parallel lines, then each pair of corresponding angles is equal.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-8
If AB ∥ CD and l is the transversal.
∠1 = ∠5; ∠4 = ∠8
(Corresponding angles)
∠2 = ∠6; ∠3 = ∠7

Axiom 4:
If a transversal intersects two lines such that a pair of correspond-ing angles are equal, then the two lines are parallel to each other.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-9
In Fig., AB and CD are two lines, intersected by transversal ‘l’ such that ∠1 = ∠2 (corresponding angles,) then AB ∥ CD.

Theorem 1.
If a transversal intersects two parallel lines, then each pair of alternate interior angles are equal.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-10
Given. AB ∥ CD and l is the transversal.
To prove:

  1. ∠3 = ∠5
  2. ∠4 = ∠6

Proof:

∠1 = ∠3 (V.O.A’s) ……(i)
∠1 = ∠5 (Corresponding angle’s) …(ii)
From (i) and (ii), we get
∠3 = ∠5
∠4 = ∠2 (V.O.A’s)
∠2 = ∠6 (Corresponding angle’s)
From (iii) and (iv), we get
∠4 = ∠6. Proved.

Theorem 3.
if a transversal intersect two lines, such that a pair of alternate interior angle is equal, then the two lines are parallel.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-11
Given
AB and CD are two lines, and l is the transversal.
∠2 = ∠3
To prove:
AB ∥ CD
Proof:
∠2 = ∠3 (V.O.A’s) …..(i)
∠1 = ∠2 (Corresponding angle’s) …(ii)
From (i) and (ii), we get
∠1 = ∠2
∠1 and ∠3 are corresponding angles and are equal.
AB ∥ CD. Proved.

MP Board Solutions

Theorem 4.
If a transversal intersects two parallel lines, then each pair of interior angles on the same side of the transversal is supplementary.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-12
Given
AB ∥ CD and l is the transversal.
To prove:
∠4 + ∠5 = 180° and ∠3 + ∠6 = 180°
Proof
∠3 + ∠4 = 180° (LPA’s) …..(i)
∠3 = ∠5 (AIA’s) …..(ii)
∠4 = ∠6 (AIA’s) …..(iii)
From (i) and (ii) we get
∠5 + ∠4 = 180°
From (i) and (iii), we get
∠3 + ∠6 = 180s.

Theorem 5.
If a transversal intersects two lines, such that a pair of interior angles on the same side of transversal is supplementary, then the two lines are parallel.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-13
Given
AB and CD are two lines, l is the transversal.
∠4 + ∠5 = 180°
To prove
AB ∥ CD
Proof
∠4 + ∠5 = 180° (Given) …..(i)
∠1 + ∠4 = 180° (LPA’s) …..(ii)
From (i) and (ii), we get
∠4 + ∠5 = ∠1 + ∠4
∠5 = ∠1
∠1 and ∠5 are corresponding angles and are equal.
AB ∥ CD. Proved.

Theorem 6.
Lines which are parallel to the same line are parallel to each other.
MP Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1 img-14
Given, p, q and r are three lines
P ∥ r and q ∥ r
To prove
p ∥ q
Proof
p ∥ r and l is the transversal.
∠1 = ∠3 (Corresponding angles) …..(i)
q ∥ r and l is the transversal.
∠2 = ∠3 (Corresponding angles) …..(ii)
From (i) and (ii), we get
∠1 = ∠2
∠1 and ∠2 are corresponding angles and are equal.
p ∥ q. Proved.

MP Board Class 9th Maths Solutions

MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom

MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom

Structure of the Atom Intext Questions

Structure of the Atom Intext Questions Page No. 47

Question 1.
What are canal rays?
Answer:
Canal rays are positively charged radiations which led to the discovery of positively charged sub-atomic particle called proton. These rays were discovered by E. Goldstein.

MP Board Solutions

Question 2.
If an atom contains one electron and one proton, will it carry any charge or not?
Answer:
The atom will not contain any charge and will be electrically neutral because both electron and proton will balance each other.

Structure of the Atom Intext Questions Page No. 49

Question 1.
On the basis of Thomson’s model of an atom, explain how the atom is neutral as a whole.
Answer:
According to Thomson’s model, an atom consist of a positively charged sphere and electrons are embedded in it. So, both charges are equal which makes the atom electrically neutral.

Question 2.
On the basis of Rutherford’s model of an atom, which sub – atomic particle is present in the nucleus of an atom?
Answer:
Proton is the sub – atomic particle which is present in the nucleus of an atom.
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 1

Question 3.
Draw a sketch of Bohr’s model of an atom with three shells.
Answer:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 2

Question 4.
What do you think would be the observation if the a-particle scattering experiment is carried out using a foil of a metal other than gold?
Answer:
The observations would be same as that of gold foil.

Structure of the Atom Intext Questions Page No. 49

Question 1.
Name the three sub – atomic particles of an atom.
Answer:

  1. Positively charged – Protons
  2. Negatively charged – Electrons
  3. No charged – Neutrons.

Question 2.
Helium atom has an atomic mass of 4u and two protons in its nucleus. How many neutrons does it have?
Answer:
Atomic mass = Number of protons + Number of neutrons
∴ 4 = 2 + Number of neutrons
∴ Number of neutrons = 4 – 2 = 2.

Structure of the Atom Intext Questions Page No. 50

Question 1.
Write the distribution of electrons in carbon and sodium atoms.
Answer:
Atomic number of Carbon = 6
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 3

Question 2.
If K and L shells of an atom are full, then what would be the total number of electrons in the atom?
Answer:
K shell is the 1 shell
So, n = 1
Then maximum electron’s = 2n2 = 2 × (1)2
= 2 × 1 = 2
and L shell is the second shell.
So, n = 2
Then maximum electrons = 2(n)2
= 2 × (2)2 = 8
∴ Total number of electrons = 2 + 8 = 10.

Structure of the Atom Intext Questions Page No. 52

Question 1.
How will you find the valency of chlorine, sulphur and magnesium?
Answer:
We know that valency is the number of electrons lost, gained or shared by atom to become stable or to complete 8 electrons in the shell.
Now, Chlorine,
Atomic number = 17
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 4
Then, it will take 8 – 7 = 1 electron to complete its shell.
∴ Its valency is ‘I’
Sulphur, Atomic number = 16
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 5
It will take 8-6 = 2 electrons to complete its shell.
∴ Its valency is ‘2’.
Magnesium, Atomic number = 12
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 6
It will lose 2 electrons from its outermost shell to become stable.
∴ Its valency will be ‘2’.

Structure of the Atom Intext Questions Page No. 52

Question 1.
If number of electrons in an atom is 8 and number of protons is also 8 then,
(i) What is the atomic number of the atom? and
(ii) What is the charge on the atom?
Answer:
(i) Number of electrons = 8 and,
Number of protons =8
Then, Atomic number = Number of protons = 8

(ii) Now, total electrons (-) = Total protons (+)
So, atom will be electrically neutral.

MP Board Solutions

Question 2.
With the help of table 4.1 of Textbook, find out the mass number of oxygen and sulphur atom.
Answer:
From the table, we have,
Oxygen,
Mass Number = Number of protons + Number of neutrons
= 8 + 8 = 16
Sulphur,
Mass number = Number of protons + Number of neutrons
= 16 + 16 = 32.

Structure of the Atom Intext Questions Page No. 53

Question 1.
For the symbol H, D, and T tabulate three sub – atomic particles found in each of them.
Answer:
H, D, and T stand for protium, deuterium and tritium as isotopes of hydrogen atom.
Table:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 7

Question 2.
Write the electronic configuration of any one pair of isotopes and isobars.
Answer:
Pair of isotopes: \(_{ 6 }^{ 12 }{ C }\), \(_{ 6 }^{ 14 }{ C }\)
Electronic configuration:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 8

Structure of the Atom NCERT Textbook Exercises

Question 1.
Compare the properties of electrons, protons and neutrons.
Answer:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 10

Question 2.
What are the limitations of J.J. Thomson’s model of the atom?
Answer:
J.J. Thomson’s model explained the existence of positive charge in the form of sphere and electrons embedded in it. But, he was unable to explain the Rutherford’s gold foil experiment in which most of positive α – particles passed straight, existence of electrons in the circular path and protons at the centre of the atom.

MP Board Solutions

Question 3.
What are the limitations of Rutherford’s model of the atom?
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 11
Answer:
Rutherford explained that electrons revolve in a circular path which is found contradictory in terms of stability of atom. Because electrons are negatively charged and when they move continuously in circular paths then they should lose their energies and finally, fall into the positively charged nucleus making atoms unstable and collapse.

Question 4.
Describe Bohr’s Model of the atom.
Answer:
Neils Bohr proposed the theory for model of the atom. It is explained as:

  1. Atom is made up of three sub – atomic particles as electrons, protons and neutrons.
    MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 12
  2. The electrons move round the nucleus in fixed circular paths called orbits or shells.
  3. The orbits are represented by the letters K, L, M, N, or the number n = 1, 2, 3, 4.
  4. Centre of the atom is called the nucleus.
  5. Electrons do not radiate energies while revolving in the orbits.
  6. Electrons gain energy when they jump from lower shell to higher shell and lose energy when they return down from higher energy level to lower energy level.

Question 5.
Compare all the proposed models of an atom given in this chapter.
Answer:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 13

Question 6.
Summarise the rules for writing of distribution of electrons in various shells for the first eighteen elements.
Answer:
Rules:

(a) Maximum electrons present in a shell is given by 2n2 whereas n is the number of that shell.
Like,

  • K Shell, n = 1 → 2n2 = 2 × (1)2 = 2
  • L Shell, n = 2 → 2n2 = 2 × (2)2 = 8
  • M Shell, n = 3 → 2n2 = 2 × (3)2 = 18
  • N Shell, n = 4 → 2n2 = 2 × (4)2 = 32.

(b) The outermost shell can have maximum of 8 electrons.
(c) Electrons cannot be occupied in a shell till its inner shells or orbits are completely filled.

Question 7.
Define valency by taking examples of silicon and oxygen.
Answer:
Valency is the combining capacity of an atom to become electrically stable. Or It means how many electrons are lost or gained by an atom to become stable.
In Silicon,
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 30
It has 4 valence electrons.
So, it will lose 4 electrons to become stable.
∴ Its valency is 4.
In Oxygen,
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 31
It has 6 valence electrons.
So, it will gain 8 – 6 = 2 electrons to become stable.
∴ Its valency is 2.

Question 8.
Explain with examples:
(i) Atomic number
(ii) Mass number
(iii) Isotopes
(iv) Isobars
Give any two uses of isotopes.
Answer:
(i) Atomic number: It is equal to the total number of
protons in the nucleus of its atom.
E.g.,

  • Carbon has 6 protons. So, its atomic number is 6.

(ii) Mass number: It is equal to the sum of total number of protons and neutrons in the nucleus.
E.g.,

  • Sodium has 11 protons and 12 neutrons. So, its mass number is 11 + 12 = 23

(iii) Isotopes: These are atoms of the same element having same atomic number, but different mass number.
E.g.

  • \(_{ 35 }^{ 79 }{ Br }\), \(_{ 35 }^{ 81 }{ Br }\), \(_{ 6 }^{ 12 }{ C }\), \(_{ 6 }^{ 14 }{ C }\)

(iv) Isobars: These are the atoms of different elements having different atomic number but same mass number.
E.g.

  • \(_{ 18 }^{ 40 }{ Ar }\), \(_{ 20 }^{ 40 }{ Ca }\), \(_{ 11 }^{ 24 }{ Na }\), \(_{ 12 }^{ 24 }{ Mg }\)

Use of Isotopes:

  • Uranium isotope is used as a fuel in nuclear reactor for generating electricity.
  • Sodium isotope is used to detect the blood clots.

MP Board Solutions

Question 9.
Na+ has completely filled K and L shells. Explain.
Answer:
Atomic number of sodium (Na) is 11.
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 14
Now, if Na loses 1 electron then it will become Na+.
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 15
Now K shell can have maximum of 2 electrons and L shell can have maximum of 8 electrons.
Then, Na+ has completely filled K and L shell.

Question 10.
If bromine atom is available in the form of, say, two isotopes \(_{ 35 }^{ 79 }{ Br }\) (49.7%) and \(_{ 35 }^{ 81 }{ Br }\)Br (50.3%), calculate the average atomic mass of bromine atom.
Answer:
Average atomic mass of bromine atom
= 49.7% of atomic mass of \(_{ 35 }^{ 79 }{ Br }\) + 50.3% of atomic mass of \(_{ 35 }^{ 81 }{ Br }\)
= 49.7% of 79 + 50.3% of 81
= \(\frac { 49.7 }{ 100 }\) × 49 + \(\frac { 450.3 }{ 100 }\) × 81
= (39.263 + 40.743)u = 80.006u

Question 11.
The average atomic mass of a sample of an element X is 16.2u. What are the percentages of isotopes If \(_{ 8 }^{ 16 }{ X }\) and \(_{ 8 }^{ 18 }{ X }\) in the sample?
Answer:
Let the percentage of \(_{ 8 }^{ 16 }{ X }\) in sample be x% and percentage of \(_{ 8 }^{ 18 }{ X }\) in sample be (100 – x)%.
Now,
x% of 16 + (100 – x)% of 18 = 16.2
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 16
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 17
-2x + 1800 = 16.2 × 100 – 2x + 1800 = 1620
∴ -2x = 1620- 1800 = -180
x = \(\frac {180}{2}\) = 90.
∴ Percentage of  \(_{ 8 }^{ 16 }{ X }\) is 90% and percentage of \(_{ 8 }^{ 18 }{ X }\) is (100 – 90)% = 10%.

Question 12.
If Z = 3, what would be the valency of the element? Also, name the element.
Answer:
Z = 3
So, atomic number = 3 (∵ Z = atomic number)
∴ Electronic configuration = 2, 1
Valency = 1
The name of the element is lithium (Li).

Question 13.
Composition of the nuclei of two atomic species X and Y are given as under
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 18
Give the mass number of X and Y. What is the relation between the two species?
Answer:
Mass number of X = Protons + Neutrons = 6 + 6 = 12
And,
Mass number of Y = Protons + Neutrons = 6 + 8 = 14
Both species have same atomic number.
So, they are isotopes of the same element.

Question 14.
For the following statements, write T for True and F for False.

  1. J.J. Thomson proposed that the nucleus of an atom contains only nucleons.
  2. A neutron is formed by an electron and a proton combining together. Therefore, it is neutral.
  3. The mass of an electron is \(\frac {1}{2000}\) times that of proton.
  4. An isotope of iodine is used for making tincture iodine which is used as a medicine.

Answer:

  1. False
  2. False
  3. True
  4. False.

Put tick (✓) against correct choice and cross (✗) against wrong choice in questions 15, 16 and 17.

Question 15.
Rutherford’s alpha – particle scattering experiment was responsible for the discovery of.
(a) Atomic nucleus
(b) Electron
(c) Proton
(d) Neutron.
Answer:
(a) Atomic nucleus

Question 16.
Isotopes of an element have.
(a) the same physical properties
(b) different chemical properties
(c) different number of neutrons
(d) different atomic numbers.
Answer:
(c) different number of neutrons

MP Board Solutions

Question 17.
Number of valence electrons in Cl ion are:
(a) 16
(b) 8
(c) 17
(d) 18
Answer:
(b) 8

Question 18.
Which one of the following is a correct electronic configuration of sodium?
(a) 2, 8
(b) 8, 2, 1
(c) 2, 1, 8
(d) 2, 8, 1.
Answer:
(d) 2, 8, 1.

Question 19.
Complete the following table:

Atomic NumberMass NumberNumber of NeutronsNumber of ProtonsNumber of ElectronsName of the Atomic Species
910
1632Sulphur
2412
21
1010

Answer:

Atomic Number

Mass NumberNumber of
Neutrons
Number of
Pro-­tons
Number of Elec­tronsName of the Atomic Species
9191099Fluorine
16321666Sulphur
1224121212Magnesium
12111Hydrogen
11010Deuterium

Structure of the Atom Additional Questions

Structure of the Atom Multiple Choice Questions

Question 1.
Which is a positive sub – atomic particle?
(a) Proton
(b) Neutron
(c) Electron
(d) None of these.
Answer:
(a) Proton

Question 2.
Electron is discovered by _____ .
(a) J.Chadwick
(b) Neils Bohr
(c) J.J Thomson
(d) Rutherford.
Answer:
(c) J.J Thomson

Question 3.
Proton is discovered by _____ .
(a) Rutherford
(b) J. Chadwick
(c) J J. Thomson
(d) E. Goldstein.
Answer:
(d) E. Goldstein.

Question 4.
Neutron is discovered by _____ .
(a) J.J. Thomson
(b) J. Chadwick
(c) Neils Bohr
(d) Rutherford.
Answer:
(b) J. Chadwick

Question 5.
Nucleus is discovered by _____ .
(a) Rutherford
(b) J. Chadwick
(c) J.J. Thomson
(d) Neils Bohr.
Answer:
(a) Rutherford

MP Board Solutions

Question 6.
Mass of electron is _____ .
(a) 9 × 10-25g
(b) 6 × 10-28g
(c) 8 × 10-24g
(d) 9 × 10-28g.
Answer:
(d) 9 × 10-28g.

Question 7.
Mass of Neutron is _____ .
(a) 1.6 × 10-22g
(b) 1.6 × 10-23g
(c) 1.6 × 10-25g
(d) 1.6 × 10-24g.
Answer:
(d) 1.6 × 10-24g.

Question 8.
Charge on an electron is _____ .
(a) -1.8 × 10-18C
(b) -1.7 × 10-20C
(c) -1.6 × 10-19C
(d) -1.5 × 10-21C.
Answer:
(c) -1.6 × 10-19C

Question 9.
The energy paths in an atom in which electrons revolve are called _____ .
(a) Rings
(b) Cycles
(c) Orbits
(d) Circles.
Answer:
(c) Orbits

Question 10.
ass number is the sum of _____ .
(a) Protons and Electrons
(b) Protons and Neutrons
(c) Electrons, Protons and Neutrons
(d) None of these.
Answer:
(c) Electrons, Protons and Neutrons

Question 11.
Atomic number is equal to _____ .
(a) Number of protons
(b) Number of neutrons
(c) Number of electrons
(d) Both (a) and (c).
Answer:
(d) Both (a) and (c)

Question 12.
Maximum number of electrons that can be filled in ‘M’ shell are _____ .
(a) 17
(b) 19
(c) 18
(d) 20.
Answer:
(c) 18

Question 13.
An atom has atomic number ‘17’, then its valency will be _____ .
(a) 7
(b) 2
(c) 1
(d) 8.
Answer:
(c) 1

Question 14.
Isotopes of an element have same number of _____ .
(a) Neutrons
(b) Protons
(c) Electrons
(d) Both (b) and (c).
Answer:
(c) Electrons

Question 15.
Isobars of different elements have same _____ .
(a) Atomic number
(b) Electrons
(c) Mass number
(d) Neutrons.
Answer:
(d) Neutrons

Structure of the Atom Very Short Answer Type Questions

Question 1.
Who discovered canal rays?
Answer:
E. Goldstein.

Question 2.
Name the fruit which resembles J.J. Thomson model of atom.
Answer:
Watermelon.

Question 3.
Who discovered nucleus?
Answer:
Ernest Rutherford.

Question 4.
Who discovered neutrons?
Answer:
James Chadwick.

Question 5.
Name the central part of an atom where protons and neutrons are held together.
Answer:
Nucleus.

MP Board Solutions

Question 6.
What is Alpha Particle?
Answer:
It is a Helium ion (He2+) which has 2 units of positive charge and 4 units of mass.

Question 7.
What are cathode rays?
Answer:
Cathode rays are a beam of fast moving electrons.

Question 8.
What was the main drawback of Rutherford’s model of the atom?
Answer:
Inability to explain the stability of atom.

Question 9.
Write the symbolic representation of an element A with atomic number 10 and mass number 20.
Answer:
\(_{ 10 }^{ 20 }{ A }\)

Question 10.
Name three Isotopes of Hydrogen.
Answer:

  1. Protium (\(_{ 1 }^{ 1 }{ H }\))
  2. Deuterium (\(_{ 1 }^{ 2 }{ H }\))
  3. Tritium (\(_{ 1 }^{ 3 }{ H }\))

Question 11.
Write the electronic configuration of potassium (K).
Answer:
Atomic number of potassium (K) =19
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 32

Question 12.
Define valency.
Answer:
It is the combining capacity of an atom to become electrically stable.

Question 13.
What is the charge of a proton?
Answer:
1.6 × 10-19C.

Question 14.
Write the year of discoveries of these sub – atomic particles – electron, proton, neutron and neucleus.
Answer:

  1. Electron – 1897
  2. Proton – 1866
  3. Neutron – 1932
  4. Nucleus – 1911.

Question 15.
Which radioactive Isotope is used in treatment of goitre?
Answer:
Iodine – 131.

Structure of the Atom Short Answer Type Questions

Question 1.
Define:
(a) Canal rays
(b) Cathode rays
(c) Atomic number
(d) Mass number
(e) Energy shells
(f) Valency
(g) Octet
(h) Isotopes
(t) Isobars.
Answer:
(a) Canal rays: These are positively charged radiations which led to the discovery of sub – atomic positively charged particles called protons through an experiment conducted by J.J. Thomson in 1897.

(b) Cathode rays: These are negatively charged radiations which led to the discovery of sub – atomic negatively charged particles called electrons during an experiment conducted by E. Goldstein in 1866.

(c) Atomic number: It is the number of protons present in the nucleus of an atom. It is represented by the letter ‘Z’.

(d) Mass number: It is the total number of protons and neutrons present in an atom of an element.
So, Mass number = Number of protons + Number of neutrons.

(e) Energy Shells: These are fixed circular paths around the nucleus of an atom in which electrons revolve continuously with high speed. These are also called orbits. They are represented by the alphabets K, L, M, N.

(f) Valency: It is the combining capacity of an atom to become electrically stable, or it also means the number of valency electrons lost or gained by an atom to complete the eight electrons in the valence shell.

(g) Octet: The completely filled outermost shell like L, M or N with 8 electrons is called an octet. When an atom completes its octet, then it become stable.

(h) Isotopes: These are atoms of same element having same atomic number, but different mass number.

E.g.

  • (\(_{ 1 }^{ 1}{ H }\)) , (\(_{ 1 }^{ 2 }{ H }\)), (\(_{ 1 }^{ 3 }{ H }\)) and \(_{ 6 }^{ 12 }{ C }\), \(_{ 6 }^{ 14 }{ C }\)are the isotopes of hydrogen and carbon respectively.

(i) Isobars: These are atoms of different elements having different atomic number but same mass number.
E.g.

  • \(_{ 18 }^{ 40 }{ Ar }\), \(_{ 20 }^{ 40 }{ Ca }\) and \(_{ 11 }^{ 24 }{ Na }\), \(_{ 12 }^{ 24 }{ Mg }\).

Question 2.
Differentiate between:
(a) Electrons and protons.
(b) Atomic number and mass number.
(c) Isotopes and isobars.
(d) Valence electrons and valency.
Answer:
(a)

ElectronsProtons
(i) This is negatively charged sub – atomic particle.(i) This is positively charged sub – atomic particle.
(ii) Its mass is 9 × 1028gms.(ii) Its mass is 1.6 × 10-24gms.
(iii) Its symbol is “e”.(iii) Its symbol is “P+”.

(b)

Atomic numberAtomic mass
(i) It is the total number of protons present in the atom.(i) It is the sum of protons and neutrons present in the atom.
(ii) It is represented by ‘Z’.(ii) It is represented by ‘A’.
(iii) It is written on the bottom left as a subscript with the symbol the of element.(iii) It is written on top left as a subscript with the symbol the of element.

(c)

IsotopesIsobars
(i) These are atoms of the same element.(i) These are atoms of the different elements.
(ii) They have same atomic number.(ii) They have different atomic number.
(iii) They have different mass number.(iii) They have same mass number.
(iv) They have same chemical properties.(iv) They have different chemical properties.

(d)

Valence ElectronsValency
(i) These are electrons present in the outermost shell of an atom.(i) These are electrons lost or gained through valence shell of an atom to become stable.
(ii) Valence electrons can be 1, 2, 3 …….. 8 or more.(ii) Valency can be 0, 1, 2, 3, 4 only.

Question 3.
Draw the diagrams of:
(a) J.J. Thomson’s model of atom.
(b) Rutherford’s model of atom.
(c) Neils Bohr’s model of atom.
Answer:
(a) J.J. Thomson’s Model:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 19

(b) Rutherford’s Model:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 20

(c) Neils Bohr’s model of atom.
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 21

Question 4.
Write the postulates of J.J. Thomson’s model of the atom.
Answer:
J.J. Thomson’s postulates for model of the atom are as follows:

  1. An atom is a positively charged sphere or ball and negatively charged electrons are embedded in it.
  2. The atom is electrically neutral because negative and positive charges are equal in magnitude.

Question 5.
Write the main points of the theory given by Rutherford for model of atom.
Answer:
Main points of theory of Rutherford regarding model of atom are:

  1. There is an existence of positively charged centre in the atom called as nucleus which contains all the mass of the atom.
  2. The electrons revolve round the nucleus in circular paths called orbits at high speeds.
  3. The size of nucleus (centre of the atom) is very small as compared to size of the atom.
  4. Most of the sphere in an atom is empty.

Question 6.
Write the rules given by Bohr – Bury for arrangement of electrons in different orbits in an atom.
Answer:
Rules given by Bohr – Bury are as follows:

  1. Maximum electrons present in a shell is given by 2n2 where
    • n is the number of that shell.
    • Like, for first shell K, n = 1
    • For second shell L, n = 2
    • third shell M, n = 3
    • fourth shell N, n = 4 called as nucleus which contains all the mass of the atom.
  2. The outermost shell can have maximum of 8 electrons.
  3. Electrons cannot occupy a shell till its inner shells or orbits are completely filled.

MP Board Solutions

Question 7.
An atom ‘X’ has a mass number ‘23’ and atomic number ‘11’. Find its electrons, protons and neutrons. Also, name the element
Answer:
We know,
Atomic number = Number of protons.
∴ 11 = Number of protons
And, Number of protons = Number of electrons.
∴ Number of electrons = 11
Now, Mass number = Protons + Neutrons.
23 = 11 + Neutrons
∴ Neutrons = 23 – 11 = 12
∴ Atom ‘X’ has 11 electrons, 11 protons and 12 neutrons.
The element is Sodium (Na).

Question 8.
Write the electronic configuration of neon, aluminium, sulphur, argon. Also, find valencies.
Answer:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 22

Question 9.
What are radioactive isotopes? Write down the type of isotopes used in:
(a) Tracing blood clots and tumours in human body
(b) Treatment of cancer
(c) Treatment of Goitre
(d) Nuclear reactor as a fuel.
Answer:
Radioactive isotopes: These are unstable isotopes due to extra neutrons in their nucleus and emits different types of radiations.
Examples:

  • Uranium – 235
  • Cobalt – 60
  • Carbon – 14.

Types of Isotopes used in:
(a) Sodium – 24 to detect blood clots and Arsenic – 72 to detect tumours.
(b) Cobalt – 60
(c) Iodine-131
(d) Uranium – 235.

Question 10.
Draw the atomic structure of:
(a) Fluorine atom (F)
(b) Sodium atom (Na)
(c) Potassium atom (K)
Answer:
(a) Fluorine atom (F):
Atomic number: 9
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 23

(b) Sodium atom (Na)
Atomic number: 11
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 24

(c) Potassium atom (K)
Atomic number: 19
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 25

Question 11.
Write the atomic number, mass number, electrons, protons and neutrons of following atoms:
(a) \(_{ 14 }^{ 24 }{ X }\)
(b) \(_{ 13 }^{ 27 }{ X }\)
Answer:
(a) \(_{ 14 }^{ 24 }{ X }\)
Atomic number = 14
Mass number = 24
Electrons = 14
Protons = 14
Neutrons = 24 – 14 = 10

(b) \(_{ 13 }^{ 27 }{ X }\)
Atomic number = 13
Mass number = 27
Electrons = 13
Protons = 13
Neutrons = 27 – 13 = 14

Question 12.
Pick out the Isotopes and Isobars from the following atoms:
\(_{ 17 }^{ 37 }{ A }\), \(_{ 18 }^{ 40 }{ A }\), \(_{ 17 }^{ 33 }{ A }\), \(_{ 20 }^{ 40 }{ A }\).
Answer:

  1. Isotopes: \(_{ 17 }^{ 37 }{ A }\), \(_{ 17 }^{ 33 }{ A }\)
  2. Isobars: \(_{ 18 }^{ 40 }{ A }\), \(_{ 20 }^{ 40 }{ A }\).

Question 13.
What are noble gases? Why they are stable? Give three examples.
Answer:
Noble gases are the elements which are stable and do not take part in chemical reaction.
They are stable because they have completely filled outer- most shell with 8 electrons
example:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 26
Helium is the only noble gas which has 2 electrons in outermost shell.

Question 14.
Write all the Isotopes of:

  1. Hydrogen
  2. Oxygen
  3. Chlorine
  4. Bromine
  5. Carbon
  6. Neon.

Answer:

  1. Hydrogen (H) – \(_{ 1 }^{ 1 }{ H }\), \(_{ 1 }^{ 2 }{ H }\)
  2. Oxygen (O) – \(_{ 8 }^{ 16 }{ O }\), \(_{ 8 }^{ 17 }{ O }\), \(_{ 8 }^{ 18 }{ O }\)
  3. Chlorine (Cl) – \(_{ 17 }^{ 35 }{ Cl }\), \(_{ 17 }^{ 37 }{ Cl }\)
  4. Bromine (Br) – \(_{ 35 }^{ 79 }{ Br }\), \(_{ 35 }^{ 81 }{ Br }\)
  5. Carbon (C) – \(_{ 6 }^{ 12 }{ C }\), \(_{ 6 }^{ 14 }{ C }\)
  6. Neon (Ne) –  \(_{ 10 }^{ 20 }{ Ne }\), \(_{ 10 }^{ 21 }{ Ne }\), \(_{ 10 }^{ 22 }{ Ne }\)

Question 15.
Why is it wrong to say that atomic number of an atom is equal to its number of electrons?
Answer:
We know that in an atom number of electrons is equal to the number of protons. But, we cannot say that atomic number is equal to number of electrons because number of electrons can be changed after losing or gaining by an atom during chemical reaction. But, number of protons remain constant.

Question 16.
What explanation did Neils Bohr gave on stability of atoms?
Answer:
Neils Bohr explained the stability of atom through following points:

  1. The electrons revolve around the nucleus in fixed orbits or energy levels or shells and each orbit has its fixed radius.
  2. While revolving electrons do not radiate their energies, so they do not fall into the nucleus and make the atom stable.

Question 17.
What are nucleons? What is the name given to the atoms having same number of nucleons?
Answer:
Protons and neutrons together in the nucleus are called nucleons. It means number of nucleons is equal to the sum of protons and neutrons. Atoms having same number of nucleons are called isobars.

Structure of the Atom Long Answer Types Questions

Question 1.
The average atomic mass of a sample of an element X is 13u. What are the percentages of isotopes \(_{ 6 }^{ 12 }{ X }\) and \(_{ 6 }^{ 14 }{ X }\) in the sample?
Answer:
Let, the percentage of isotope \(_{ 6 }^{ 12 }{ X }\) be x%.
So, percentage of isotope \(_{ 6 }^{ 14 }{ X }\) is (100- x) %.
Now, Average atomic mass = Mass of \(_{ 6 }^{ 12 }{ X }\) + Mass of \(_{ 6 }^{ 14 }{ X }\) According to percentages,
∴ 13 = x% of 12 + (100 – x)% of 14
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 27
∴ 13 × 100 = 1400 – 2x
1300 = 1400 – 2x
1300 = 1400 – 2x
-100 = -2x
x = \(\frac { 100 }{2 }\) = 50
So, percentage of \(_{ 6 }^{ 12 }{ X }\) is 50% and percentage of \(_{ 6 }^{ 14 }{ X }\) is
= (100 – x)%
= (100 – 50)%
= 50%

MP Board Solutions

Question 2.
Explain Rutherford’s Gold Foil Experiment. Also, explain its observations conclusion, theory proposed and drawback of his model.
Answer:
Ernest Rutherford performed an alpha-particles scattering experiment in which he passed a-particles on the gold foil.
Observation:

  1. Most of α – particles passed straight without any deflection.
  2. Some of the α – particles get deflected from their path.
  3. Very few α – particles get completely bounced back.

Conclusions:

  1. Maximum space in an atom is vacant as most of α – particles passed straight without any deflection.
  2. Some α – particles get deflected from their paths show the existence of positive charge in the atom.
  3. Very few α – particles get completely bounced back indicating the concentration of all mass with positive charge in a small volume at the centre.

Theory proposed:

  1. There is an existence of positively charged centre in the atom called nucleus which contains all the mass of the atom.
  2. The electrons revolve around the nucleus in circular paths called orbits at high speeds.
  3. The size of nucleus (centre of the atom) is very small as compared to size of the atom.
  4. Most of the space in an atom is empty.

Drawback: Rutherford’s model did not explain the stability of the atom. He proposed that electron revolves around the nucleus in circular paths. So, electrons should radiate their energies as they are continuously in circular motion. Then, they should fall into the positively charged nucleus making the atom unstable and collapse.

Question 3.
Draw the electronic structure of sodium and calcium with atomic number 11 and 20 respectively.
Answer:
Sodium has electronic distribution as 2, 8, 1
Calcium has electronic distribution as 2, 8, 8, 2
Electronic structures of sodium and calcium are given:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 28

Question 4.
Both helium (He) and beryllium (Be) have two valence electrons. Whereas ‘He’ represents a noble gas element, ‘Be’ does not. Assign reason.
Answer:
The element He (Z = 2) has two electrons present in the only shell
i.e., K – shell. Since, this shell can have a maximum of two electrons only therefore,
‘He’ is a noble gas element.
The element ‘Be’ (Z = 4) has the electronic configuration as: 2,2.
Although, the second shell has also two electrons but it do not represent a noble gas element.

Structure of the Atom Higher Order Thinking Skills (HOTS)

Question 1.
Which isotope of hydrogen contain same number of electrons, protons and neutrons?
Answer:
Deuterium (\(_{ 1 }^{ 2 }{ D }\))
Number of electron (1) = Number of proton (1)
= Number of neutron (2 – 1 = 1)

Question 2.
Which element of these two would be chemically more reactive: element A with atomic number 18 or element B with atomic number 16 and why?
Answer:
Electric configuration of

  • A – 2,8,8
  • B – 2, 8, 6

Since, the outermost shell of A is complete, it would be inert and will not react. Whereas element B require two atoms to complete its octet. Therefore, B would be more reactive.

Structure of the Atom Value Based Question

Question 1.
Shivek could not solve the following question in the group. His group – mate explained him and solved his difficulty.
The question was as follows:
MP Board Class 9th Science Solutions Chapter 4 Structure of the Atom 29
What information do you get from the given figure about the atomic number, mass number and valency of the given atom ‘X’:

  1. What is the atomic number, the mass number and valency of the atom?
  2. Name the element ‘X’.
  3. What value of Shivek’s friend are reflected in this behaviour?

Answer:

  1. The atomic number is 5, The mass number is 11, The valency is 3.
  2. The element ‘X’ is boron.
  3. Shivek’s friend showed the values of helping and caring nature.

MP Board Class 9th Science Solutions