MP Board Class 9th Science Solutions Chapter 12 Sound

MP Board Class 9th Science Solutions Chapter 12 Sound

Sound Intext Questions

Sound Intext Questions Page No. 162

Question 1.
How does the sound produced by a vibrating object in a medium reach your ear?
Answer:
When an object vibrates, it allows the particles of the medium around it to vibrate. It exerts force on the adjacent particles and continue oscillating in all directions and one of it, hit our ear’s medium which creates sound. This process continues in the medium till the sound reaches your ear.

Sound Intext Questions Page No. 163

Question 1.
Explain how sound is produced by your school bell.
Answer:
When the bell rings, it continues to move forward and backward which creates vibration and simultaneously a series of compressions and rarefactions which produce a very loud sound.

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Question 2.
Why are sound waves called mechanical waves?
Answer:
Sound waves needs medium to propagate therefore, they are called mechanical waves. Sound cannot travel in the absence of a medium. Sound waves are propagated through a medium because of the interaction of the particles present in that medium.

Question 3.
Suppose you and your friend are on the moon. Will you be able to hear any sound produced by your friend?
Answer:
No, because sound waves needs a medium through which they can propagate. And since there is no medium on the moon due to absence of atmosphere, one cannot hear any sound produced by his / her friend on the moon.

Sound Intext Questions Page No. 166

Question 1.
Which wave property determines.

  1. loudness
  2. pitch?

Answer:

  1. Amplitude determines loudness of a sound wave.
  2. Frequency determines pitch of a sound wave.

Question 2.
Guess which sound has a higher pitch: guitar or car horn?
Answer:
Guitar has a higher pitch than car horn, because sound produced by the strings of guitar has higher frequency and since pitch is proportional to frequency, pitch of guitar will be higher.

MP Board Solutions

Question 3.
What are wavelength, frequency, time period and amplitude of a sound wave?
Answer:

  1. Wavelength: Wave length is the length between two consecutive peaks it is represented by Greek letter λ (lambda). Louder sound has shorter wavelength and softer sound has longer wavelength.
  2. Frequency: The number of sound waves produced in unit time is called the frequency of sound waves. Frequency is measured in seconds. Frequency is denoted by Greek letter v (nu). The SI unit of frequency is ‘hertz’.
  3. Amplitude: Amplitude of a wave is magnitude of maximum disturbance on either side of the normal position or mean value in a medium.

Question 4.
How are the wavelength and frequency of a sound wave related to its speed?
Answer:
Speed, wavelength, and frequency of a sound wave are related as follows:
Speed (ν) = Wavelength [λ] × Frequency (v)
⇒ ν = λ × v

Question 5.
Calculate the wavelength of a sound wave whose frequency is 220 Hz and speed is 440 m/s in a given medium.
Answer:
Given,
Frequency of the sound wave, v = 220 Hz
Speed of the sound wave, u = 440 ms-1
Putting the equations,
Speed = Wavelength (λ) × Frequency (v)
ν = λ × v
∴ λ = \(\frac { ν }{ v  }\) = \(\frac { 440 }{ 220 }\) = 2 m
Hence, Wavelength = 2 m.

Question 6.
A person is listening to a tone of 500 Hz sitting at a distance of 450 m from the source of the sound. What is the time interval between successive compressions from the source?
Answer:
Given,
Frequency = 500 Hz
Distance = 450 m
Since, T = \(\frac { 1 }{ Frequency }\)
= \(\frac { 1 }{ 500 }\) = 0.002 sec.
Hence, person will listen the sound after every 0.002 sec.

Question 7.
Distinguish between loudness and intensity of sound.
Answer:
Intensity drives loudness of a sound. These both qualities of sound are proportional to each other. The amount of sound passing through a unit area per second represents intensity of a sound wave. While loudness is the response of the ear to the sound (amount received to pinna). The loudness of a sound is defined by its amplitude. The amplitude of a sound decides its intensity, which in turn is perceived by the ear as loudness.

Sound Intext Questions Page No. 167

Question 1.
In which of the three media, air, water or iron, does sound travel the fastest at a particular temperature?
Answer:
Sound travels the fastest in solids medium (here Iron) then in liquids (water) and it is the slowest in gases (air). Therefore, for a given temperature, sound travels as follows (decreasing order): ⇒ Iron > water >air.

Sound Intext Questions Page No. 168

Question 1.
An echo returned in 3s. What is the distance of the reflecting surface from the source, given that the speed of sound is 342 ms-1?
Answer:
Given,
Speed, v = 342 ms-1
Time, t = 3 s
Since, Distance = v × t
= 342 × 3 = 1026 m
Condition,
In fixed time interval, sound has to travel a distance that is twice the distance of the reflecting surface and the source.
Hence, the distance of the reflecting surface from the source = \(\frac { 1026 }{ 2 }\) m = 513 m.

Sound Intext Questions Page No. 169

Question 1.
Why are the ceilings of concert halls curved?
Answer:
Ceilings of concert halls are curved to:

  1. Enhance loudness and echo of sound created.
  2. Sound after reflection (from the walls) spreads uniformly in all directions.

Sound Intext Questions Page No. 170

Question 1.
What is the audible range of the average human ear?
Answer:
The audible range of an average human ear is between 20 Hz to 20,000 Hz.

Question 2.
What is the range of frequencies associated with

  1. Infrasound?
  2. Ultrasound?

Answer:

  1. Infrasound: frequencies less than 20 Hz.
  2. Ultrasound: frequencies more than 20,000 Hz.

Sound Intext Questions Page No. 172

Question 1.
A submarine emits a sonar pulse, which returns from an underwater cliff in 1.02 s. If the speed of sound in salt water is 1531 m/s, how far away is the cliff?
Answer:
Given,
Time taken by the sonar pulse to return, t = 1.02s
Speed of sound in salt water, v = 1531 ms-1
Distance of the cliff from the submarine = Speed of sound × Time taken
= 1531 × 1.02 m = 1561.62 m
Distance travelled by the sonar pulse during its transmission and reception in water
= 2 × Actual distance = 2d
Actual distance,
d = Distance of the cliff from the submarine / 2 = \(\frac { 1561 }{ 2 }\) = 780.31 m.

MP Board Solutions

Sound NCERT Textbook Exercises

Question 1.
What is sound and how is it produced?
Answer:
Sound is a form of energy which is received at our ear pinna and gives the sensation of hearing. It is a vibration which propagates in air and developed by vibrating objects.

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Question 2.
Describe with the help of a diagram, how compressions and rarefactions are produced in air near a source of sound.
Answer:
When vibration is produced by a body, it moves in backward and forward direction till the energy lasts. During forward movement it creates a region of high pressure. This region of high pressure is known as compressions. When it moves backward, it creates a region of low pressure. This region is known as a rarefaction. This is shown in figure given below.
MP Board Class 9th Science Solutions Chapter 12 Sound 1
Here,
C = compressions
R = rarefaction.

Question 3.
Cite an experiment to show that sound needs a material medium for its propagation.
Answer:
Arrange the instrument according to the picture given below:
MP Board Class 9th Science Solutions Chapter 12 Sound 2

  • Take an electric bell and an air tight jar with glass bell and connect it to a vacuum pump.
  • Suspend the bell inside the jar, and press the switch of the bell.

Method: Now pump out the air from the glass jar. The sound of the bell will become fainter and after some time, the sound will not be heard. This shows that sound needs a material medium to travel.

Question 4.
Why is sound wave called a ‘longitudinal wave’?
Answer:
Sound wave is called longitudinal wave because the air particles vibrates parallel to the direction of propagation of sound wave,it is produced by compressions and rarefactions in the air.

Question 5.
Which characteristics of the sound helps you to identify your friend by his voice while sitting with others in a dark room?
Answer:
The quality of pitch and loudness of sound enables us to identify our friend by his voice.

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Question 6.
Flash and thunder are produced simultaneously. But thunder is heard a few seconds after the flash is seen, why?
Answer:
Speed difference is the main reason of this happening. The speed of sound (344 m/s) is very less than the speed of light (3 × 108 m/s). A flash is seen before we hear a thunder because sound of thunder takes more time to reach the Earth as compared to light.

Question 7.
A person has a hearing range from 20 Hz to 20 kHz. What are the typical wavelengths of sound waves in air corresponding to these two frequencies? Take the speed of sound in air as 344 ms-1.
Answer:
We know,
Speed (ν) = Wavelength × Frequency v
ν = λ × v
Given,
Speed of sound in air ν = 344 m/s (Given)

(i) For, v = 20 Hz
λ1 = \(\frac { ν }{ v }\)
= \(\frac { 344 }{ 20 }\) = 17.2 m

(ii) For, v = 20000 Hz
12 = \(\frac { ν }{ v }\)
= \(\frac { 344 }{ 20000 }\) = 0.172 m
Hence, for humans, the wavelength range for hearing is 0. 0172 m to 17.2 m.

Question 8.
Two children are at opposite ends of an aluminium rod. One strikes the end of the rod with a stone. Find the ratio of time taken by the sound wave in air and in aluminium to reach the second child.
Answer:
Velocity of sound in air= 346 m/s
Velocity of sound waves in aluminium 6420 m/s
Let length of rod be 1.
Time taken for sound wave in air, t1 = \(\frac { 1 }{ Velocity }\) in air.
Time taken for sound wave in aluminium, t2 = \(\frac { 1 }{ Velocity }\) in aluminium.
Therefore,
MP Board Class 9th Science Solutions Chapter 12 Sound 6
= \(\frac { 6420 }{ 346 }\) = 18.55.

Question 9.
The frequency of a source of sound is 100 Hz. How many times does it vibrate in a minute?
Answer:
Frequency =100 Hz. (Given)
This means the source of sound vibrates 100 times in one second.
Therefore, number of vibrations in 1 minute, i.e. in 60 seconds = 100 × 60 = 6000 times.

Question 10.
Does sound follow the same laws of reflection as light does? Explain.
Answer:
Yes, sound waves also follow the same laws of reflection as light wave do because:

  1. Angle of incidence of sound is always equal to that of angle of reflection of sound waves.
  2. The direction in which sound is incident, the direction in which it is reflected and normal all lie in the some plane.

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Question 11.
When a sound is reflected from a distant object, an echo is produced. Let the distance between the reflecting surface and the source of
sound production remains the same. Do you hear echo sound on a hotter day?
Answer:
An echo is heard when the time for the reflected sound is just 0.1 s
Time taken = \(\frac { Total Distance }{ Velocity }\)
On a hotter day, due to lighter medium the velocity of sound is more then a colder day. Hence, sound wave will move faster and if time taken by echo is less than 0.1 sec it will not be heard.

Question 12.
Give two practical applications of reflection of sound waves.
Answer:
Two practical applications of reflection of sound waves are:

  1. Reflection of sound is used to measure the distance and speed of underwater objects. This method is known as SONAR.
  2. Working of a stethoscope is also based on reflection of sound. In a stethoscope, the sound of the patient’s heartbeat reaches the doctor’s ear by multiple reflection of sound.

Question 13.
A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g = 10 ms-2 and speed of sound = 340 ms-1.
Answer:
Height of the tower, s = 500 m
Velocity of sound, v = 340 ms-1
Acceleration due to gravity, g = 10 ms-2
Initial velocity of the stone, u = 0 (since the stone is initially at rest)
Time taken by the stone to fall to the base of the tower t1,
According to the second equation of motion:
s = ut1 + \(\frac { 1 }{ 2 }\) gt12
500 = 0 × t1 + \(\frac { 1 }{ 2 }\) × 10 t12
t12 = 500
t1 = 10 s
Now, time taken by the sound to reach the top from the base of the tower,  t2 = \(\frac { 500 }{ 340 }\) = 1.47 s.
Therefore, the splash is heard at the top after time, t Where, t = t1 + t2 = 10 + 1.47 = 11.47 s.

Question 14.
A sound wave travels at a speed of 339 ms-1. If its wavelength is 1.5 cm, what is the frequency of the wave? Will it be audible?
Answer:
Speed of sound, v = 339 ms-1
Wavelength of sound, λ = 1.5 cm = 0.015 m
Speed of sound = Wavelength × Frequency
ν = λ × v
∴ v = \(\frac { ν }{ λ }\)
= \(\frac { 339 }{ 0.015 }\)
= 22600 Hz.
The frequency range of audible sound for humans lies between 20 Hz to 20,000 Hz.
Since, the frequency of the given sound is more than 20,000 Hz, it is not audible.

Question 15.
What is reverberation? How can it be reduced?
Answer:
The repeated multiple reflections of sound in any big enclosed space is known as reverberation. The reverberation can be reduced by covering the ceiling and walls of the enclosed space with sound absorbing materials, such as fibre board, loose woollens, etc.

Question 16.
What is loudness of sound? What factors does it depend on?
Answer:
The effect produced in the brain by the sound of different frequencies is called loudness of sound. Loudness depends on the amplitude of vibrations. In fact, loudness is proportional to the square of the amplitude of vibrations.

Question 17.
Explain how bats use ultrasound to catch a prey.
Answer:
Bats produce high – pitched ultrasonic squeaks. These high – pitched squeaks are reflected by objects such as preys and returned to the bat’s ear. This allows a bat to know the distance of his prey.

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Question 18.
How is ultrasound used for cleaning?
Answer:
Objects to be cleansed are put in a cleaning solution and ultrasonic sound waves are passed through that solution. The high frequency of these ultrasound waves detaches the dirt from the objects.

Question 19.
Explain the working and application of a SONAR.
Answer:
Sonar stands for Sound Navigation And Ranging. It is a device used to measure the depth, direction and speed of under – water objects such as submarines and ship wrecks with the help of ultrasounds and is also used to measure the depth of seas and oceans. An ultrasonic sound is produced and transmitted by the transducer (it is a device that produces ultrasonic sound) of the Sonar, which travels through sea water.

The echo produced by the reflection of this ultrasonic sound is detected and recorded by the detector, which is converted into electrical signals. The distance (d) of the under – water object is calculated from the time (t) taken by the echo to return with speed (v) is given by 2d = v × t.
MP Board Class 9th Science Solutions Chapter 12 Sound 3

Question 20.
A SONAR device on a submarine sends out a signal and receives an echo 5 s later. Calculate the speed of sound in water if the distance of the object from the submarine is 3625 m.
Answer:
Given,
Time taken to hear the echo, t = 5 s
Distance of the object from the submarine, d = 3625 m
Total distance travelled by the sonar waves during the transmission and reception in water = 2d
Using formula:
Velocity of sound in water,
v = 2 \(\frac { d }{ t }\)
= 2 × \(\frac { 3625 }{ 5 }\) = 1450 ms-1.

Question 21.
Explain how defects in a metal block can be detected using ultrasound.
Answer:
Defects in metal blocks do not allow ultrasound to pass through them and they are reflected back. This fact is used to detect defects in metal blocks. Ultrasound is passed through one end of a metal block and detectors are placed on the other end. The defective part of the metal block does not allow ultrasound to pass through it. As a result, it will not be detected by the detector. Hence, defects in metal blocks can be detected using ultrasound.
MP Board Class 9th Science Solutions Chapter 12 Sound 4

Question 22.
Explain how the human ear works.
Answer:
The human ear consists of three parts – the outer ear, middle ear and inner ear.

  1. Outer ear: It is also termed ‘pinna’. It collects the sound from the surrounding and directs it towards auditory canal.
  2. Middle ear: It is at the auditory canal where there is a thin membrane called eardrum or tympanic membrane. The sound waves set this membrane to vibrate. These vibrations are amplified by three small bones hammer, anvil and stirrup.
  3. Inner ear: When vibration reach the cochlea in the inner ear and are converted into electrical signals which are sent to the brain by the auditory nerve, and the brain interprets them as sound.
    MP Board Class 9th Science Solutions Chapter 12 Sound 5

Sound Additional Questions

Sound Multiple Choice Questions

Question 1.
Which of the following waves have no requirement of any medium to propagate?
(a) sound
(b) radio
(c) light waves
(d) none of above.
Answer:
(c) light waves

Question 2.
What kinds of waves are produced by sound?
(a) longitudinal only
(b) transverse waves only
(c) electromagnetic Waves
(d) both Longitudinal and Transversal.
Answer:
(a) longitudinal only

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Question 3.
When a wave propagate, it transfers ___________ .
(a) energy only
(b) matter only
(c) both energy and matter
(d) none of these.
Answer:
(a) energy only

Question 4.
Note is a sound ___________ .
(a) of mixture of several frequencies
(b) of mixture of two frequencies only
(c) of a single frequency
(d) always unpleasant to listen.
Answer:
(a) of mixture of several frequencies

Question 5.
A key of a mechanical piano struck gently and then struck again but much harder this time. In the second case:
(a) sound will be louder but pitch will not be different.
(b) sound will be louder and pitch will also be higher.
(c) sound will be louder but pitch will be lower.
(d) both loudness and pitch will remain unaffected.
Answer:
(d) both loudness and pitch will remain unaffected.

Question 6.
Earthquake produces which kind of sound before the main shock wave begins ___________ .
(a) ultrasound
(b) Infrasound
(c) audible sound
(d) none of the above.
Answer:
(b) Infrasound

Question 7.
Infrasound can be heard by ___________ .
(a) dog
(b) bat
(c) rhinoceros
(d) human beings.
Answer:
(c) rhinoceros

Question 8.
Before playing the orchestra in a musical concert, a sitarist tries to adjust the tension and pluck the string suitably. By doing so, he is adjusting ___________ .
(a) intensity of sound only.
(b) amplitude of sound only.
(c) frequency of the sitar string with the frequency of other musical instruments.
(d) loudness of sound.
Answer:
(c) frequency of the sitar string with the frequency of other musical instruments.

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Question 9.
What we term to the number of oscillations completed in one second?
(a) time period
(b) velocity
(c) frequency
(d) wavelength.
Answer:
(c) frequency

Question 10.
Sound waves which can be propagate in solids are ___________ .
(a) Longitudinal only.
(b) Transverse only.
(c) Either longitudinal or transverse.
(d) Non mechanical waves only.
Answer:
(c) Either longitudinal or transverse.

Question 11.
In SONAR, we use ___________ .
(a) ultrasonic waves
(b) infrasonic waves
(c) radio waves.
(d) audible sound waves.
Answer:
(a) ultrasonic waves

Question 12.
Sound travels in air if ___________ .
(a) particles of medium travel from one place to another.
(b) there is no moisture in the atmosphere.
(c) disturbance moves.
(d) both particles as well as disturbance travel from one place to another.
Answer:
(c) disturbance moves.

Question 13.
When we change feeble sound to loud sound we increases ___________ .
(a) Frequency
(b) Amplitude
(c) Velocity
(d) Wavelength.
Answer:
(b) Amplitude

Question 14.
In the curve (Figure) half the wavelength is ___________ .
image
(a) AB
(b) BD
(c) DE
(d) AE
Answer:
(a) AB

Question 15.
The time taken to complete an osoillation ___________ .
(a) time period
(b) velocity
(c) frequency
(d) wavelength.
Answer:
(a) time period

Question 16.
The period of a vibrating body of frequency 100 Hz is ___________ .
(a) 100 seconds
(b) 10 seconds
(c) 0.1 second
(d) 0.01 second.
Answer:
(a) 100 seconds

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Question 17.
Which of the following is SI unit of amplitude?
(a) metre
(b) s-1
(c) metre / second
(d) Hertz.
Answer:
(a) metre

Question 18.
The quantity λ is known as ___________ .
(a) wave velocity
(b) frequency
(c) wavelength
(d) wave number.
Answer:
(c) wavelength

Question 19.
Sound wave of which of the following frequency is an ultrasonic sound?
(a) 30 Hz
(b) 300 Hz
(c) 3000 Hz
(d) 30,000 Hz.
Answer:
(d) 30,000 Hz.

Question 20.
In which of the following, speed of the sound is maximum?
(a) air
(b) water
(c) steel
(d) kerosene.
Answer:
(c) steel

Sound Very Short Answer Type Questions

Question 1.
How does sound travels in gases and liquids – as longitudinal or as transverse waves?
Answer:
As longitudinal waves.

Question 2.
Give examples of longitudinal waves.
Answer:
Sound waves.

Question 3.
What is speed of sound in air?
Answer:
At 0° C, it is 331 m/s. At 20°C, it is 341 m/s.

Question 4.
What is reverberation?
Answer:
The repeated reflection that results in the persistence of sound is called reverberation.

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Question 5.
Among solids, liquids and gases sound travels faster in which medium?
Answer:
Sound travels the fastest in solids.

Question 6.
What is one Hz?
Answer:
Hz is the unit of frequency, called as Hertz. One Hertz is equal to one cycle per second.

Question 7.
What is ‘note’ of second?
Answer:
The sound produced due to a mixture of several frequency is called a note, it is pleasant to listen to.

Question 8.
What is pitch?
Answer:
The way our brain interprets the frequency of an emitted sound is called the pitch.

Sound Short Answer Type Questions

Question 1.
What is Sound? Why it is important for us?
Answer:
Sound is a longitudinal mechanical wave. Sound has great importance in our daily life. It gives us a sensation of hearing. It makes it possible to communicate with other persons through speech.

Question 2.
What is a mechanical wave?
Answer:
A mechanical wave is a disturbance that moves through a medium when the particles of the medium set neighbouring particles into motion. The particles vibrating in turn do not move forward but the disturbance is carried forward.

Question 3.
What is a longitudinal wave?
Answer:
If the particles of a medium vibrate in a direction, parallel to or along the direction of propagation of wave, it is called longitudinal wave.

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Question 4.
What type of waves can travel in vacuum? Give example(s).
Answer:
Electromagnetic waves can travel in vacuum. Sun light, x – rays are examples of electromagnetic waves.

Question 5.
Suppose you and your friend are on the Moon. Will you be able to hear any sound produced by your friend?
Answer:
No, we will not hear any sound on the Moon. The Moon does not have any atmosphere, since sound is a mechanical wave and requires a medium to travel.

Question 6.
What are the factors, speed of sound wave depends upon?
Answer:
Speed of the sound depends on the following factors:

  1. Inertial property of the medium (to store kinetic energy).
  2. Elastic property of the medium (to store potential energy).
  3. Temperature of the medium.
  4. Density of the medium.
  5. Humidity present in the medium (in air / gases).

Question 7.
Three persons A, B and C are made to hear a sound travelling through different mediums as given below:

PersonsMedium
AIron Rod
BAir
Cwater

Who will hear the sound first ? Why ?
Answer:
Person A will hear the sound first because sound travels the faster in solids than in liquids and gases.

Question 8.
If 20 waves are produced per second, what is the frequency in hertz?
Answer:
Number of waves per second is known as frequency.
∴ Frequency (v) = 20 Hz.

Question 9.
What is echo?
Answer:
The sound waves produced bounce back or gets reflected from the mountains or buildings and come to our ears, this reflected sound is known as Echo. To hear echo, the barrier reflecting the sound should be atleast at a distance of 17 metres.

MP Board Solutions

Question 10.
What is infrasonic? Give an example.
Answer:
Sound having frequency less than 20 Hz is known as infrasonic sound or infrasonic. Waves produced during earthquake are infrasonic.

Sound Long Answer Type Questions

Question 1.
Establish the relationship between speed of sound, its wave length and frequency. If velocity of sound in air is 340 m s-1, calculate:

  1. wavelength when frequency is 256 Hz.
  2. frequency when wavelength is 0.85 m.

Answer:
Derivation of formula ν = v λ

  1. 340 = 256 λ ⇒ λ = 1.33 m.
  2. 340 = v (0.85) ⇒ v = 400 Hz.

Question 2.
A girl is sitting in the middle of a park of dimension 12 m × 12 m. On the left side of it there is a building adjoining the park and on right side of the park, there is a road adjoining the park. A sound is produced on the road by a cracker. Is it possible for the girl to hear the echo of this sound? Explain answer.
Answer:
If the time gap between the original sound and reflected sound received by the listener is around 0.1 s, only then the echo can be heard. The minimum distance travelled by the reflected sound wave for the distinctly listening the echo, distance = velocity of sound × time interval;
= 344 × 0.1 = 34.4 m.
But, in this case the distance travelled by the sound reflected from the building and then reaching the girl will be (6 + 6 = 12 m),  which is much smaller than the required distance. Therefore, no echo can be heard.

Sound Higher Order Thinking Skills (HOTS)

Question 1.
A key of piano is struck gently and then struck again but much harder this time. What will happen in the second case?
Answer:
In second case, the loudness will increase as this will increase the amplitude of vibration of string. Pitch and frequency will also increase in force or tension in the string.

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Question 2.
At a hill station, a child could hear the echo of his voice after 0.2 s. But, when he went to the same place in the afternoon, he could not hear echo at all. What could be the reason?
Answer:
In afternoon, the temperature rises, therefore the speed of sound also increased. The reflected sound will take very less time to travel back and no echo is heard.

Sound Value Based Question

Question 1.
It is not advisable to construct houses near airports, inspite of that many new residential apartments are constructed near airports. Rajesh / Sumit files RTI and also complains the municipal office about the same.

  1. Why one should not reside near airport?
  2. Name other two places where there is noise pollution.
  3. What value of Rajesh is reflected in this act?

Answer:

  1. The landing and taking off of the air – planes causes lot of noise-pollution which may lead to deafness, high blood pressure and other health problems.
  2. The other two places where there is noise-pollution are residing near the heavy traffic routes and railway stations or lines.
  3. Rajesh shows participating citizen and moral responsibility values.

MP Board Class 9th Science Solutions

MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.3

MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.3

Question 1.
Draw different pairs of circles. How many points does each pair have in common? What is the maximum number of common points?
Solution:
Let us draw different pairs of circles as shown below:
MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.3 img-1
We gave,
In figure           Maximum number of common points
(i)             –                     nil
(ii)            –                    one
(iii)           –                    two
Thus, two circles can have at the most two points in common.

Question 2.
Suppose you are given a circle. Give a construction to find its center.
Solution:
Steps of construction:

  1. Mark any three points A, B and C on the circle.
    MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.3 img-2
  2. Join AB and BC.
  3. Draw the perpendicular bisector of AS. Let it be PQ.
  4. Draw the perpendicular bisector of BC. Let it be RS.
  5. PQ and RS intersect at point O.
  6. O is the center of given circle.

MP Board Solutions

Question 3.
If two circles intersect at two points, prove that their centers lie on the perpendicular bisector of the common chord.
Solution:
Given:
Circles C(O, r) and C(D, r1) intersect at A and B.
To prove:
OD is perpendicular bisector of AS.
MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.3 img-3
Construction:
Join OA, AD, OB and BD.
Proof:
In ∆AOD and ∆BOD,
OA = OB
DA = DB (Radii of the circle)
OD = OD (Common)
∆AOD ≅ ∆BOD (By SXS)
and ∠1 = ∠2 (By CPCT)
In ∆OAC and ∆OBC,
OA = OB (Radii of the circle)
OC =OC (Common)
∠1 = ∠2 (Proved)
∆AOC = ∆OBC (By SAS)
So ∠3 = ∠4 (By CPCT)
and AC = BC (By CPCT)
∠3 + ∠4 = 180.°
2∠3 = 180°
∠3 = \(\frac{180^{\circ}}{2}\) =90° (UA’s)
OD is perpendicular bisector of AB.

MP Board Class 9th Maths Solutions

MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.2

MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.2

Question 1.
Recall that two circles are congruent if they have the same radii. Prove that equal chords of congruent circles subtend equal angles at their centers.
Solution:
We have a circles having its centers at O and O’ two equal chords AB and CD such that they subtend ∠AOB and ∠COD respectively at their centers, i.e. at O and O’.
MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.2 img-1
We have to prove that
∠AOB = ∠CO’D
Now, in ∆AOB and ∆CO’D, we have
AO = CO’ [Radii of the same circle]
BO = DO’ [Radii of the same circle]
AB = CD [Given]
∆AOB = ∆CO’D [SSS criterion]
Their corresponding parts are equal.
∴ ∠AOB = ∠CO’D

MP Board Solutions

Question 2.
Prove that if chords of congruent circles subtend equal angles at their centers, then the chords are equal.
Solution:
We have circles having their centers at O and O’, and its two chords AB and CD such that
∠AOB = ∠CO’D
we have to prove that
AB = CD
In ∆AOB and ∆COO’D, we have:
AO = CO’ [Radii of the same circle]
BO = DO’ [Radii of the same circle]
∠AOB = ∠CO’D [Given]
∆AOB = ∆CO’D [SAS criterion]
Their corresponding parts are equal, i.e.,
AB = CD.
MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.2 img-2

MP Board Class 9th Maths Solutions

MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.1

MP Board Class 9th Maths Solutions Chapter 10 Circles Ex 10.1

Question 1.
Fill in the blanks:

  1. The center of a circle lies in …………of the circle.
  2. A point, whose distance from the center of a circle is greater then its radius lies in …………..of the circle.
  3. The longest chord of a circle is a ………… of the circle.
  4. An arc is a ………….. when its ends are the ends of a diameter.
  5. Segment of a circle is the region between an arc and ……….. of the circle.
  6. A circle divides the plane, on which it lies, in ……….. parts.

Solution:

  1. interior
  2. exterior
  3. diameter
  4. semicircle
  5. the chord
  6. three.

MP Board Solutions

Question 2.
Write True or False. Give reasons for your answers.

  1. Line segment joining the center to any point on the circle is a radius of the circle.
  2. A circle has only finite number of equal chords.
  3. If a circle is divided into three equal arcs, each is a major arc.
  4. A chord of a circle, which is twice as long as its radius, is a diameter of the circle.
  5. Sector is the region between the chord and its corresponding arc.
  6. A circle is a plane figure.

Solution:

  1. True [∵ All points on the circle are equidistant from the center]
  2. False [∵ A circle can have an infinite number of equal chords.]
  3. False [∵ Each part will be less than a semicircle.]
  4. True [∵ Diameter = 2 x Radius]
  5. False [∵ The region between the chord and its corresponding arc is a segment.]
  6. True [∵ A circle is drawn on a plane.]

MP Board Class 9th Maths Solutions

MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2

MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2

Question 1.
In fig. given below, ABCD is a parallelogram, AE ⊥ DCand CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD.
MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2 img-1
Solution:
ar (ABCD) = AE x DC ….(i)
ar (ABCD) = AD x CF ….(ii)
From (i) and (ii), we get
AE x DC = AD x CF
⇒ AE x AB = AD x CF (∵ AB = DC)
MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2 img-2
8 x 16 = AD x 10
\(\frac{8×16}{10}\) = AD
\(\frac{128}{10}\) = AD
AD = 12.8 cm.

Question 2.
If E, F, G and H are respectively the mid-points of the sides of a parallelogram ABCD, show that ar (EFGH) \(\frac{1}{2}\) = ar (ABCD)
Solution:
Given
ABCD is a ∥gm E, F, G, H, are the mid-points of AB, BC, CD and DA respectively.
MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2 img-3
To prove:
ar (EFGH) = \(\frac{1}{2}\) ar (ABCD)
Construction: Join GE.
Proof:
ABCD is a ∥gm
∴ AB ∥ DC and AB = DC
⇒ \(\frac{1}{2}\)AB ∥ \(\frac{1}{2}\)DC and \(\frac{1}{2}\) AB = \(\frac{1}{2}\) DC
AE ∥ DG and AE = DG
∴ AEGD is a parallelogram.
Similarly BCGE is also a parallelogram.
∥gm AEGD and AEGH both lie on the same base EG and are between the same parallels AD and EG.
ar (EGH) = \(\frac{1}{2}\) ar {AEGD) …(1)
Similarly ar {GEF) = \(\frac{1}{2}\) ar {BCGE) …(2)
Adding (1) and (2), we get
ar (EGH) + ar (GEF) = ar (AEGD) + \(\frac{1}{2}\) ar {BCGE)
ar (EFGH) ar {EFGH) = \(\frac{1}{2}\) [ar (AEGD) + ar (BCGE)]

MP Board Solutions

Question 3.
P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar (APB) = ar (BQC).
Solution:
Given:
ABCD is a ∥gm
To prove:
ar (APB) = ar (BQC)..
Proof:
∆APB and ∥gm ABCD lie on the same base BC and are between the same parallels AB and DC.
MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2 img-4
ar(APB) = \(\frac{1}{2}\) ar (ABCD)
∆BQC and ∥gm ABCD lie on the same base BC and are between the same parallels BC and AD.
ar (BQC) = \(\frac{1}{2}\) ar (ABCD) …(2)
From (1) and (2), we get
ar (APB) = ar (BQC)

Question 4.
In Fig. given below, P is a point in the interior of a parallelogram ABCD, Show that
MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2 img-5

  1. ar (APB) + ar (PCD) = \(\frac{1}{2}\) ar (ABCD)
  2. ar (APD) + ar (PBC) = ar (APB) + ar (PCD)

[Hint: Thorough P, draw a line parallel to AB.]
Solution:
Given:
P is any point in the interior of ∥gm ABCD.
To prove:

  1. ar (APB) + ar (PCD) \(\frac{1}{2}\) ar (ABCD)
  2. ar (APD) + ar (PBC) ar (APB) + ar (PCD)

1. Construction:
Draw a line EF passing through point P parallel to AB.
Proof:
AB ∥EF (By construction) …(1)
AB ∥ DC (∵ ABCD is a ∥gm) …(2)
EF ∥ DC [From (1) and (2)]
MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2 img-6
In quadrilateral ABFE, AB ∥ EF and AE ∥ BF (∵ AD ∥ BC)
∴ ABFE is a ∥gm
∆ APB and ∥gm ABEF lie on same base base AB and are between the same parallels AB and EF.
ar (APB) = \(\frac{1}{2}\) ar (ABFE) …. (A)
Similarly, ar (PCD) = \(\frac{1}{2}\) ar (DCFE) …(B)
Adding (A) and (B), we get
ar (APB) + ar (PCD) = \(\frac{1}{2}\) ar (ABFE) + \(\frac{1}{2}\) (DCFE)
= \(\frac{1}{2}\) [ar (ABFE) + ar (DCFE)]
= \(\frac{1}{2}\) ar (ABCD) …(3)

2. Construction:
Draw a line GH passing through point P parallel to AD.
Proof:
AD ∥ GH (by construction) …(4)
AD ∥ BC (∵ ABCD is a ∥gm) …(5)
GH ∥ BC [From (4) and (5)]
In quadrilateral ADHG,
AD ∥ GH (by construction)
and AG ∥ DH (∵ AB\\DC)
∴ ADHG is a parallelogram.
∆APD and ∥gm ADHG lie on the same base AD and lie betweeiwthe same parallels AD and GH.
ar(APD) = \(\frac{1}{2}\) ar (ADHG) …(6)
Similarly, ar (BCP) = \(\frac{1}{2}\) ar (BCHG) …(7)
Adding (6) and (7), we get
ar (APD) + ar (BCP) = \(\frac{1}{2}\) ar (ADHG) + \(\frac{1}{2}\) ar (BCHG)
= \(\frac{1}{2}\) ar (ADHG) + ar (BCHG)
= \(\frac{1}{2}\) [ar (ADHG) + ar (BCHG)]
= \(\frac{1}{2}\) ar (ABCD) …(8)
From (3) and (8), we get
ar (APB) + ar (PCD) = ar (APD) + ar (BCP)

Question 5.
In Fig. given below PQRS and ABRS are parallelograms and X is any point on side BR. Show that
MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2 img-7

  1. ar (PQRS) = ar (ABRS)
  2. ar (AZS) = \(\frac{1}{2}\) ar (PQRS)

Solution:
Given
PQRS and ABRS are H801 and X is any point on side BR.
To prove:

  1. ar (PQRS) = ar (ABRS)
  2. ar (AXS) \(\frac{1}{2}\) ar (PQRS)

Proof:
1. ∥gm PQRS and ABRS lie on the same base SR and are on the same parallels SR and PB.
∴ ar (PQRS) = ar (ABRS) …(i)

2. D AXS and ∥gm ABRS lie on the same base AS and are on the same parallels AS and BR.
ar (∆ AXS) = \(\frac{1}{2}\) ar (ABRS) …(ii)
MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2 img-8
From (i) and (ii), we get
ar (AXS) = \(\frac{1}{2}\) ar (PQRS)

MP Board Solutions

Question 6.
A farmer was having a field in the form of a parallelogram PQRS. She took any point A on RS and joined it to points P and Q. In how many parts the fields is divided? What are the shapes of these parts? The farmer wants to sow wheat and pulses in equal portions of the field separately. How should she do it?
Solution:
The field will be divided in three parts. The shapes of three parts are triangles.
Given:
PQRS is a ∥gm
To prove:
ar (APQ) = ar (APS) + ar (AQR)
Construction:
Draw a line AB ∥ SP.
Proof:
∆APQ and ∥gm PQRS are on the same base PQ and are between the same parallels PQ and SR.
MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.2 img-9
ar (PQRS) = \(\frac{1}{2}\) ar (PQRS)
⇒ 2ar (APQ) = ar (PQRS)
2ar (APQ) = ar (APS) + ar (APQ) + ar (AQR)
2ar (APQ) – ar (APQ) = ar (APQ) ar (AQR)
ar (APQ) = ar (APS) + ar (AQR)

MP Board Class 9th Maths Solutions

MP Board Class 9th Science Solutions Chapter 13 Why do we Fall Ill

MP Board Class 9th Science Solutions Chapter 13 Why do we Fall Ill

Why do we Fall Ill Intext Questions

Why do we Fall Ill Intext Questions Page No. 178

Question 1.
State any two conditions essential for good health.
Answer:
Two conditions essential for good health are:

  1. Balanced diet and good nutrition.
  2. Good social surrounding and economic wellness.

MP Board Solutions

Question 2.
State any two conditions essential for being free of disease.
Answer:
Two conditions essential for being disease – free are:

  1. Personal and community hygiene.
  2. Proper diet and economic growth.

Question 3.
Are the conditions essential for maintaining good health and being free of diseases same or different? Why?
Answer:
Yes, to some extent they are the similar, because if the conditions that are essential for good health are maintained, then the chances of getting a disease will be minimized. But at the same time, we can say that they are different because being health or good health means physical, mental and social well-being while being disease-free means not suffering from a particular disease.

Why do we Fall Ill Intext Questions Page No. 180

Question 1.
List any three reasons why you would think that you are sick and ought to see a doctor. If only one of these symptoms were present, would you still go to the doctor? Why or why not?
Answer:
Common symptoms which indicate sickness are:

  1. Headache
  2. Cough
  3. Dysentery

If only one of these symptoms is present, we usually do not visit a doctor. This is because such symptoms do not have much effect on our general health and ability to work. However, if a person is experiencing these symptoms for quite sometime, then he needs to visit a doctor for proper treatment.

Question 2.
In which of the following case do you think the long – term effects on your health are likely to be most unpleasant?

  1. If you get jaundice
  2. If you get lice
  3. If you get acne.
    Why?

Answer:
Jaundice is a disease that can cause long – term effects on our health. It is a chronic disease that lasts for a long period of time. Jaundice does not spread rapidly, but it develops slowly over a period of time.

Why do we Fall Ill Intext Questions Page No. 187

Question 1.
Why are we normally advised to take bland and nourishing food when we are sick?
Answer:
When we are sick, the normal body functions get disturbed. In such a situation, food that is easily digestible and contains adequate nutrients are required for the speedy recovery. Thus, bland and nourishing food is given during sickness.

MP Board Solutions

Question 2.
What are the different means by which infectious diseases spread?
Answer:
The different modes of transmission of infectious diseases are:

  1. Through Air: Certain disease – causing micro – organisms are expelled in air by coughing, sneezing, talking etc. These micro-organisms can travel through dust particles or water droplets in air to reach other people. For example, tuberculosis, pneumonia etc. spread through air.
  2. Through Water: Sometimes causal micro – organisms get mixed with drinking water and spread water borne diseases. Cholera, for example is a water borne disease.
  3. Through Sexual Contact: Sexual act between two people can lead to the transfer of diseases such as syphilis, gonorrhoea, AIDS etc.
  4. Through Vectors: Certain diseases spread by animals called vectors. For example, mosquitoes spread malaria.

Question 3.
What precautions can you take in your school to reduce the incidence of infectious diseases?
Answer:
Precautions to reduce incidence of infectious diseases are:

  1. Staying away from the infected person.
  2. Covering mouth or nose while coughing or sneezing to prevent the spread of disease.
  3. Drinking safe water.
  4. Keeping the school environment clean to prevent multiplication vectors.

Question 4.
What is immunisation?
Answer:
Immunisation is defined as protection of the body from communicable diseases by administration of some agent that mimics the pathogen.

Question 5.
What are the immunisation programmes available at the nearest health centre in your locality? Which of these diseases are the major health problems in your area?
Answer:
The immunisation programmes available at the nearest health centre are DPT (Diphtheria, Pertusis, and Tetanus), polio vaccine, hepatitis B, MMR (Measles, Mumps, and Rubella), jaundice, typhoid etc. Of all these diseases, jaundice and typhoid are major health problems.

Why do we Fall Ill NCERT Textbook Exercises

Question 1.
How many times did you fall ill in the last one year? What were the illnesses?

  1. Think of one change you could make in your habits in order to avoid any of/most of the above illnesses.
  2. Think of one change you would wish for in your surroundings in order to avoid any of / most of the above illnesses.

Answer:
The illness was 2 – 3 times common – cold, occurred in a year:

  1. One change I would make in my habits in order to avoid the above illness is that I would take proper diet rich in vitamin C and would avoid too cold food.
  2. The surroundings should be neat and clean.

Question 2.
A doctor / nurse / health – worker is exposed to more sick people than others in the community. Find out how she / he avoids getting sick herself / himself.
Answer:
The following precautions must be taken by a doctor / nurse / health – worker:

  1. Wearing a mask when in contact with a diseased person.
  2. Keeping yourself covered while moving around an infected place.
  3. Drinking safe water.
  4. Eating healthy and nutritious food.
  5. Ensuring proper cleanliness and personal hygiene.

MP Board Solutions

Question 3.
Conduct a survey in your neighbourhood to find out what the three most common diseases are. Suggest three steps that could be taken by your local authorities to bring down the incidence of these diseases.
Answer:
Common diseases are dysentry, malaria, viral fever / jaundice. Preventive Measures:

  1. Cleanliness of surrounding neighbourhood i.e, removal of garbage from the streets / house and storage in a covered place till it is disposed off. Proper cleaning of drains and proper disposal of sewer water.
  2. Removal of breeding places of mosquitoes like ditches with stagnant water.
  3. Ensure supply of safe drinking water.

Or
Periodical programmes to educate people about prevention of disease.

Question 4.
A baby is not able to tell her / his caretakers that she / he is sick. What would help us to find out

  1. that the baby is sick?
  2. what is the sickness?

Answer:

  1. The baby is sick can be determined by his / her behavioural changes such as constant crying of baby, improper intake of food, frequent mood changes etc.
  2. The sickness is determined by symptoms or indications that can be seen in the baby. The symptoms include vomiting, fever, loose motion, paleness in the body etc.

Question 5.
Under which of the following conditions is a person most likely to fall sick?
(a) when she is recovering from malaria.
(b) when she has recovered from malaria and is taking care of someone suffering from chicken – pox.
(c) when she is on a four – day fast after recovering from malaria and is taking care of someone suffering from chicken – pox. Why?
Answer:
(c) A person is more likely to fall sick when she is on a four day fast after recovering from malaria and is taking care of someone who is suffering from chicken pox. This is because she is fasting during recovery and her immune system is so weak that it is not able to protect its own body from any foreign infection. If she is taking care of someone suffering from chicken pox, then she has more chances of getting infected from chicken pox virus and will get sick again with this disease.

MP Board Solutions

Question 6.
Under which of the following conditions are you most likely to fall sick?
(a) when you are taking examinations.
(b) when you have travelled by bus and train for two days.
(c) when your friend is suffering from measles. Why?
Answer:
(c) You are more likely to fall sick when your friend is suffering from measles. This is because measles is highly contagious and can easily spread through respiration i. e., through air. Thus, if your friend is suffering from measles, stay away from him otherwise you might easily get infected with the disease.

Why do we Fall Ill Additional Questions

Why do we Fall Ill Multiple Choice Questions

Question 1.
Community health is related to:
(a) Social health
(b) Physical health
(c) Mental health
(d) All.
Answer:
(d) All.

Question 2.
Every disease have particular:
(a) Body weight
(b) temperature
(c) Sign
(d) Appearance change.
Answer:
(c) Sign

Question 3.
Condition for good community health is by maintaining:
(a) Cleanliness
(b) Pollution less atmosphere
(c) Economic growth
(d) All.
Answer:
(d) All.

MP Board Solutions

Question 4.
Malaria is caused by:
(a) Vibrio cholerae
(b) Plasmodium vivax
(c) Andies
(d) H. pylori.
Answer:
(b) Plasmodium vivax

Question 5.
Vibrio cholerae is a:
(a) Agent
(b) Host
(c) Vector
(d) None.
Answer:
(a) Agent

Question 6.
Which one of the following is water born infectious disease?
(a) Common cold
(b) Peptic ulcers
(c) Cholera
(d) AIDS.
Answer:
(c) Cholera

Question 7.
Which one among the following is a viral disease?
(a) AIDS
(b) Cholera
(c) TB
(d) Typhoid.
Answer:
(a) AIDS

Question 8.
Which one among the following is a chronic disease?
(a) Cold
(b) Malaria
(c) Elephantiasis
(d) None.
Answer:
(c) Elephantiasis

MP Board Solutions

Question 9.
In malaria disease, which one of the following is vector?
(a) Plasmodium vivax
(b) Mosquito
(c) Human
(d) Dog.
Answer:
(b) Mosquito

Question 10.
Which one of the following is mechanical cause of disease?
(a) Injury
(b) Microbes
(c) Heat
(d) All.
Answer:
(a) Injury

Question 11.
HIV – AIDS is transmitted by:
(a) Microbes
(b) Sexual contact
(c) Water
(d) All.
Answer:
(b) Sexual contact

Question 12.
Main factors which can help in public health hygiene:
(a) Availability of safe drinking water.
(b) Availability of clean environment.
(c) Spacious condition for living.
(d) All.
Answer:
(d) All.

Question 13.
Penicillin is a / an:
(a) Antigen
(b) Antibody
(c) Pathogen
(d) Host.
Answer:
(a) Antigen

Why do we Fall Ill Very Short Answer Type Questions

Question 1.
Write symptoms of a disease.
Answer:
Discomfort pain and tiredness is symptoms of a disease.

Question 2.
Is mental discomfort a disease?
Answer:
Yes.

Question 3.
When a part of body is hurt, can it affect all body? Why?
Answer:
Yes, because all body parts are connected internally.

MP Board Solutions

Question 4.
Write name of two diseases caused by virus.
Answer:
AIDS, common cold.

Question 5.
Write name of two diseases caused by worms.
Answer:
Elephantiasis, intestine infection.

Question 6.
Write name of two deficiency diseases.
Answer:
Beri – Beri, Rickets.

Question 7.
What is a vector?
Answer:
Organism which transfer a disease is called a vector.

Question 8.
What is a host?
Answer:
Organism which bear disease and their causative agents is called host.

Question 9.
Name one genetical disorder.
Answer:
Haemophilia.

Question 10.
How malaria and dengue are spread?
Answer:
By species of mosquito.

Question 11.
Name two communicable diseases.
Answer:

  1. AIDS
  2. cold.

MP Board Solutions

Question 12.
What become vector for a communicable disease?
Answer:
Host itself.

Question 13.
What kind of disease is AIDS?
Answer:
AIDS is a fatal viral disease.

Question 14.
Name two air born diseases.
Answer:

  1. Influenza
  2. pneumonia.

Question 15.
Name a disease against which vaccines are available.
Answer:
Typhoid.

Why do we Fall Ill Short Answer Type Questions

Question 1.
Define congenital diseases. Give some examples of such disease.
Answer:
Diseases or abnormalities present since birth are called congenital diseases. It is due to gene mutations (genetic factor) or environmental factors.
Examples:

  • Colour blindness
  • Cleft lip or palate.

Question 2.
Name the agent and vector which cause rabies.
Answer:
The causative agent of rabies is rabies virus (RV). The animals included humans can be infected and all of them can spread the disease.
Causes:

  • Dogs
  • rats
  • cats
  • monkeys
  • squirrels
  • cattle
  • wolves
  • racoons
  • bears etc. can spread this disease.

MP Board Solutions

Question 3.
What are acquired diseases?
Answer:
The diseases which develop after birth are called acquired diseases. It is categorized into

  • Communicable Diseases(Infectious Diseases): malaria, influenza etc. and
  • Non – Communicable Diseases: diabetes, scurvy, high blood pressure.

Question 4.
Write some common signs and symptoms of a disease if a brain is affected.
Answer:
Headache, fits, vomitting, unconsciousness etc.

Question 5.
What are infectious agents?
Answer:
The microorganisms which spread the disease from one person to other are called infectious agents.

Question 6.
Define ‘germ theory of disease’?
Answer:
Louis Pasteur proposed ‘germ theory of disease’ also called pathogenic theory of medicine. He stated that micro – organisms are the causes of many diseases.

MP Board Solutions

Question 7.
What happen when kidneys of a person do not filter urine properly?
Answer:
If the kidneys of a person do not filter urine properly then the toxic substances which disturbs metabolism could be fatal.

Question 8.
Is skin, hairs, saliva form the first line of defence against diseases? If yes, then how?
Answer:
Yes, skin, nose hairs, saliva act as the first line of defence.

  • Skin: It prevents the entry of microbes.
  • Hairs: These prevent the entry of dust particles and germs.
  • Saliva: It washes away bacterial growth from teeth and mouth.

Question 9.
What is immunity?
Answer:
Immunity refers to ability of the body to be resistant towards injury, poison or harmful pathogens. It is part of the defence reaction in the body. There are two types of immunity – natural or innate immunity and acquired or specific immunity.

Question 10.
Why are kids and elderly people more vulnerable to cold / flu?
Answer:
Kids are more vulnerable to cold and flu because their immune systems haven’t fully developed. Elderly people also more prone to catch a cold because of their poor health.

MP Board Solutions

Question 11.
Define antibiotic. Explain how it is able to control bacterial infections but not viral infections.
Answer:
Antibiotics (anti means against and biotic means living) are types of medications which slows and destroy the growth of bacteria. They commonly block biochemical pathways important for bacteria. Many bacteria, for example, make a cell – wall to protect themselves. The antibiotic penicillin blocks the bacterial processes that build the cell wall. Thus, bacteria fail to build their cell – wall, stop multiplying and die out.

Question 12.
Name infectious diseases that are spread through air.
Answer:
Infectious diseases that spread through air are – sneezing, coughing, open pneumonia, tuberculosis, measles, SARS, chicken – pox.

Question 13.
How infectious diseases are spread through water? Give two examples.
Answer:
Open defecation, consuming contaminated water, inadequate hand washing causes infectious diseases through water. Water – borne diseases are cholera, typhoid etc.

Question 14.
Give few examples of direct and indirect contact diseases.
Answer:

  1. Direct Contact Diseases: Examples of diseases spread by direct contact are common cold, tuberculosis, chicken pox, warts etc. Sexual Transmitted Diseases (STD) are Syphilis, AIDS, gonorrhoea.
  2. Indirect Contact Diseases: Examples of diseases spread by indirect contact are Flu, TB, Chickenpox, urinal infections etc.

Why do we Fall Ill Long Answer Type Questions

Question 1.
Becoming exposed to or infected with an infectious microbe does not necessarily mean developing noticeable disease. Explain.
Answer:
Infected with a microbe does not mean developing a disease because an infectious microbe is able to cause a disease only. If the immune system of the person is weak but a person with strong immune system normally fights off microbes. We have cells which are specialised to kill the pathogenic microbes. These cells are active when infecting microbes enter the body and if they are successful in removing the pathogen, we remain disease – free. So, even if we are exposed to infectious microbes, the person will not catch the disease.

MP Board Solutions

Question 2.
Give any four factors necessary for a healthy person.
Answer:
Factors necessary for a healthy person are as follows:

  1. A clean environment with proper public health services.
  2. Personal hygiene prevents infectious diseases.
  3. A proper balanced diet and sufficient nourishment are necessary for good immune system of our body.
  4. Immunisation / vaccination against severe diseases.

Question 3.
Why is AIDS considered to be a ‘Syndrome’ and not a disease?
Answer:
AIDS is considered a syndrome and not a disease because AIDS causing virus – HIV comes into the body via the sexual organs or any other means like blood transfusion and spread to lymph nodes all over the body. The virus damages the immune system of the body and the body can no longer fight off many minor infectious. Instead, every small cold can become pneumonia, or minor get infection can become severe diarrhoea. The effect of disease becomes very severe and complex, at times killing the person suffering from AIDS. Hence, there is no specific disease symptoms for AIDS but it results in a complex disease and symptoms.

Question 4.
(a) The signs and symptoms of a disease depend upon the tissues or organ the microbe targets. Explain giving any two examples.
(b) How does the immune system work against microbes?
(c) Name two diseases against which vaccines are available.
Answer:
(a) Disease – causing microbes enter the body through different means. These disease – causing micro – organisms are tissues specific or we can say that they target a specific organ.  If these microbes enter the body via the nose, the lungs are target and the symptoms are:

  1. cough
  2. breathlessness.

This is seen in the bacteria causing tuberculosis. If brain is targetted by these microbes, the symptoms will be headache, vomitting, fits or unconsciousness. This is seen in the bacteria causing meningitis.

(b) Immunisation is most important and effective way to raise resistance against the disease. Immunity may be two types:

  1. Active immunity
  2. Passive Immunity (artificial).

In active immunity, the body responds against disease – causing microbes and produces antibodies. The antibodies attack organ and kill the disease – causing microbes. In passive immunity, prepared antibodies are used against disease – causing microbes.

(c) We have vaccine against polio and tuberculosis.

Why do we Fall Ill Higher Order Thinking Skills (HOTS)

Question 1.
Why we cannot destroy virus?
Answer:
Virus attacks our body and consume proteins and RNA only. They do not have any metabolic pathway while other pathogens have their metabolic pathways. Our medicines stops the metabolic activity of pathogens and hence they get destroyed, but it is not possible in case of virus.

MP Board Solutions

Question 2.
How vaccine stops disease while it is, itself a low dose of similar causative agent?
Answer:
Our body has a very strong immune system and it develops antigen to subside the effect of any new high quantity antibody entering in the body. Presence of chemical in small harmless quantity initiate development of antigen in body and when actually agent enters in the body, antigen fights easily with it.

Why do we Fall Ill Value Based Questions

Question 1.
Anya got vaccination, she told her friend Sakshi. Sakshi got scared and doubted if it was safe as it contains weakened pathogens which cause diseases. Later, Anya explained her the concept of vaccination and immunity. Answer the following questions:

  1. What did Anya explain Sakshi?
  2. What values did Anya possess?

Answer:

  1. Anya explained that vaccine or weakened pathogen are not harmful to the body. Rather, they boost the person immunity against the same pathogen when it is actually encountered by the body is attacked by it leading to its destruction.
  2. Anya possess the values of helpfulness and intelligence. She is practical.

MP Board Solutions

Question 2.
Akash found in a blood test that his brother was HIV positive. His brother, due to this was expelled from the job. Only after intervention of NGO, he got it back.

  1. Which disease is his brother suffering from?
  2. Write its modes of transmission.
  3. Write your views about the NGO and the organization where his brother worked.

Answer:

  1. AIDS (caused by HIV).
    • Mother to child (during pregnancy).
    • Using infected syringes.
    • Blood transfusion.
    • Sexual contact with infected person.
  2. NGO has taken correct step and has helped Akash in fighting for injustice. While, organisation was wrong in its step as it does not spread by touching or by working with the infected person.

MP Board Class 9th Science Solutions

MP Board Class 9th Science Solutions Chapter 14 Natural Resources

MP Board Class 9th Science Solutions Chapter 14 Natural Resources

Natural Resources Intext Questions

Natural Resources Intext Questions Page No. 193

Question 1.
How is our atmosphere different from the atmospheres on Venus and Mars?
Answer:
Earth’s atmosphere has mixture of nitrogen (79%), oxygen (20%), and a small fraction of carbon dioxide, water vapours and other gases which makes the existence of life possible on Earth while the atmospheres on Venus and Mars mainly has carbon dioxide. Approximately, 95% to 97% is carbon dioxide is present on these planets which do not support existence of life.

MP Board Solutions

Question 2.
How does the atmosphere act as a blanket?
Answer:
Atmosphere is a mixture of various gases along with vapour and submerged particles. It surrounds the earth and separates it from outer space. As a blanket stop interaction between body covered inside and atmosphere outside, in similar way atmosphere stops interaction between earth and space.
The most important isolations done by atmosphere are:

  1. It keeps the average temperature of the Earth fairly constant during day time and even during the course of whole year.
  2. It prevents a sudden increase in the temperature during day time.
  3. It slows down the escape of heat from the surface of the Earth into outer space during night time.

Question 3.
What causes winds?
Answer:
Atmospheric pressure and temperature difference generates wind. As earth surface is not similar everywhere even at some places it is occupied by huge water bodies, lava emitting volcanoes, moist forest etc., a difference in temperature and pressure arises and to maintain equilibrium wave of pressure moves which we feel or notice as wind.

Question 4.
How are clouds formed?
Answer:
During day time, a large amount of water evaporates from various water bodies and of earth surface and through biological activities such as transpiration and respiration and mix up into the air. This causes the air in the atmosphere to heat up and since air is a bad conductor of heat, when this heated air rises, it expands and cools, which results in the condensation and formation of water droplets. The presence of dust and other suspended particles in air also facilitates cloud formation. The gathering of water droplets leads to the formation of clouds.

MP Board Solutions

Question 5.
List any three human activities that you think would lead to air pollution.
Answer:
Three human activities leading to air pollution are:

  1. Smoke from industrial and manufacturing activities etc.
  2. Burning of fossil fuels for household and commercial purpose.
  3. Spreading farming chemicals such as crop dusting, insect / pest killers, fertilizer dust etc.

Natural Resources Intext Questions Page No. 194

Question 1.
Why do organisms need water?
Answer:
Water is the major component of living organism some of the living organism has up to 90% of water of their body weight. Water is a wonderful liquid, it helps in performing most of the functions of our body like digestion, cell sap and oilier content formation, transportation of substance from one place to another inside the body etc.

Question 2.
What is the major source of fresh water in the city’town/ village where you live?
Answer:
The major source of fresh water near me is river.

Question 3.
Do you know of any activity which may be polluting this water source?
Answer:
Dumps from industrial activities, household works for various purpose in the fresh water sources are main activities which causes pollution. Air pollution which generates acid rain and spread submerged dust is also responsible for polluting water resources.

Natural Resources Intext Questions Page No. 196

Question 1.
How is soil formed?
Answer:
The process of soil formation is termed ‘paedogenesis’. Soil is formed mainly by the weathering of rocks through various physical chemical and biological processes with the help of various factors such as the sun, water, wind, and living organisms. It is made up of mineral particles, organic materials, air, water and living organisms. During day time, the rocks are heated up by solar rays. This causes the rocks to expand. During night time, these rocks cool down and contracts. It causes weathering of rock and formation of soil.

  1. Water: It helps in breaking of rocks in two ways:
    • It goes into the cracks and crevices formed in the rocks. When this water freezes, its volume increases. As a result, the size of the cracks also increases. This helps in the weathering of rocks.
    • Water moving at fast speed carries big and small particles of rock downstream. These rocks rub against each other, resulting in breaking down of rocks. These smaller particles are carried away by running water and deposited down its path.
  2. Wind: Strong winds carry away rocks, which causes rubbing of rocks. This results in the breaking down of rocks into smaller and smaller particles.
  3. Living Organism: Some living organisms like lichens help in the formation of soil. Lichens grow on rock surfaces and converts them into powdery form and make soil layer. In the same way, the plants like moss also helps in the making of fine soil particles.

Question 2.
What is soil erosion?
Answer:
The blowing away or washing away of land surface by wind or water is known as soil erosion.

MP Board Solutions

Question 3.
What are the methods of preventing or reducing soil erosion?
Answer:
The methods of preventing or reducing soil erosion are:

  1. Plantation of tress and plants.
  2. Prevention of deforestation.
  3. Prevent excessive grazing.

Natural Resources Intext Questions Page No. 201

Question 1.
What are the different states in which water is found during the water cycle?
Answer:
Water is found in three different states during the water cycle:

  1. Solid (snow, ice).
  2. Liquid water (ground water, river water, etc.)
  3. Gaseous state (water vapours).

Question 2.
Name two biologically important compounds that contain both oxygen and nitrogen.
Answer:
Two biologically important compounds that contain both oxygen and nitrogen are:

  1. Amino acids.
  2. Deoxyribonucleic acid (DNA) and Ribonucleic acid (RNA).

Question 3.
List any three human activities which would lead to an increase in the carbon dioxide content of air.
Answer:
Three Human activities are:

  1. Burning of fuels in various processes like heating, cooking, transportation and industry.
  2. Human induced forest fires.
  3. The process of deforestation includes the cutting down of trees. This decreases the uptake of carbon dioxide for photosynthesis. Eventually, the content of carbon dioxide increases.

Question 4.
What is the greenhouse effect?
Answer:
Some gases like carbon dioxide, methane, nitrous oxide prevent the escape of heat from the Earth’s surface by trapping it. This increases the average temperature of the Earth. This is called the green house effect.

MP Board Solutions

Question 5.
What are the two forms of oxygen found in the atmosphere?
Answer:
The two forms of oxygen found in the atmosphere are:

  1. Diatomic molecular form with chemical formula O2.
  2. Triatomic molecular form with chemical formula O3 known as ozone.

Natural Resources NCERT Textbook Exercise

Question 1.
Why is the atmosphere essential for life?
Answer:
The atmosphere is essential for life because it maintains an appropriate climate for the sustenance of life by carrying out the following activities:

  1. Atmosphere keeps the average temperature of the earth fairly constant during day time.
  2. It prevents a sudden increase in temperature during day time.
  3. It also slows down the escape of heat from the surface of the earth into outer space during night time.

Question 2.
Why is water essential for life?
Answer:
Water is essential for life because of the following reasons:

  1. Most biological reactions occur when substances are dissolved in water. Thus, all cellular processes need water as a medium to take place.
  2. Transportation of biological substances needs water as a medium.

Question 3.
How are living organisms dependent on the soil?
Or
Are organisms that live in water totally independent of soil as a resource?
Answer:
Almost all living organisms are dependent on soil. Some depends directly, while some depends indirectly. Plants need soil for getting support as well as nutrients to prepare their food. On the other hand, organisms depend on plants for food and other substances that are essential for life. Herbivores depend directly upon plants and carnivores depend upon animals, which in turn depend upon plants for food. This makes them depend on soil indirectly.

Organisms that live in water are not totally independent of soil as a resource. These organisms depend on aquatic plants for food and other substances. These aquatic plants in turn require minerals for their sustenance. These minerals are carried to water bodies from soil by rivers, rain water etc. Without the supply of minerals from the soil to the water bodies, it is impossible to imagine aquatic life.

MP Board Solutions

Question 4.
You have seen weather reports on television and in newspapers. How do you think we are able to predict the weather?
Answer:
The meteorological department of the government collects data on the elements of weather such as maximum and minimum temperatures, maximum and minimum humidity, rainfall, wind speed etc. They are able to study these elements using various instruments. The maximum and minimum temperature of a day is measured by a thermometer known as the maximum – minimum thermometer. Rain fall is measured by an instrument known as the rain gauge. Wind speed is measured by anemometers. There are various instruments used to measure humidity.

Question 5.
We know that many human activities lead to increasing levels of pollution of the air, water-bodies and soil. Do you think that isolating these activities to specific and limited areas would help in reducing pollution?
Answer:
Yes. Isolating human activities to specific areas would help in reducing levels of pollution. For example, setting up of industries in isolated regions will control pollution to some extent. The pollution caused by these industries will not contaminate water resources, agriculture land, fertile land, etc.

Question 6.
Write a note on how forests influence the quality of our air, soil and water resources.
Answer:
Forests influence the quality of our air, soil, and water resources in various ways. Some of them are:

  1. Forests balance the percentages of carbon dioxide and oxygen in the atmosphere. The increasing amount of carbon dioxide caused by human activities is balanced by a larger intake of carbon dioxide by plants during
    the process of photosynthesis. Simultaneously, a large amount of oxygen is released.
  2. Forests prevent soil erosion. Roots of plants bind the soil tightly in a way that the surface of the soil cannot be eroded away by wind, water etc.
  3. Forests help in the replenishment of water resources. During the process of transpiration, a huge amount of water vapour goes into the air and condenses to form clouds. These clouds cause rainfall that recharge water bodies.

Natural Resources Additional Questions

Natural Resources Multiple Choice Questions

Question 1.
The atmosphere of the earth is heated by radiations which are mainly ___________ .
(a) radiated by the sun
(b) re – radiated by land
(c) re – radiated by water
(d) re – radiated by land and water.
Answer:
(d) re – radiated by land and water.

Question 2.
If there were no atmosphere around the earth, the temperature of the earth will ___________ .
(a) increase.
(b) go on decreasing.
(c) increase during day and decrease during night.
(d) be unaffected.
Answer:
(c) increase during day and decrease during night.

Question 3.
What would happen, if all the oxygen present in the environment is converted to ozone?
(a) We will be protected more.
(b) It will become poisonous and kill living forms.
(c) Ozone is not stable, hence it will be toxic.
(d) It will help harmful sun radiations to reach earth and damage many life forms.
Answer:
(b) It will become poisonous and kill living forms.

MP Board Solutions

Question 4.
One of the following factors does not lead to soil formation in nature ___________ .
(a) the sun
(b) water
(c) wind
(d) polythene bags.
Answer:
(d) polythene bags.

Question 5.
The two forms of oxygen found in the atmosphere are ___________ .
(a) water and ozone
(b) water and oxygen
(c) ozone and oxygen
(d) water and carbon – dioxide.
Answer:
(c) ozone and oxygen

Question 6.
The process of nitrogen – fixation by bacteria does not take place in the presence of ___________ .
(a) molecular form of hydrogen
(b) elemental form of oxygen
(c) water
(d) elemental form of nitrogen.
Answer:
(b) elemental form of oxygen

Question 7.
Rainfall patterns depend on ___________ .
(a) the underground water table.
(b) the number of water bodies in an area.
(c) the density pattern of human population in an area.
(d) the prevailing season in an area.
Answer:
(b) the number of water bodies in an area.

Question 8.
Among the given options, which one is not correct for the use of large amount of fertilisers and pesticides?
(a) They are eco – friendly.
(,b) They turn the fields barren after sometime.
(c) They adversely affect the useful component from the soil.
(d) They destroy the soil fertility.
Answer:
(a) They are eco – friendly.

Question 9.
The nitrogen molecules present in air can be converted into nitrates and nitrites by ___________ .
(a) a biological process of nitrogen fixing bacteria present in soil.
(b) a biological process of carbon fixing factor present in soil.
(c) any of the industries manufacturing nitrogenous compounds.
(d) the plants used as cereal crops in field.
Answer:
(a) a biological process of nitrogen fixing bacteria present in soil.

Question 10.
One of the following processes is not a step involved in the water – cycle operating in nature ___________ .
(a) evaporation
(b) transpiration
(c) precipitation
(d) photosynthesis.
Answer:
(d) photosynthesis.

Question 11.
The term “water – pollution” can be defined in several ways. Which of the following statements does not give the correct definition?
(a) The addition of undesirable substances to water – bodies.
(b) The removal of desirable substances from water – bodies.
(c) A change in pressure of the water bodies.
(d) A change in temperature of the water bodies.
Answer:
(c) A change in pressure of the water bodies.

Question 12.
Which of the following is not a green house gas?
(a) Methane
(b) Carbon dioxide
(c) Carbon monoxide
(d) Ammonia.
Answer:
(d) Ammonia.

MP Board Solutions

Question 13.
Which step is not involved in the carbon – cycle?
(a) Photosynthesis
(b) Transpiration
(c) Respiration
(d) Burning of fossil fuels.
Answer:
(b) Transpiration

Question 14.
‘Ozone – hole’ means
(a) a large sized hole in the ozone layer.
(b) thinning of the ozone layer.
(c) small holes scattered in the ozone layer.
(d) thickening of ozone in the ozone layer.
Answer:
(b) thinning of the ozone layer.

Question 15.
Ozone – layer is getting depleted because of ___________ .
(a) excessive use of automobiles.
(b) excessive formation of industrial units.
(c) excessive use of man – made compounds containing both fluorine and chlorine.
(d) excessive deforestation.
Answer:
(c) excessive use of man – made compounds containing both fluorine and chlorine.

MP Board Solutions

Question 16.
Which of the following is a recently originated problem of environment?
(a) Ozone layer depletion.
(b) Green house effect.
(c) Global warming.
(d) All of the above.
Answer:
(d) All of the above.

Question 17.
When we breathe in air, nitrogen also goes inside along with oxygen. What is the fete of this nitrogen?
(a) It moves along with oxygen into the cells.
(b) It comes out with the CO2 during exhalation.
(c) It is absorbed only by the nasal cells.
(d) Nitrogen concentration is already more in the cells so it is not at all absorbed.
Answer:
(b) It comes out with the CO2 during exhalation.

Question 18.
Top – soil contains the following ___________ .
(a) Humus and living organisms only.
(b) Humus and soil particles only.
(c) Humus, living organisms and plants.
(d) Humus, living organisms and soil particles.
Answer:
(d) Humus, living organisms and soil particles.

Question 19.
Choose the correct sequences ___________ .
(a) CO2 in atmosphere → decomposers → organic carbon in animals → organic carbon in plants.
(b) CO2  in atmosphere → organic carbon in plants → organic carbon in animals → inorganic carbon in soil.
(c) Inorganic carbonates in water → organic carbon in plants → organic carbon in animals → scavengers.
(d) Organic carbon in animals → decomposers → CO2 in atmosphere → organic carbon in plants.
Answer:
(b) CO2  in atmosphere → organic carbon in plants → organic carbon in animals → inorganic carbon in soil.

MP Board Solutions

Question 20.
Major source of mineral in soil is the ___________ .
(a) parent rock from which soil is formed.
(b) plants.
(c) animals
(d) bacteria.
Answer:
(a) parent rock from which soil is formed.

Natural Resources Very Short Answer Type Questions

Question 1.
Name the factor responsible for rainfall patterns in India.
Answer:
North – East or South – West Monsoons.

Question 2.
Name any two organisms. Which play important role in nitrogen – fixation.
Answer:
Rhizobium and Nitrosomonas.

Question 3.
State the process and the form by which carbon enters in the living system.
Answer:
Respiration.

Question 4.
Write any one difference between oxygen and ozone.
Answer:
Oxygen is diatomic (O2) whereas ozone is triatomic (O3).

MP Board Solutions

Question 5.
What is the temperature range on the surface of moon?
Answer:
-190°C to 110°C.

Natural Resources Short Answer Type Questions

Question 1.
Rivers from land, add minerals to sea water. Discuss, how?
Answer:
Water is wonderful solvent. As water flows over the rocks which containing soluble minerals and these mineral get dissolved in the water. Thus, Rivers from land, add minerals to sea water.

Question 2.
How can we prevent the loss of top soil?
Answer:
Loss of top soil can be prevented by stopping the falling of trees and excessive grazing by animals, growing more the vegetation cover.

MP Board Solutions

Question 3.
How is the life of organisms living in water affected when water gets polluted?
Answer:
When water gets polluted, oxygen does not dissolves in water properly, which effects the aquatic organisms adversely. Also, due to undesirable chemicals and waste discharge from factories and households cause diseases to the aquatic organisms.

Question 4.
During summer, if you go near the lake, you feel relief from the heat, why?
Answer:
Due to evaporation of water, air nearby water bodies become cooler.

Question 5.
In coastal area, wind current moves from the sea towards the land during day; but during night it moves from land to the sea. Discuss the reason.
Answer:
Air above the land gets heated quickly during day and starts rising. This creates a region of low pressure as a result air over sea rushes into this area of low pressure. This movement of air from one region to the other creates winds. During night, as water cools down slowly, the air above water is warmer than the air on land. So, air moves from land to sea creating winds.

Question 6.
Following are a few organisms: (a) lichen (b) mosses (c) mango tree (d) cactus.
Which among the above can grow on stones; and also help in formation of soil? Write the mode of their action for making soil.
Answer:
Lichens and Mosses: (a) and (b).
Lichens and mosses release materials which break down the stones causes formation of soil.

Question 7.
Soil formation is done by both abiotic and biotic factors. List the names of these factors by classifying them as abiotic and biotic?
Answer:

  1. Sun, water and wind are abiotic factors that forms soil.
  2. Lichens, mosses and trees are biotic factors which form soil.

Question 8.
All the living organisms are basically made up of C, N, S, P, H and O. How do they enter the living forms? Discuss.
Answer:
In 1952, Stanley Miller along with Harold C. Urey designed an experiment to see how complex organic molecules might have formed under the conditions of early Earth. From long experimental method he developed organic matter from non living things. And, concluded that on specific environmental conditions non living things grow up to living form.

MP Board Solutions

Question 9.
Why does the percentage of gases like oxygen, nitrogen and carbon dioxide remain almost the same in the atmosphere?
Answer:
The percentage of gases like oxygen, nitrogen and carbon dioxide remain almost the same in the atmosphere because cycling of these gases maintains consistency.

Question 10.
Why does moon have very cold and very hot temperature variations e.g., from -190°C to 110°C even though it is at the same distance from the sun as the earth is?
Answer:
No atmosphere exists on the moon thus, moon have very cold and very hot temperature variations e.g., from -190°C to 110°C even though it is at the same distance from the sun as the earth.

Question 11.
Why do people love to fly kites near the seashore?
Answer:
People love to fly kites near the seashore because air gets heated quickly during day and creates wind, which helps them to fly kites easily.

Question 12.
Why does Mathura refinery pose problems to the Taj Mahal?
Answer:
Polluted environment of Mathura due to refinery and other infrastructural facilities, industries etc. release toxic gases (like oxides of sulphur) which causes acid rain and corrode the marbles of Taj Mahal.

Question 13.
Why does water need conservation even though large oceans surround the land masses?
Answer:
Marine water is not useful for human and plant life directly. Hence fresh water need conservation. Uneven distribution of limited fresh water resources need conservation to ft ever rising demands.

Question 14.
There is mass mortality of fishes in a pond. What ma) the reasons?
Answer:

  1. Thermal pollution
  2. Addition of poisonous (mercury) compounds in water
  3. Due to blockage of gills with any pollutant.

Natural Resources Long Answer Type Questions

Question 1.
How do fossil fuels cause air pollution?
Answer:
Most of air pollution of our environment is caused by the burning of fossil fuels, such as coal, oil natural gas and gasoline to produce electricity and power out vehicles. Carbon dioxide (CO2) is a good indicator of how much fossil fuel is burnt and how much of other pollutants are emitted as a result. When fossil fuels are burnt, they release primarily nitrogen oxides into the atmosphere, which leads to the formation of smog and simultaneously acid rain.

The most common nitrogen – related compounds emitted into the air by human activities are collectively referred to as nitrogen oxides. Ammonia is also a harmful nitrogen compound emitted to the air, agricultural activities also contribute in air pollution but fossil fuels are most common reason for its increase day by day.

MP Board Solutions

Question 2.
What are the causes of water pollution? Discuss how you can contribute in reducing water pollution.
Answer:
Domestic and industrial waste dump to water – bodies are main reason of water pollution. Industries produce huge amount of waste which contains toxic chemicals and pollutants which can cause air pollution and damage us and our environment. They contain pollutants such as lead, mercury, sulphur, asbestos, nitrates and many harmful chemicals.

Prevention of water pollution:
Stop dumping waste in water – bodies is the only way to get clear water resources. Do not throw chemicals, oils, paints and medicines down the sink drain or the toilet. If you use chemicals and pesticides for your gardens and farms, be mindful not to overuse pesticides and fertilizers. This will reduce run offs of the chemical into nearby water sources.

Natural Resources Higher Order Thinking Skills (HOTS)

Question 1.
If decomposers are removed completely from the Earth, what will be the result? Give reasons.
Answer:
Decomposers are the organisms that feed on dead and decaying matter present on the Earth. These organisms decompose the dead plants and animals returning the complex nutrients present in them in available form to the nature.

Question 2.
Why is nitrogen – fixing bacteria found only in the roots of leguminous plants?
Answer:
The roots of leguminous plants contains root nodules. These nodules provide shelter to nitrogen fixing bacteria like Rhizobium.

Natural Resources Value Based Questions

Question 1.
Manisha lived near industrial area in Delhi. During winters . she saw that the smoke has reduced the visibility in the area. Manisha requested the industries to fit in chimney the precipitators that would not release smoke particulates in air.

  1. What is smog?
  2. Name two disease caused due to air pollution.
  3. What values are displayed by Manisha?

Answer:

  1. When smoke is added to fog, smog is formed.
  2. Air – pollution causes respiratory problem and allergies.
  3. Manisha showed the value of self-awareness, and responsible behaviour.

Question 2.
Radha saw a child sleeping in a car parked with closed doors and glass rolled up in the open area on a sunny day near the market. She immediately raised an alarm and with the help of police, she got the window glass rolled down.

  1. Why was it not safe to keep the doors with window glass rolled Up for a child inside the car?
  2. Name two gases that can lead to above effect.
  3. What values are exhibited by Radha?

Answer:

  1. It was not safe for the child in the car with locked doors and window rolled up, the sunlight would result in the green house effect in the car. This would increase the temperature in the car and also result in the increase in CO2 level which would lead to suffocation.
  2. Carbon dioxide gas and methane gas can lead to green house effect.
  3. Radha displayed the value of aware citizen and responsible behaviour.

MP Board Class 9th Science Solutions

MP Board Class 9th Science Solutions Chapter 15 Improvement in Food Resources

MP Board Class 9th Science Solutions Chapter 15 Improvement in Food Resources

Improvement in Food Resources Intext Questions

Improvement in Food Resources Intext Questions Page No. 204

Question 1.
What do we get from cereals, pulses, fruits and vegetables?
Answer:
We get carbohydrates from cereals and proteins from pulses. Fruits and vegetables give us lots of vitamins and minerals.

Improvement in Food Resources Intext Questions Page No. 205

Question 1.
How do biotic and abiotic factors affect crop production?
Answer:
Biotic factors like pests, insects etc. reduce the crop production. Pests harm crops by feeding over them. Weeds also reduce crop productivity by competing with the main crop for nutrients and light. Abiotic factors like wind, rain, temperature etc. impact the overall crop production. For example, droughts and floods almost completely destroy the whole crop of a particular area.

MP Board Solutions

Question 2.
What are the desirable agronomic characteristics for crop improvements?
Answer:
The desirable agronomic characteristics for crop improvements are:

  1. Tallness and profuse branching in any fodder crop.
  2. Dwarf characteristics in cereals.

Improvement in Food Resources Intext Questions Page No. 206

Question 1.
What are macro – nutrients and why are they called macro – nutrients?
Answer:
Macro – nutrients are those nutrients which are required in large quantities for growth and development of plants. Since they are required in large quantities, they are known as macro – nutrients. The six macro – nutrients required by plants are nitrogen, phosphorus, potassium, calcium, magnesium and sulphur.

Question 2.
How do plants get nutrients?
Answer:
Plants consume nutrients from air, water and soil. Soil is one of the important sources of nutrients. Plants get thirteen nutrients from soil. The remaining three nutrients (carbon, oxygen, and hydrogen) are obtained from air and water.

Improvement in Food Resources Intext Questions Page No. 207

Question 1.
Compare the use of manure and fertilizers in maintaining soil fertility.
Answer:
Manures are biodegradable substances which increase soil fertility by enriching the soil with organic matter and nutrients as it is prepared by the decomposition of animal excreta and plant wastes.

On the other hand, fertilizers are mostly artificially developed inorganic compounds whose excessive use is harmful to ecosystems components and soil fertility. Hence, fertilizers are considered good only for short term use.

Improvement in Food Resources Intext Questions Page No. 208

Question 1.
Which of the following conditions will give the most benefits? Why?
(а) Farmers use high – quality seeds, do not adopt irrigation or use fertilizers.
(b) Farmers use ordinary seeds, adopt irrigation and use fertilizer.
(c) Farmers use quality seeds, adopt irrigation, use fertilizer and use crop protection measures.
Answer:
(c) Farmers using good quality seeds, adopting irrigation, using fertilizers and using crop protection measures will get most benefits.
Reasons are as follows:

  1. Increases the total crop production as good quality seeds, then a majority of the seeds will germinate properly, and will grow into a healthy plants.
  2. Proper irrigation will improve the water availability to crops.
  3. Fertilizers promote high growth and development in plants by providing the essential nutrients such as nitrogen, phosphorus, potassium etc.
  4. Crop protection measures include various methods to control weeds, pests and infectious agents.

Improvement in Food Resources Intext Questions Page No. 209

Question 1.
Why should preventive measures and biological control methods be preferred for protecting crops?
Answer:
Preventive measures and biological control methods should be preferred for protecting crops because excessive use of chemicals leads to environmental problems. Biological methods harm neither crops nor environment.

MP Board Solutions

Question 2.
What factors may be responsible for losses of grains during storage?
Answer:
Factors causing loss of grains during storage:

  1. Biotic Factors: Insects, rodents, fungi and bacteria etc.
  2. Abiotic Factors: moisture content and temperature etc.

Improvement in Food Resources Intext Questions Page No. 210

Question 1.
Which method is commonly used for improving cattle breeds and why?
Answer:
Cross breeding is commonly used for improving cattle breeds. Cross breeding between two good varieties of cattle will produce a new improved variety. For example, the cross between foreign breeds such as Jersey Brown, Swiss and Indian breeds such as Red Sindhi, Sahiwal produces a new variety having qualities of both breeds.

Improvement in Food Resources Intext Questions Page No. 211

Question 1.
Discuss the implications of the following statement: “It is interesting to note that poultry is India’s most efficient converter of low fibre food stuff (which is unfit for human consumption) into highly nutritious animal protein food.”
Answer:
Poultry in India is the most efficient converter of low fibre food stuff in nutritious animal protein food. In poultry farming, domestic fowls are raised to produce eggs and chicken. For this, the fowls are given animal feeds in the form of roughage, which mainly consists of fibres. Thus, by feeding animals a fibre rich diet, the poultry gives highly nutritious food in the form of eggs and chicken.

Question 2.
What management practices are common in dairy and poultry farming?
Answer:
Common management practices in dairy and poultry farming are:

  1. Proper shelter facilities and their regular cleaning.
  2. Some basic hygienic conditions such as clean water, nutritious food etc.
  3. Animals are kept in spacious, airy and ventilated place.
  4. Prevention and cure of diseases at the right time is ensured.

MP Board Solutions

Question 3.
What are the differences between broilers and layers and in their management?
Answer:
Layers are meant for egg production, whereas broilers are meant for poultry meat. Nutritional, environmental and housing conditions required by broilers are different from those required by egg layers. A broiler chicken, for their proper growth, requires vitamin rich supplements especially vitamin A and K. Also, their diet includes protein rich food and enough fat. They also require extra care and maintenance to increase their survival rate in comparison to egg layers.

Improvement in Food Resources Intext Questions Page No. 213

Question 1.
How are fish obtained?
Answer:
Fish can be obtained by two ways:

  1. Capture fishing: It is the process of obtaining fish from natural resources.
  2. Culture fishery: It is the practice of farming fishes. Farming can be done in both freshwater ecosystem (which includes river water, pond water) and marine ecosystem.

Question 2.
What are the advantages of composite fish culture?
Answer:
The advantages of composite fish culture are:

  1. Fish can be grown in crop fields especially paddy.
  2. Intensive fish farming is possible because plenty of water is available during crop seasons.
  3. In this system, both local and imported fish species can be cultivated.

Question 3.
What are the desirable characters of bee varieties suitable for honey production?
Answer:
Bee varieties having the following desirable characters are suitable for honey production:

  1. They should yield high quantity of honey.
  2. They should not sting much.
  3. They should stay in the beehive for long durations.
  4. They should breed very well.

MP Board Solutions

Question 4.
What is pasturage and how is it related to honey production?
Answer:
Pasturage is the availability of flowers from which bees collect nectar and pollen. It is related to the production of honey as it determines the taste and quantity of honey.

Improvement in Food Resources NCERT Textbook Exercises

Question 1.
Explain any one method of crop production which ensures high yield.
Answer:
Inter – cropping method ensures high yield of crop production. It is a practice of growing two or more crops simultaneously in the same field in rows. In inter – cropping, definite row patterns are followed such as one row of main crop is followed by two rows of inter – crop. In inter – cropping, there is a greater utilisation of the inter – spaced area, light, nutrients, water and air. As a result, productivity per unit area is increased.

Question 2.
Why are manures and fertilizers used in fields?
Answer:
Manures and fertilizers are used in fields to enrich the soil with the required nutrients. Manure helps in enriching the soil with organic matter and nutrients. This improves the fertility and structure of the soil. On the other hand, fertilizers ensure a healthy growth and development in plants. They are a good source of nitrogen, phosphorus and potassium. To get an optimum yield, it is instructed to use a balanced . combination of manures and fertilizers in the soil.

Question 3.
What are the advantages of inter-cropping and crop rotation?
Answer:
Inter – cropping and crop rotation, both are used to get maximum benefit on limited land. Inter – cropping helps in preventing pests and diseases to spread throughout the field. It also increases soil fertility, whereas crop rotation prevents soil depletion, increases soil fertility and reduces soil erosion. Both of these methods reduce the need for fertilizers. They also helps in controlling weeds and the growth of pathogens and pests in crops.

MP Board Solutions

Question 4.
What is genetic manipulation? How is it useful in agricultural practices?
Answer:
Genetic manipulation is a process where the gene for a particular character is introduced inside the chromosome of a cell. When the gene for a particular character is introduced in a plant cell, a transgenic plant is produced. These transgenic plants exhibit characters governed by the newly introduced gene.

Genetic manipulation is useful in developing varieties with higher yield, good quality, biotic and abiotic resistance, short maturity period, wider adaptability and desirable agronomic characteristics.

Question 5.
How do storage grain losses occur?
Answer:
There are many biotic and abiotic factors that harm stored grains and result in degradation, poor germinability, discolouration etc. which leads to storage grain losses. Biotic factors like insects or pests cause direct damage by feeding on seeds.

They also deteriorate and contaminate the grain, making it unfit for further consumption.  Abiotic factors such as temperature, light, moisture etc., also affect storage food. They decrease the germinating ability of the seeds and make them unfit for future use by farmers. Unpredictable occurrence of droughts and floods also causes destruction of crops.

Question 6.
How do good animal husbandry practices benefit farmers?
Answer:
Cattle farming is one of the methods of animal husbandry that is most beneficial for farmers. Better breeds of draught animals can be produced. Such draught animals are engaged in agricultural fields for labour such as carting, irrigation, tilling, etc.

Question 7.
What are the benefits of cattle farming?
Answer:
Benefits of cattle farming:

  1. Good quality and quantity of dairy products can be produced.
  2. Draught labour animals can be raised for agricultural work.
  3. New breed of animals that are resistant to diseases can be raised by crossing two breeds with the desired traits.

Question 8.
For increasing production, what is common in poultry, fisheries and bee – keeping?
Answer:
Proper management techniques are the common factors for increasing production in poultry, fisheries and bee keeping. Regular cleaning of farms is of importance. Also, maintenance of temperature and prevention and cure of diseases in farming is also required to increase the growth of animals.

MP Board Solutions

Question 9.
How do you differentiate between capture fishing, mariculture and aquaculture?
Answer:

  1. Capture fishing is the method to obtain fishes from natural resources like rivers, ponds, waterfalls etc.
  2. Mariculture is the culture of marine fishes for commercial use.
  3. Aquaculture involves the production of aquatic animals that are of high economic value such as prawns, lobsters, fishes, crabs etc.

Improvement in Food Resources Additional Questions

Improvement in Food Resources Multiple Choice Questions

Question 1.
Which one is an oil yielding plant among the following?
(a) Lentil
(b) Sunflower
(c) Cauliflower
(d) Hibiscus.
Answer:
(b) Sunflower

Question 2.
Which one is not a source of carbohydrate?
(a) Rice
(b) Millets
(c) Sorghum
(d) Gram.
Answer:
(d) Gram.

Question 3.
Find out the wrong statement from the following:
(a) White revolution is meant for increase in milk production.
(b) Blue revolution is meant for increase in fish production.
(c) Increasing food production without compromising with environmental quality is called as sustainable agriculture.
(d) None of the above.
Answer:
(d) None of the above.

MP Board Solutions

Question 4.
To solve the food problem of the country, which among the following is necessary?
(a) Increased production and storage of food grains.
(b) Easy access of people to the food grain.
(c) People should have money to purchase the grains.
(d) All of the above.
Answer:
(d) All of the above.

Question 5.
Find out the correct sentence.
(i) Hybridisation means crossing between genetically dissimilar plants.
(ii) Cross between two varieties is called as inter specific hybridisation.
(iii) Introducing genes of desired character into a plant gives genetically modified crop.
(iv) Cross between plants of two species is called as inter varietal hybridisation.
(a) (i) and (ii)
(b) (ii) and (iv)
(c) (ii) and (iii)
(d) (iii) and (iv).
Answer:
(a) (i) and (ii)

Question 6.
Weeds affect the crop plants by
(a) killing of plants in field before they grow.
(b) dominating the plants to grow.
(c) competing for various resources of crops (plants) causing low availability of nutrients.
(d) all of the above.
Answer:
(c) competing for various resources of crops (plants) causing low availability of nutrients.

Question 7.
Which one of the following species of honey bee is an Italian species?
(a) Apis dorsata
(b) Apis florae
(c) Apis cerana indica
(d) Apis mellifera.
Answer:
(d) Apis mellifera.

Question 8.
Find out the correct sentence about manure
(ii) Manure contains large quantities of organic matter and small quantities of nutrients.
(ii) It increases the water holding capacity of sandy soil.
(iii) It helps in draining out of excess of water from clayey soil.
(iv) Its excessive use pollutes environment because it is made of animal excretory waste.
(a) (i) and (iii)
(b) (i) and (ii)
(c) (ii) and (iii)
(d) (iii) and (iv).
Answer:
(b) (i) and (ii)

Question 9.
Cattle husbandry is done for the following purposes:
(i) Milk production
(ii) Agricultural work
(iii) Meat production
(iv) Egg production.
(a) (i), (ii) and (iii)
(b) (ii), (iii) and (iv)
(c) (iii) and (iv)
(d) (i) and (iv).
Answer:
(a) (i), (ii) and (iii)

MP Board Solutions

Question 10.
Which of the following are Indian cattle?
(i) Bos indicus
(ii) Bos domestica
(iii) Bos bubalis
(iv) Bos vulgaris.
(a) (i) and (iii)
(b) (i) and (ii)
(c) (ii) and (iii)
(d) (iii) and (iv).
Answer:
(a) (i) and (iii)

Question 11.
Which of the following are exotic breeds?
(i) Brawn
(ii) Jersey
(iii) Brown Swiss
(iv) Jersey Swiss.
(a) (i) and (iii)
(b) (ii) and (iii)
(c) (i) and (iv)
(d) (ii) and (iv).
Answer:
(b) (ii) and (iii)

Question 12.
Poultry farming is undertaken to raise the following:
(a) Egg production
(b) Feather production
(c) Chicken meat
(d) Milk production.
Answer:
(a) Egg production

Question 13.
Poultry fowl are susceptible to the following pathogens:
(a) Viruses
(b) Bacteria
(c) Fungi
(d) All of the above.
Answer:
(d) All of the above.

Question 14.
Which one of the following fishes is a surface feeder?
(a) Rohus
(b) Mrigals
(c) Common carps
(d) Catlas.
Answer:
(d) Catlas.

Question 15.
Animal husbandry is the scientific management of ___________ .
(i) animal breeding
(ii) culture of animals
(iii) animal livestock
(iv) rearing of animals
(a) (i), (ii) and (iii)
(b) (ii), (iii) and (iv)
(c) (i), (ii) and (iv)
(d) (i), (iii) and (iv).
Answer:
(d) (i), (iii) and (iv).

Improvement in Food Resources Very Short Answer Type Questions

Question 1.
Match the column A with the column B
MP Board Class 9th Science Solutions Chapter 15 Improvement in Food Resources 1
Answer:
(a) (ii)
(b) (iii)
(c) (i)
(d) (iv).

Question 2.
Fill in the blanks.

  1. Pigeon pea is a good source of ___________ .
  2. Berseem is an important ___________ crop.
  3. The crops which are grown in rainy season are called ___________ crops.
  4. ___________ are rich in vitamins.
  5. ___________ crop grows in winter season.

Answer:

  1. protein
  2. fodder
  3. Kharif
  4. vegetables
  5. Rabi.

Question 3.
State any one importance of photoperiod in agriculture.
Answer:
Photoperiod is important for growth of plants and flowering.

MP Board Solutions

Question 4.
What are desirable traits for fodder crop?
Answer:

  1. Profused branching.
  2. Tall Plants.

Question 5.
White revolution in India has made us self – sufficient in a product. Name it.
Answer:
Milk.

Improvement in Food Resources Short Answer Type Questions

Question 1.
What is a GM crop? Name any one such crop which is grown in India.
Answer:
Crop developed artificially with the help of modern biotechnology to obtain the desired character is called as genetically modified(GM) crop. But, cotton and egg plant are examples of GM crops which are resistant to many harming biological factors.

Question 2.
List out some useful traits in improved crop.
Answer:
Useful traits in improved crops are as follows:

  1. better yield.
  2. improved quality.
  3. resistance to biotic and abiotic factors.
  4. better adaptability.
  5. better economically.

Question 3.
Why is organic matter important for crop production?
Answer:
Organic matter is important for crops because a fertile and healthy soil is the basis for healthy plant’s growth and soil organic matter works as a foundation for healthy and productive soils.
It helps soil by:

  1. improving soil structure.
  2. increasing water holding capacity of soil.
  3. drainage and in avoiding water logging.
  4. giving shelter to number of animals which also improve soil’s nutrients value.

Question 4.
Why is excessive use of fertilizers detrimental for environment?
Answer:
Excessive use of fertilizers is harmful because it is artificial in origin and accumulate in biological cycle and disturb its balance which causes environmental pollution as their residual and unused amounts will become pollutants for air, water and soil.

Question 5.
Give one word for the following:

  1. Farming without the use of chemicals as fertilizers, herbicides and pesticides is known as ___________ .
  2. Growing of wheat and groundnut on the same field is called as ___________ .
  3. Planting soyabean and maize in alternate rows in the same field is called as ___________ .
  4. Growing different crops on a piece of land in preplanned succession is known as ___________ .
  5. Xanthium and Parthenium are commonly known as ___________ .
  6. Causal organism of any disease is called as

Answer:

  1. organic farming
  2. mixed farming
  3. inter – cropping
  4. crop rotation
  5. weeds
  6. pathogens

Question 6.
Match the following A and B:

(A)(B)
(a) Cattle used for tilling and carting(i) Milk producing female
(b) Indian breed of chicken(ii) Broiler
(c) Sahiwal, Red Sindhi(iii) Draught animals
(d) Milch(iv) Local breed of cattle
(e) Chicken better fed for obtaining(v) Aseel

Answer:
(a) (iii)
(b) (v)
(c) (iv)
(d) (i)
(e) (ii).

Question 7.
Define the term hybridization and photoperiod.
Answer:

  1. Hybridization: Hybridization is the process in which two genetically different individuals are crossed to result generally into an individual with a desired trait.
  2. Photoperiod: Photoperiod in plants is defined as the developmental responses towards the comparative lengths of light and dark periods in its region.

Question 8.
Fill in the blanks:

  1. Photoperiod affects the ___________ .
  2. Kharif crops are cultivated from ___________ to ___________ .
  3. Rabi crops are cultivated from ___________ to ___________ .
  4. Paddy, maize, green gram and black gram are ___________ crops.
  5. Wheat, gram, pea, mustard are ___________ crops.

Answer:

  1. flowering
  2. June to October
  3. November to March,
  4. Kharif
  5. Rabi

Question 9.
Cultivation practices and crop yield are related to environmental condition. Yes/No? Give reasons.
Answer:
Environmental conditions are the components which influence plant growth and genetic factors. Environmental factors include everything in our surrounding i.e. air, water, temperature, atmospheric pressure, surrounding gases etc. When we cultivate any plant or consider crop growth, we check all the above environmental factors before sowing. Hence yes, cultivation practices and crop yield are related to environmental condition.

MP Board Solutions

Question 10.
Fill in the blanks:

  1. A total of ___________ nutrients are essential to plants.
  2. ___________ and ___________ are supplied by air to plants.
  3. ___________ is supplied by water to plants.
  4. Soil supplies ___________ nutrients to plants.
  5. nutrients are required in large quantity and called as ___________ .
  6. nutrients are needed in small quantity for plants and are called ___________ .

Answer:

  1. sixteen
  2. Oxygen and carbon
  3. Hydrogen
  4. thirteen
  5. Six, macro – nutrients
  6. Seven, micronutrients

Improvement in Food Resources Long Answer Type Questions

Question 1.
Define:

  1. Vermicompost
  2. Green manure
  3. Bio fertilizer.

Answer:

  1. Vermicompost: Vermicomposting is the process in which worms and micro – organisms are used to turn organic waste into a black, earthy – smelling, nutrient – rich humus.
  2. Green manure: When crop or plant that is grown and then intentionally plowed under to improve the underlying soil, it is called green manure.
  3. Bio fertilizer: Fertilizer created from biological components as small plants.

Question 2.
Discuss various methods for weed control.
Answer:
Unwanted plants which grow along with crops are called weeds. They compete with the crop plants for light, water, space and minerals, and harm their growth and yield. Some of them produce poisonous substances which can harm the growth of the crop or poison the produce.

Removing weeds from a field is called weeding. It can be done Manually or by using an implement like a trowel, hoe or rake. A third way of getting rid of weeds is by spraying chemicals called weedicides. These chemicals destroy the weeds but not the crop plants.

Improvement in Food Resources Higher Order Thinking Skills (HOTS)

Question 1.
Why should our food contain cereals, pulses, fruits and vegetables?
Answer:

  1. Cereals provide carbohydrates for energy requirements.
  2. Pulses give proteins.
  3. Fruits and vegetables provide various vitamins and minerals.

MP Board Solutions

Question 2.
Why moisture level of food grains should be checked before their storage?
Answer:
Before storage, moisture level of food grains should not be more than 9% otherwise growth of micro – organisms (bacteria and fungi) will take place causing either discolouration or complete spoilage of food grains.

Improvement in Food Resources Value Based Questions

Question 1.
A group of Eco Club students made a compost pit in the school. They collected all bio – degradable waste from the school canteen and used it to prepare the compost

  1. Name two waste that can be used for the compost and two wastes obtained from canteen which cannot be used for the compost making.
  2. What is the other important compound required for making the compost?
  3. State the values of Eco Club students.

Answer:

  1. Two waste used for compost are vegetable peels, fruit peels and pulps. Two waste materials that cannot be used as compost are pickels and curd.
  2. Bacteria present in soil are used as component for making compost.
  3. Eco club students reflect the value of group workers and responsible citizens.

MP Board Solutions

Question 2.
In a poultry farm, large number of birds died. Farm owner was unable to identify the reason and thought someone has done it intentionally. Aryan living nearby his farm noticed that the conditions in the farm were very unhygienic and poor ventilation was there.

  1. What do you think can be the reason for these deaths?
  2. What measures can be followed to prevent this in future?
  3. What values are shown by Aryan?

Answer:

  1. The conditions of the farm were unhygienic and ventilation was also poor. These may be the possible reasons.
  2. These conditions should be improved. Proper food, hygiene practices and good ventilation should be there to prevent this.
  3. The values of awareness and carefullness are shown by Aryan.

MP Board Class 9th Science Solutions

MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.1

MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.1

Question 1.
Which of the following figures lie on the same base and between the same parallels. In such a case, write the common base and the two parallels.
MP Board Class 9th Maths Solutions Chapter 9 Areas of Parallelograms and Triangles Ex 9.1 img-1
Solution:
(i) Base DC, Parallels DC and AB
(iii) Base QR, Parallels QR and PS
(v) Base AD, Parallels AD and BQ.

MP Board Class 9th Maths Solutions

MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2

MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2

Question 1.
ABCD is quadrilateral in which P, Q, R and S are mid-point^jf the sides AB, BC, CD and DA (see Fig.). AC is a diagonal. Show that:

  1. SR ∥ AC and SR = \(\frac{1}{2}\) AC
  2. PQ = SR
  3. PQRS is a parallelogram.

MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2 img-1
Solution:
Given
ABCD is in which P, Q, R and S are the mid-points of sides AB,BC, CD and DA.
To prove.

  1. SR ∥ AC and SR= \(\frac{1}{2}\) AC
  2. PQ = SR
  3. PQRS is a parallelogram.

MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2 img-2
Proof:
In ∆ABC. P is the mid point of AB and Q is the midpoint of BC.
∴ PQ ∥ AC and PQ = \(\frac{1}{2}\) AC (by MPT)…(1)
In ∆ADC, S is the mid-point of AD and R is the mid – point of DC.
SR ∥ AC and SR = \(\frac{1}{2}\) AC (by MPT)…(2)

1. SR ∥ AC and SR = \(\frac{1}{2}\) AC (proved)
2. PQ ∥ AC and SR = \(\frac{1}{2}\) AC
∴ PQ = SR
3. From (1) and (2), we get
PQ ∥ SR and PQ = SR
∴ PQRS is a parallelogram

MP Board Solutions

Question 2.
ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral P&RS is a rectangle.
Solution:
Given
ABCD is rhombus and P, Q and R and S are the mid-points of sides AB, BC, CD and DA.
To prove
PQRS is a rectangle.
Construction:
Join AC and BD).
MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2 img-3
Proof:
In ∆ABC, P is the midpoint of AB and Q is the midpoint of BC.
∴ PQ ∥AC (By MPT) …(1)
In ∆ADC, S is the midpoint of AD and R is the midpoint of DC.
SR ∥ AC (By MPT) …(2)
From (1) and (2), we get
PQ ∥ SR …(3)
In ∆ABD, P is the midpoint of AB and S is the midpoint of AD.
PS ∥ BD …(4)
In ABCD, Q is the midpoint of BC and R is the midpoint of CD
∴ QR ∥ BD (ByMPT) …(5)
From (4) and (5), we get
PS ∥ QR …(6)
In quadrilateral PQRS, PQ ∥ SR and PS ∥ QR
∴ PQRS is a parallelogram.
In quadrilateral OESF
SF ∥ EO (∴ SR ∥ AO …(7)
SE ∥ FO (∴ SP ∥ BD) …(8)
SEOF is a parallelogram.
We know that, that in a parallelogram opposite angles are equal.
∴ ∠ESF = ∠EOF= 90°
(∴ In a rhombus, diagonals intersect each other at right angles)
Hence, PQRS is a rectangle.

Question 3.
ABCD is a rectangle and P,Q,R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus.
Given
ABCD is a rectangle P,Q,R and S are the mid-points of AB, BC, CD and DA.
To prove.
PQRS is a rhombus.
Proof:
In ∆ABC, P is the midpoint of AB and Q is the midpoint of BC.
MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2 img-4
PQ ∥ AC and PQ = \(\frac{1}{2}\) AC (By MPT) ….(1)
In ∆ADC, S is the midpoint of AD and R is the midpoint of DC.
∴ SR ∥ AC and SR = \(\frac{1}{2}\) AC (By MPT)…(2)
From (1) and (2),we get
PQ ∥ SB and PQ = SR
PQRS is a parallelogram
AD = BC (∴ ABCD is a rectangle)
⇒ \(\frac{1}{2}\) AD = \(\frac{1}{2}\) BC
AS = BQ
In ∆PAS and ∆PBQ, AS = BQ (proved)
AP = BP P is the mid-point of AB
∠A = ∠B (each 90°)
and so PS = PQ (ByCPCT)
In a ∥gm, if adjacent sides are equal, then it a rhombus.
∴ PQRS is a rhombus.

Question 4.
ABCD is a trapezium in which AB ∥ DC, BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB intersecting BC and F (see Fig. below). Show that F is the mid-point of BC.
MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2 img-5
Solution:
Given
AB ∥ DC, DE = AE and EF ∥ AS.
To prove
F is the mid-point of BC
Proof:
AB ∥ DC (given) …(1)
AB ∥ EF (given) …(2)
MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2 img-6
From (1) and (2) we get,
DC ∥ EF
In ∆ABD, E is the mid – point of AD
EP ∥ AB (∴ EF∥AB)
∴ P is the mid – point of BD (By CMPT)
In ∆BCD, P is the midpoint of BD.
PF ∥ DC (∴ EF ∥ DC)
F is the midpoint of BC (By CMPT).

MP Board Solutions

Question 5.
In a parallelogram ABCD, E and F are the mid-point of sides AB and CD respectively (See Fig.). Show that the line segments AD and EC trisect the diagonal BD.
MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2 img-7
Solution:
Given
ABCD is a ∥gm, E and F are the mid-point of AB and CD.
To prove:
BQ = PQ = DP
Proof:
AB ∥ DC and AB = DC (∴ ABCD is a ∥gm)
⇒ \(\frac{1}{2}\) ∥ AB \(\frac{1}{2}\) DC and \(\frac{1}{2}\) AB = \(\frac{1}{2}\)DC
⇒ AE ∥ FC and AE = FC (∴ \(\frac{1}{2}\) AB = AE and \(\frac{1}{2}\) DC = FC)
AECF is a parallelogram (∴ AECF is a ∥gm)
In ∆ABP, E is the mid – point of AB,
EQ ∥AP (∴ AECF is a ∥<sup<gm)
MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2 img-8
∴ Q is the midpoint of BP (∴ by CMPT) …(1)
BQ = PQ
In ∆DQC, F is the midpoint of DC
EF ∥ CQ AECF is a ∥<sup<gm)
P is the midpoint of DQ
i.e., DP = PQ
From (1) and (2), we get BQ = PQ = DP.

Question 6.
Show that the line segments joining the mid-points of the opposite sides of a quadrilateral bisect each other.
Solution:
Given
ABCD is a in which P, Q.R and S are the mid-points of AB, BC, CD and DA respectively.
To prove
PR and SQ bisect each other.
Construction:
Join AC. Join PQ, QR, RS and SP.
MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2 img-9
Proof:
In ∆ABC, P is the midpoint of AB and Q is the midpointof BC.
PQ ∥ AC and PQ = \(\frac{1}{2}\) AC (By MPT) …..(1)
In ∆ADC, S is the midpoint of AD and R is the midpoint of DC.
SR ∥ AC and SR = \(\frac{1}{2}\) AC (by MPT) …(2)
Form (1) and (2), we get
PQ ∥ SR and PQ = SR
∴ PQRS is a parallelogram in which PR and SQ are diagonals^ and so PR and SQ bisect each other (In a ∥gm, diagnaols bisect each other)

MP Board Solutions

Question 7.
ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that

  1. D is the mid – point of AC
  2. MD ⊥ AC
  3. CM = MA = \(\frac{1}{2}\) AB.

MP Board Class 9th Maths Solutions Chapter 8 Quadrilaterals Ex 8.2 img-10
Solution:
Given
ABC is a right ∆. ∠C = 90°
AM = BM and MD ∥ BC.
To prove:

  1. D is the mid-point of AC, i.e., AD – CD
  2. MD ⊥ AC
  3. CM = MA = \(\frac{1}{2}\) AB

Proof:
1. In ∆ACB, M is the mid-point of AB and MD ∥ BC
∴ D is the mid – point of AC (By CMPT)
i.e., AD = CD

2. MD ∥ BC and AC is the transversal
∴ ∠ADM = ∠ACB (CA’s)
⇒ ∠ADM = 90° (∠ACB = 90°)
∴ MD ⊥ AC

3. In ∆ADM and ∆CDM,
AD = CD (proved)
∠ADM = ∠CDM (each 90°)
[∴ ∠ADM + ∠CDM = 180° (LPA’s); 90° + ∠CDM= 180°; ∠CDM = 90°]
MD = MD (common)
∴ ∆ADM = ∆CDM (By SAS)
and so MA = MC (By cpct) …(1)
MA = \(\frac{1}{2}\) AB (Given) …(2)
Form (1) and (2), we get MA = MC = \(\frac{1}{2}\) AB.

MP Board Class 9th Maths Solutions