Category: Class 7

MP Board Class 7th Maths Solutions Chapter 3 Data Handling Ex 3.4

Question 1.
Tell whether the following is certain to happen, impossible, can happen but not certain.
(i) You are older today than yesterday.
(ii) A tossed coin will land heads up.
(iii) A die when tossed shall land up with 8 on top.
(iv) The next traffic light seen will be green.
(v) Tomorrow will be a cloudy day.
Solution:
(i) Certain to happen
(ii) Can happen but not certain
(iii) Impossible as there are only six faces of a die marked as 1, 2, 3, 4, 5 and 6 on it.
(iv) Can happen but not certain
(v) Can happen but not certain

Question 2.
There are 6 marbles in a box with numbers from 1 to 6 marked on each of them.
(i) What is the probability of drawing a marble with number 21
(ii) What is the probability of drawing a marble with number 5?
Solution:
Probability of an event

(ii) Probability of drawing a marble with number 5 = \(\frac{1}{6}\).

Question 3.
A coin is flipped to decide which team starts the game. What is the probability that your team will start?
Solution:
A coin has two faces – Head and Tail. One team can opt either Head or Tail. Probability of an event

Probability (our team will start first) = \(\frac{1}{2}\)

MP Board Class 7th Maths Solutions

MP Board Class 7th Maths Solutions Chapter 3 Data Handling Ex 3.3

Question 1.
Use the given bar graph to answer the following questions.
(a) Which is the most popular pet?
(b) How many students have dog as a pet?

Solution:
(a) Since, the bar representing number of students for cats is the tallest, so cat is the most popular pet.
(b) The number of students having dog as a pet is 8.

Question 2.
Read the given bar graph which shows the number of books sold by a bookstore during five consecutive years and answer the following questions:

(i) About how many books were sold in 1989? 1990? 1992?
(ii) In which year were about 475 books sold? About 225 books sold?
(iii) In which years were fewer than 250 books sold?
(iv) Can you explain how you would estimate the number of books sold in 1989?
Solution:
(i) In 1989, 175 books were sold. In 1990, 475 books were sold. In 1992, 225 books were sold.
(ii) From the graph, it can be concluded that in the year 1990 about 475 books were sold and in the year 1992 about 225 books were sold.
(iii) From the graph, it can be concluded that in the year 1989 and 1992, the number of books sold were less than 250.
(iv) From the graph, it can be concluded that the number of books sold in the year 1989 is about 1 and \(\frac{3}{4}\) th part of 1 cm.
We know that the scale is taken as 1 cm = 100 books.
∴ Number of books sold in 1989

Therefore, about 175 books were sold in the year 1989.

Question 3.
Number of children in six different classes are given below. Represent the data on a bar graph.

(a) How would you choose a scale?
(b) Answer the following questions:
(i) Which class has the maximum number of children? And the minimum?
(ii) Find the ratio of students of class sixth to the students of class eighth.
Solution:

(a) We will choose a scale as 1 unit = 10 children because we can represent a more
clear difference between the number of students of class 7^th and that of class 9^th by this scale.
(b) (i) Since, the bar representing the number of children for class fifth is the tallest. So, there are maximum number of children in class fifth. Similarly, the bar representing the number of children for class tenth is the smallest. So, there are minimum number of children in class tenth.
(ii) The number of students in class sixth is 120 and the number of students in class eighth is 100. Therefore, the ratio of students of class sixth to the students 5.
of class eighth \(=\frac{120}{100}=\frac{6}{5}\) i.e., 6 : 5

Question 4.
The performance of a student in 1^st Term and 2^nd Term is given. Draw a double bar graph choosing appropriate scale and answer the following:

(i) In which subject, has the child improved his performance the most?
(ii) In which subject is the improvement the least?
(iii) Has the performance gone down in any subject?
Solution:
A double bar graph for the given data is as follows.

(i) There was a maximum increase in the marks obtained in Maths. Therefore, the child has improved his performance the most in Maths.
(ii) From the graph, it can be concluded that the improvement was the least in
S. Science.
(iii) From the graph, it can be observed that the performance in Hindi has gone down.

Question 5.
Consider this data collected from a survey of a colony.

(i) Draw a double bar graph choosing an appropriate scale. What do you infer from the bar graph?
(ii) Which sport is most popular?
(iii) Which is more preferred, watching or participating in sports?
Solution:
(i) A double bar graph for the given data is as follows:

The double bar graph represents the number of people who like watching and participating in different sports.
(ii) From the bar graph, it can be observed that the bar representing the number of people who like watching and participating in cricket is the tallest among all the bars. Hence, cricket is the most popular sport.
(iii) The bars representing watching sport are longer than the bars representing participating in sport. Hence, watching different types of sports is more preferred than participating in the sports.

Question 6.
Take the data giving the minimum and the maximum temperature of various cities given in the table. Plot a double bar graph using the data and answer the following:

(i) Which city has the largest difference in the minimum and maximum temperature on the given date?
(ii) Which is the hottest city and which is the coldest city?
(iii) Name two cities where maximum temperature of one was less than the minimum temperature of the other.
(iv) Name the city which has the least difference between its minimum and the maximum temperature.
Solution:
A double bar graph for the given data is constructed as follows.

(i) From the graph, it can be concluded that Jammu has the largest difference in its minimum and maximum temperature on 20.6.2006.
(ii) From the graph, it can be concluded that Jammu is the hottest city and Bangalore is the coldest city.
(iii) Bangalore and Jaipur, Bangalore and Ahmedabad.
For Bangalore, the maximum temperature was 28°C, while minimum temperature of both cities, Ahmedabad and Jaipur, was 29°C.
(iv) From the graph, it can be concluded that the city which has least difference between its minimum and maximum temperature is Mumbai.

MP Board Class 7th Maths Solutions

MP Board Class 7th Maths Solutions Chapter 3 Data Handling Ex 3.2

Question 1.
The scores in Mathematics test (out of 25) of 15 students are as follows:
19, 25, 23, 20, 9, 20, 15, 10, 5, 16, 25, 20, 24, 12, 20
Find the mode and median of this data. Are they same?
Solution:
Arranging the given scores in ascending order, we have 5, 9, 10, 12, 15, 16, 19, 20, 20, 20, 20, 23, 24, 25, 25
Mode of given data is that value of observation which occurs for the most number of times i.e., 20. 5.
Median of the given data is the middle observation when the data is arranged in ascending order i.e., 8^th term = 20
Hence, mode of data = median of data.

Question 2.
The runs scored in a cricket match by 11 players are as follows:
6, 15, 120, 50, 100, 80, 10, 15, 8, 10, 15
Find the mean, mode and median of this data. Are the three same?
Solution:
Arranging the given scores in an ascending order, we have

As 15 occurs for the most number of times.
∴ Mode = 15
Median = Middle term = 15
∴ All three mean, mode and median are not same.

Question 3.
The weights (in kg.) of 15 students of a class are: 38, 42, 35, 37, 45, 50, 32, 43, 43, 40, 36, 38, 43, 38, 47
(i) Find the mode and median of this data.
(ii) Is there more than one mode?
Solution:
Arranging the given weights in ascending order, we have 32, 35, 36, 37, 38, 38, 38, 40, 42, 43, 43, 43, 45,47, 50
(i) Mode = 38 and 43
Median = Middle term = 40
(ii) Yes, there are 2 modes for the given data i.e., 38 and 43.

Question 4.
Find the mode and median of the data: 13, 16, 12, 14, 19, 12, 14, 13, 14
Solution:
Arranging the given data in an ascending order, we have
12, 12, 13, 13, 14, 14, 14, 16, 19
14 occurs for the most number of times
∴ Mode = 14
Median = Middle observation = 14

Question 5.
Tell whether the statement is true or false:
(i) The mode is always one of the numbers in a data.
(ii) The mean is one of the numbers in a data.
(iii) The median is always one of the numbers in a data.
(iv) The data 6,4,3,8,9,12,13,9 has mean 9.
Solution:
(i) True, as mode of a given data is that value of observation which occurs for the most number of times. Therefore, it is one of the observations given in the data.
(ii) False, because mean may or may not be one of the numbers in the data.
(iii) False, because median may or may not be one of the numbers in the data
(iv) False, because

MP Board Class 7th Maths Solutions

MP Board Class 7th Maths Solutions Chapter 3 Data Handling Ex 3.1

Question 1.
Find the range of heights of any ten students of your class.
Solution:
Let the heights (in cm) of 10 students of our class be 125, 129, 131, 132, 134, 136, 139, 142, 144, 146
Highest observation = 146 cm
Lowest observation =125 cm
Range = Highest observation – Lowest observation
= (146 – 125) cm = 21 cm

Question 2.
Organise the following marks in a class assessment, in a tabular form. 4, 6, 7, 5, 3, 5, 4, 5, 2, 6, 2, 5, 1, 9, 6, 5, 8, 4, 6, 7
Solution:

(i) Highest number = 9
(ii) Lowest number = 1
(iii) Range = (9 – 1) = 8
(iv) Sum of all the observations =4 + 6 + 7 + 5 + 3 + 5 + 4 + 5 + 2 + 6 + 2 + 5 + 1 + 9 + 6 + 5 + 8 + 4 + 6 + 7 = 100
Total number of observations = 20
Arithmetic mean

Question 3.
Find the mean of the first five whole numbers.
Solution:
First five whole numbers are 0, 1, 2, 3 and 4.

Hence, the mean of first five whole numbers is 2.

Question 4.
A cricketer scores the following runs in eight innings: 58, 76,40, 35,46,45,0,100.
Find the mean score.
Solution:
Runs scored by the cricketer in eight innings are 58, 76, 40, 35, 46, 45, 0 and 100.

Therefore, mean score is 50.

Question 5.
Following table shows the points of each player scored in four games:

Now answer the following questions:
(i) Find the mean to determine A’s average number of points scored per game.
(ii) To find the mean number of points per game for C, would you divide the total points by 3 or by 4? Why?
(iii) B played in all the four games. How would you find the mean?
(iv) Who is the best performer?
Solution:
(i) A’s average number of points

(ii) To find the mean number of points per game for C, we will divide the total points by 3 because C played 3 games.

(iii) Mean of B’s Score

(iv) The best performer will have the greatest average among all. Now we can observe that the average of A is 12.5 which is more than that of B and C. Therefore, A is the best performer.

Question 6.
The marks (out of 100) obtained by a group of students in a Science test are 85, 76, 90, 85, 39, 48, 56, 95, 81 and 75. Find the:
(i) Highest and the lowest marks obtained by the students.
(ii) Range of the marks obtained.
(iii) Mean marks obtained by the group.
Solution:
The marks obtained by the group of students in a Science test can be arranged in ascending order as follows.
39, 48, 56, 75, 76, 81, 85, 85, 90, 95
(i) Highest marks = 95 Lowest marks = 39
(ii) Range = 95 – 39 = 56
(iii) Mean marks

Question 7.
The enrolment in a school during six consecutive years was as follows:
1555, 1670, 1750, 2013, 2540, 2820
Find the mean enrolment of the school for this period.
Solution:
Mean enrolment

Question 8.
The rainfall (in mm) in a city on 7 days of a certain week was recorded as follows:

(i) Find the range of the rainfall in the above data.
(ii) Find the mean rainfall for the week.
(iii) On how many days was the rainfall less than the mean rainfall?
Solution:
(i) Range = (20.5 – 0.0) mm = 20.5 mm
(ii) Mean rainfall

(iii) For 5 days (i.e., Monday, Wednesday, Thursday, Saturday, Sunday), the rainfall was less than the mean rainfall.

Question 9.
The heights of 10 girls were measured in cm and the results are as follows:
135, 150, 139, 128, 151, 132, 146, 149, 143, 141.
(i) What is the height of the tallest girl?
(ii) What is the height of the shortest girl?
(iii) What is the range of the data?
(iv) What is the mean height of the girls?
(v) How many girls have heights more than the mean height?
Solution:
Arranging the heights of 10 girls in an ascending order;
128, 132, 135, 139, 141, 143, 146, 149, 150, 151
(i) Height of the tallest girl = 151 cm
(ii) Height of the shortest girl = 128 cm
(iii) Range = (151 – 128) cm = 23 cm
(iv) Mean height

(v) The heights of 5 girls are greater than the mean height (i.e., 141.4 cm) and these heights are 143 cm, 146 cm, 149 cm, 150 cm and 151 cm.

MP Board Class 7th Maths Solutions

MP Board Class 7th Maths Solutions Chapter 2 Fractions and Decimals Ex 2.7

Question 1.
Find:
(i) 0.4 ÷ 2
(ii) 0.35 ÷ 5
(iii) 2.48 ÷ 4
(iv) 65.4 ÷ 6
(v) 651.2 ÷ 4
(vii) 3.96 ÷ 4
(viii) 0.80 ÷ 7
Solution:

Question 2.
Find:
(i) 4.8 ÷ 10
(ii) 52.5 ÷ 10
(iii) 0.7 ÷ 10
(iv) 33.1 ÷ 10
(v) 272.23 ÷ 10
(vi) 0.56 ÷ 10
(vii) 3.97 ÷ 10
Solution:
We know that when a decimal number is divided by a multiple of 10 (i.e., 10,100,1000, etc.), the decimal point will be shifted to the left by as many places as there are zeros.
(i) 4.8 ÷ 10 = 0.48
(ii) 52.5 ÷ 10 = 5.25
(iii) 0.7 ÷ 10 = 0.07
(iv) 33.1 ÷ 10 = 3.31
(v) 272.23 ÷ 10 = 27.223
(vi) 0.56 ÷ 10 = 0.056
(vii) 3.97 ÷10 = 0.397

Question 3.
Find:
(i) 2.7 ÷ 100
(ii) 0.3 ÷ 100
(iii) 0.78 ÷ 100
(iv) 432.6 ÷ 100
(v) 23.6 ÷ 100
(vi) 98.53 ÷ 100
Solution:
We know that when a decimal number is divided by a multiple of 10 (i.e., 10, 100, 1000, etc.), the decimal point will be shifted to the left by as many places as there are zeros.
(i) 2.7 ÷ 100 = 0.027
(ii) 0.3 ÷ 100 = 0.003
(iii) 0.78 ÷ 100 = 0.0078
(iv) 432.6 ÷ 100 = 4.326
(v) 23.6 ÷ 100 = 0.236
(vi) 98.53 ÷ 100 = 0.9853

Question 4.
Find:
(i) 7.9 ÷ 1000
(ii) 26.3 ÷ 1000
(iii) 38.53 ÷ 1000
(v) 0.5 ÷ 1000
Solution:
We know that when a decimal number is divided by a multiple of 10 (i.e., 10, 100, 1000, etc.), the decimal point will be shifted to the left by as many places as there are zeros.
(i) 7.9 ÷ 1000 = 0.0079
(ii) 26.3 ÷ 1000 = 0.0263
(iii) 38.53 ÷ 1000 = 0.03853
(iv) 128.9 ÷ 1000 = 0.1289
(v) 0.5 ÷ 1000 = 0.0005

Question 5.
Find:
(i) 7 ÷ 3.5
(ii) 36 ÷ 2
(iii) 3.25 ÷ 0.5
(iv) 30.94 ÷ 0.7
(v) 0.5 ÷ 0.25
(vi) 7.75 ÷ 0.25
(vii) 76.5 ÷ 0.15
(viii) 37.8 ÷ 1.4
(ix) 2.73 ÷ 1.3
Solution:

Question 6.
A vehicle covers a distance of 43.2 km in 2.4 litres of petrol How much distance wilt it cover in one litre of petrol?
Solution:
Distance covered in 2.4 Litres of petrol = 43.2 km
∴ Distance covered in 1 litre of petrol = (43.2 ÷ 2.4) km

MP Board Class 7th Maths Solutions

MP Board Class 7th Social Science Solutions Miscellaneous Questions 1

Choose the correct alternative from the following:

Question 1.
The medieval period in India begins form:
(a) The 13th century
(b) 7th century
(c) 8th century
(d) 12th century
Answer:
(c) 8th century

Question 2.
The famous Raja Rajeshwara temple of Tanjavur was built by:
(a) Raja raja – I
(b) Rajendra -I
(c) Krishna – I
(d) Krishna – II
Answer:
(a) Raja raja – I

Question 3.
The President of the constituent assembly was:
(a) Dr. Harising Gaur
(b) Dr. Bhimrao Ambedekar
(c) Dr. Rajendra Prasad
(d) Pt. Jawaharlal Nehru.
Answer:
(c) Dr. Rajendra Prasad

Question 4.
The total no. of the members of the Rajya Sabha is:
(a) 238
(b) 250
(c) 230
(d) 260
Answer:
(c) 230

Question 5.
Day and night are equal on:
(a) 21 March and 25th Dec
(b) 21 June and 22 Dec
(c) 25 Dec & 25 June
(d) none of the above
Answer:
(d) none of the above

Question 7.
The percentage of oxygen percent in the atmosphere is:
(a) 78%
(b) 21%
(c) 28%
(d) 71%
Answer:
(b) 21%

Fill in the blanks:

1. India was in continuous contact with …………… through trade.
2. ……………. translated Ramayana into Tamil
3. The ancient name of the capital of Madhya Pradesh was …………….
4. The Constitution of India is a written and ……………. Constitution.
5. The earth’s axis makes an angle of ……………… from its plane.

Answer:

1. Arabs
2. Kamban
3. Bhojpal
4. Comprehensive
5. 23 \(\frac { 1 }{2 }\)°

Make correct pairs:

Answer:
1. (b) Uttar Ram charit
2. (a) Geetgovind
3. (d) Siddhata shiromani
4. (c) Life saving gas

Answer the following in brief:

Question 1.
Write the names of the important rulers of the Chouhan dynasty.
Answer:
Ajayraj Chouhan and Prithiviraj Chouhan.

Question 2.
Write any three features of the Chola administration.
Answer:

• The king was the head of the government
• The empire was divided into provinces.
• The village was the lowest unit of administration.

Question 3.
What do you understand by Secularism?
Answer:
Secularism means that from point of view of the government all religious are equal and the state shall not discriminate between the people of different facilities.

Question 4.
Write any three qualifications required to be a member of the RajyaSabha.
Answer:
A person must be 30 years or above in age.

• His name must be in the voter is list of the constituency to which he belongs.
• He must not be insolvent, bankrupt and must be same.

Question 5.
What do you know about die Ionosphere?
Answer:
It is one of the layers of gases found in thermosphere. It is found at a height of 80 to 400 km from the earth.

Question 6.
What do you mean by the axis of the earth?
Answer:
The axis of the earth is the point on which die earth rotates.

Question 7.
What is meant by change of season?
Answer:
Because of the title of the earth’s axis one hemisphere comes to face to the sun first and then comes the other hemisphere. Therefore variations in the weather phenomenon occur. Change in temperature is die bases for change in seasons. The earth gets heat from sun. Due to its tilt of 23\(\frac { 1 }{2 }\)° degrees on its axis and its revolution round the sun the quantity of temperature received differs. This brings about changes in seasons.

Question 8.
Which season does India experience when die sun is directly on the tropic of Cancer?
Answer:
Summer season.

Answer the following questions in detail:

Question 1.
Describe die political condition of India in the beginning of the early part of the medieval period.
Answer:
The Arabs made great contribution in the development of the Medieval civilization. They were expert traders. Trade had made them rich and they used the wealth for the development of art, science and literature.

They spread knowledge, which they acquired from the countries with which they had trade relations, to distant lands. They also made important contribution in the field of Geometry, Algebra, Geography and Astronomy. They also carried new inventions of China like Gun Powder, Paper and Compass to countries of Europe.

Question 2.
Write about the main features of the Pallava dynasty.
Answer:
Main features of the Pallava dynasty:

1. Pollar administration was well – managed.
2. Education, literature and art flourished greatly.
3. The local language was Tamil in which high quality literature was produced.
4. The Pollar kings were Shaivas and the Hindu religion flourished there well.
5. The Pollar as got many famous temples built there. Some of the very famous are ‘Dharmraj’ and Kailashnath temple at Kanchi, the rock – cut Rathmandir at the sea coast of Mahabalipuram.

Question 3.
Describe the freedoms given in the Rights to freedom.
Answer:
Right to freedom guarantees six basic freedoms. Two freedoms are given here:

1. Freedom to express thoughts – All die citizens of India has the freedom to express his / her thoughts, to give speech and to know about the thought of others and to propagate it The citizens have the freedom to write articles etc. in newspapers.

2. Freedom to live and settle in any part of India – All the citizens of India have die freedom to settle in any part of the country permanently or temporarily as per their wish.

Question 4.
Explain the process of framing a law.
Answer:
Every bill has to go through three stages in the Parliament. These stages are:

• The first reading of the bill – In it, copies of the bill are given to the members. The person or minister who introduces the bill in the House, gives a speech explaining die purpose of die bill.
• The second reading – In the second reading, a clause / by – clause discussion takes place on the bill.
• The third reading – in the third reading the bill as a whole is finally discussed and put to vote.

If the majority of the members are in its favor, the bill is passed. Now the bill is sent to the other House. After the bill is sent to the other House, it goes through all the three stages as mentioned above. After toe other House passes toe bill, it is sent to toe President for his assent The bill becomes a law after it is signed by toe President

Question 5.
Describe die composition of die atmosphere
Answer:
The changes in temperature at various attitudes divide the atmosphere into 5 layers.
1. Troposphere
2. Stratosphere
3. Mesosphere
4. Thermosphere
5. Exosphere

1. Troposphere:
It extends to a height of 8 km at the poles and 18 km on equator. Dust particles and water vapor are found in this layer. All kinds of weather phenomenon like clouds, rainstorm etc. is observed in this layer. All types of life forms are found in this layer. This layer is also known as dynamic layer.

2. Stratosphere:
The second layer of the atmosphere is known as stratosphere. The temperature in this layer is constant till 20 kms. height and then slowly increases.

3. Mesosphere:
The height of this layer is 50 to 80 km from the sea level. The variation in temperature is less in this layer as water vapor, clouds and dust are found less and fast wind blows here.

4. Thermosphere:
The thermosphere starts from the height of 80 km from sea level. The density of air is very less in this layer. The
temperature increases with height in this layer. Two layers of gases are found here. One is the ozone layer and the other is the ion layer.

The ozone layer is spread at a height of 32 to 80 km from the earth. The ion layer is found at a height of 80 to 400 km. from earth. The electrically charged particles stop the radio waves transmitted from the earth and return it back to the earth. In this way we can listen to various radio programmers.

5. Exosphere:
This is the outermost layer of die atmosphere the upper limit of this layer is uncertain. The density of air is the least here.

Question 6.
Describe the different types of permanent winds.
Answer:
Winds are the natural horizontal movement of air over the earth’s surface.

Difference between air and wind:

• When air moves vertically downwards or upwards, it is known as air. But when it moves horizontally, it is known as wind.
•  Airis calm-but when it becomes dynamic it take / the form of wind. Wind always blows from high pressure to low pressure.

Question 7.
Explain with the help of a diagram the changing seasons of the earth.
Answer:
The earth’s axis forms an angle of 66 \(\frac { 1 }{2 }\) with the plane of the earths orbit and the earth tilts at 23 1/2 degree on its axis. Let us understand how seasons occurs on earth.

MP Board Class 7th Social Science Solutions

MP Board Class 7th Maths Solutions Chapter 2 Fractions and Decimals Ex 2.6

Question 1.
Find:
(i) 0.2 × 6
(ii) 8 × 4.6
(iii) 2.71 × 5
(iv) 20.1 × 4
(v) 0.05 × 7
(vi) 211.02 × 4
(vii) 2 × 0.86
Solution:

Question 2.
Find the area of rectangle whose length is 5.7 cm and breadth is 3 cm.
Solution:
Length = 5.7 cm and breadth = 3 cm
Area = Length × Breadth = (5.7 × 3) cm² = 17.1 cm²

Question 3.
Find:
(i) 1.3 × 10
(ii) 36.8 × 10
(iii) 153.7 × 10
(iv) 168.07 × 10
(v) 31.1 × 100
(vi) 156.1 × 100
(vii) 3.62 × 100
(viii) 43.07 × 100
(ix) 0.5 × 10
(x) 0.08 × 10
(xi) 0.9 × 100
(xii) 0.03 × 1000
Solution:
We know that when a decimal number is multiplied by 10, 100, 1000, the decimal point in the product is shifted to the right by as many places as there are zeros.
(i) 1.3 × 10 = 13
(ii) 36.8 × 10 = 368
(iii) 153.7 × 10 = 1537
(iv) 168.07 × 10 = 1680.7
(v) 31.1 × 100 = 3110
(vi) 156.1 × 100 = 15610
(vii) 3.62 × 100 = 362
(viii) 43.07 × 100 = 4307
(ix) 0.5 × 10 = 5
(x) 0.08 × 10 = 0.8
(xi) 0.9 × 100 = 90
(xii) 0.03 × 1000 = 30

Question 4.
A two-wheeler covers a distance of 55.3 km in one litre of petrol. How much distance will it cover in 10 litres of petrol?
Solution:
Distance covered in 1 litre of petrol = 55.3 km
Distance covered in 10 litres of petrol = (10 × 55.3) km = 553 km

Question 5.
Find:
(i) 2.5 × 0.3
(ii) 0.1 × 51.7
(iii) 0.2 × 316.8
(iv) 1.3 × 3.1
(v) 0.5 × 0.05
(vii) 1.07 × 0.02
(viii) 10.05 × 1.05
(ix) 101.01 × 0.01
(x) 100.01 × 1.1
Solution:

MP Board Class 7th Maths Solutions

MP Board Class 7th Maths Solutions Chapter 2 Fractions and Decimals Ex 2.5

Question 1.
Which is greater?
(i) 0.5 or 0.05
(ii) 0.7 or 0.5
(iii) 7 or 0.7
(iv) 1.37 or 1.49
(v) 2.03 or 2.30
(vi) 0.8 or 0.88.
Solution:
(i) 0.5 or 0.05
Converting these decimal numbers into like fractions, we obtain

(ii) 0.7 or 0.5
Converting these decimal numbers into like fractions, we obtain

(iii) 7 or 0.7
Converting these decimal numbers into like fractions, we obtain

(iv) 1.37 or 1.49
Converting these decimal numbers into like fractions, we obtain

(v) 2.03 or 2.30
Converting these decimal numbers into like fractions, we obtain

(vi) 0.8 or 0.88
Converting these decimal numbers into like fractions, we obtain

Question 2.
Express as rupees using decimals:
(i) 7 paise
(ii) 7 rupees 7 paise
(iii) 77 rupees 77 paise
(iv) 50 paise
(v) 235 paise.
Solution:
There are 100 paise in 1 rupee. Therefore, if we want to convert paise into rupees, we have to divide paise by 100.

Question 3.
(i) Express 5 cm in metre and kilometre.
(ii) Express 35 mm in cm, m and km.
Solution:

Question 4.
Express in kg:
(i) 200 g
(ii) 3470 g
(iii) 4 kg 8g
Solution:

Question 5.
Write the following decimal numbers in the expanded form:
(i) 20.03
(ii) 2.03
(iii) 200.03
(iv) 2.034
Solution:

Question 6.
Write the place value of 2 in the following decimal numbers:
(i) 2.56
(ii) 21.37
(iii) 10.25
(iv) 9.42
(v) 63.352.
Solution:

∴ Place value of 2 in 2.56 is ones.

∴ Place value of 2 in 21.37 is tens.

∴ Place value of 2 in 10.25 is tenths.

∴ Place value of 2 in 9.42 is hundredths.

∴ Place value of 2 in 63.352 is thousandths.

Question 7.
Dinesh went from place A to place Band from there to place C. A is 7.5 km from B and B is
12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?

Solution:
Distance travelled by Dinesh = AB + BC = (7.5 + 12.7) km = 20.2 km
Distance travelled by Ayub = AD + DC
= (9.3+ 11.8) km = 21.1 km
Difference = (21.1 – 20.2) km = 0.9 km
Hence, Ayub travelled 0.9 km more distance than Dinesh.

Question 8.
Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?
Solution:
Total fruits bought by Shyama = 5 kg 300 g + 3 kg 250 g = 8 kg 550 g

Hence, Sarala bought more fruits.

Question 9.
How much less is 28 km than 42.6 km?
Solution:
(42.6 – 28.0) km = 14.6 km
Hence, 28 km is less than 42.6 km by 14.6 km.

MP Board Class 7th Maths Solutions

MP Board Class 7th Maths Solutions Chapter 2 Fractions and Decimals Ex 2.4

Question 1.
Find:

Solution:

Question 2.
Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers.

Solution:
(i) Reciprocal of \(\frac{3}{7}=\frac{7}{3}\). It is an improper fraction.
(ii) Reciprocal of \(\frac{5}{8}=\frac{8}{5}\). It is an improper fraction.
(iii) Reciprocal of \(\frac{9}{7}=\frac{7}{9}\). It is a proper fraction.
(iv) Reciprocal of \(\frac{6}{5}=\frac{5}{6}\). It is a proper fraction.
(v) Reciprocal of \(\frac{12}{7}=\frac{7}{12}\). It is a proper fraction.
(vi) Reciprocal of \(\frac{1}{8}\) = 8. It is a whole fraction.
(vii) Reciprocal of \(\frac{1}{11}\) = 11. It is a whole fraction.

Question 3.

Question 4.
Find:

Solution:
(i) \(\frac{2}{5}÷\frac{1}{2}=\frac{2}{5} \times 2=\frac{4}{5}\)

MP Board Class 7th Maths Solutions

MP Board Class 7th Maths Solutions Chapter 2 Fractions and Decimals Ex 2.3

Question 1.

Solution:

Question 2.
Multiply and reduce to lowest form (if possible):

Solution:

Question 3.
Multiply the following fractions:

Solution:

Question 4.

Solution:
Converting these fractions into like fractions, we obtain

Question 5.
Saili plants 4 saplings, in a row, in her garden. The distance between two adjacent saplings is \(\frac{3}{4}\) m. Find the distance between the first and the last sapling.
Solution:

From the figure, it can be observed that gap between first and last sapling = 3 × Length of gap 1
Therefore, distance between first and last

Question 6.
Lipika reads a book for \(1 \frac{3}{4}\) hours everyday. She reads the entire book in 6 days. How many hours in all were required by her to read the book?
Solution:
Time taken by Lipika to read the book per day = \(1 \frac{3}{4}\) hours = \(\frac{7}{4}\) hours
Number of days = 6
Total time taken by her to read the entire book = \(\frac{7}{4}\) × 6 hours = \(\frac{21}{2}\) hours
= \(=10 \frac{1}{2}\)hours

Question 7.
A car runs 16 km using 1 litre of petrol. How much distance will it cover using \(2 \frac{3}{4}\) litres of petrol?
Solution:
A car can run per litre of petrol = 16 km
Quantity of petrol = \(2 \frac{3}{4}\) litres = \(\frac{11}{4}\) litres
So, a car can run for \(\frac{11}{4}\) litres of petrol

Question 8.

Solution:

MP Board Class 7th Maths Solutions