MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3

Question 1.
Solve the following equations:
(a) \(2 y+\frac{5}{2}=\frac{37}{2}\)
(b) 5t + 28 = 10
(c) \(\frac{a}{5}+3\) = 2
(d) \(\frac{q}{4}+7\) = 5
(e) \(\frac{5}{2} x\) = -10
(f) \(\frac{5}{2} x=\frac{25}{4}\)
(g) \(7 m+\frac{19}{2}\) = 13
(h) 6z + 10 = -2
(i) \(\frac{3 l}{2}=\frac{2}{3}\)
(j) \(\frac{2 b}{3}-5\) = 3
Solution:
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 2
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 3
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 4
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 5

Question 2.
Solve the following equations.
(a) 2(x + 4) = 12
(b) 3(n – 5) = 21
(c) 3(n – 5) = -21
(d) -4(2 + x) = 8
(e) 4(2 – x) = 8
Solution:
(a) 2(x + 4) = 12
Dividing both sides by 2,
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 6
(Transposing 4 to R.H.S.)

(b) 3(n – 5) = 21
Dividing both sides by 3,
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 7
(Transposing – 5 to R.H.S.)

(c) 3(n – 5) = -21
Dividing both sides by 3,
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 8
(Transposing – 5 to R.H.S.)

(d) – 4(2 + x) = 8
Dividing both sides by – 4,
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 9
(Transposing 2 to R.H.S.)

(e) 4(2 – x) = 8
Dividing both sides by 4,
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 10
(Transposing 2 to R.H.S.)
⇒ x = 0

MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3

Question 3.
Solve the following equations:
(a) 4 = 5(p – 2)
(b) -4 = 5(p – 2)
(c) 16 = 4 + 3(t + 2)
(d) 4 + 5(p – 1) = 34
(e) 0 = 16 + 4(m – 6)
Solution:
(a) 4 = 5(p – 2)
Dividing both sides by 5,
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 11
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 12
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 13

MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3

Question 4.
(a) Construct 3 equations starting with x= 2.
(b) Construct 3 equations starting with x = -2.
Solution:
(a) x = 2
Multiplying both sides by 5,
5x = 10 … (i)
(b) Let the number be x.
Subtracting 3 from both sides,
5x – 3 = 10 – 3
5x – 3 = 7 …(ii)
Dividing both sides by 2,
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3 14

(b) x= -2
Subtracting 2 from both sides,
x – 2 = -2 – 2 ⇒ x – 2 = -4 … (i)
Again, take x = – 2
Multiplying both sides by 6,
6 × x = -2 × 6 ⇒ 6x = -12
Subtracting 12 from both sides,
6x – 12 = – 12 – 12 ⇒ 6x – 12 = – 24 …(ii)
Adding 24 to both sides,
6x – 12 + 24 = – 24 + 24
⇒ 6x + 12 = 0 …(iii)

MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3

MP Board Class 7th Maths Solutions

Leave a Reply