MP Board Class 7th Maths Solutions Chapter 10 Practical Geometry Ex 10.5

Question 1.
Construct the right angled ∆PQR, where m ∠Q = 90°, QR = 8 cm and PR 10 cm.
Solution:
Steps of Construction :
MP Board Class 7th Maths Solutions Chapter 10 Practical Geometry Ex 10.3 1
1. Draw a line segment QR = 8 cm.
2. Draw ∠RQX = 90°.
3. .With centre R and radius 10 cm (= PR = Hypotenuse), draw an arc to intersect ray QX at P.
4. Join PR.
Then, PQR is the required right angled triangle.

MP Board Class 7th Maths Solutions Chapter 10 Practical Geometry Ex 10.5

Question 2.
Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.
Solution:
Steps of Construction :
MP Board Class 7th Maths Solutions Chapter 10 Practical Geometry Ex 10.5 2
1. Draw a line segment QR of length 4 cm.
2. Draw ∠QRX = 90°.
3. With Q as centre and radius 6 cm (= hypotenuse) draw an arc intersecting QX at P.
4. Join PQ.
Then, PQR is the required right-angled triangle.

Question 3.
Construct an isosceles right-angled triangle ABC, where m ∠ACB = 90° and AC = 6 cm.
Solution:
Steps of Construction :
MP Board Class 7th Maths Solutions Chapter 10 Practical Geometry Ex 10.5 3
1. Draw a line segment BC = 6 cm.
2. At C, draw an angle BCX = 90°
3. From ray CX, cut off CA = 6 cm.
4. Join AB.
Then, ABC is the required an isosceles right-angled triangle.

MP Board Class 7th Maths Solutions

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