## MP Board Class 7th Maths Solutions Chapter 10 Practical Geometry Ex 10.5

Question 1.

Construct the right angled ∆PQR, where m ∠Q = 90°, QR = 8 cm and PR 10 cm.

Solution:

Steps of Construction :

1. Draw a line segment QR = 8 cm.

2. Draw ∠RQX = 90°.

3. .With centre R and radius 10 cm (= PR = Hypotenuse), draw an arc to intersect ray QX at P.

4. Join PR.

Then, PQR is the required right angled triangle.

Question 2.

Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Solution:

Steps of Construction :

1. Draw a line segment QR of length 4 cm.

2. Draw ∠QRX = 90°.

3. With Q as centre and radius 6 cm (= hypotenuse) draw an arc intersecting QX at P.

4. Join PQ.

Then, PQR is the required right-angled triangle.

Question 3.

Construct an isosceles right-angled triangle ABC, where m ∠ACB = 90° and AC = 6 cm.

Solution:

Steps of Construction :

1. Draw a line segment BC = 6 cm.

2. At C, draw an angle BCX = 90°

3. From ray CX, cut off CA = 6 cm.

4. Join AB.

Then, ABC is the required an isosceles right-angled triangle.